313200 \(\mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{+}(\mathrm{g})\) by energy \(\mathrm{E}_{1} \cdot \mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{-}(\mathrm{g})\) of energy \(\mathrm{E}_{2}\). Hence, ionization energy and electron affinity of \(\mathrm{X}(\mathrm{g})\) are:

313201 The electron affinity values are negative for
\({\rm{(I)Be}} \to {\rm{B}}{{\rm{e}}^ - }\,\,\,{\rm{(II)N}} \to {{\rm{N}}^ - }\)
\({\rm{(III)O}} \to {{\rm{O}}^{2 - }}\,\,{\rm{(IV)Na}} \to {\rm{N}}{{\rm{a}}^ - }\)
\({\rm{(V)Al}} \to {\rm{A}}{{\rm{l}}^ - }\)
Choose the most appropriate answer from the options given below.

313202 Ionisation of energy of \({{\rm{F}}^{\rm{ - }}}\,\,{\rm{is}}\,\,{\rm{320}}\,{\rm{kJ}}\,{\rm{/}}\,{\rm{mole}}\). The electron gain enthalpy of fluorine would be

313217 Assertion :
\(\mathrm{F}\) is more electronegative than \(\mathrm{Cl}\).
Reason :
\(\mathrm{F}\) has high electron affinity than \(\mathrm{Cl}\).

313238 In the compound \({\rm{M}}\,{\rm{ - }}\,{\rm{O}}\,{\rm{ - }}\,{\rm{H,}}\,\,{\rm{the}}\,\,{\rm{M}}\,{\rm{ - }}\,{\rm{O}}\) bond will be broken if :

313200 \(\mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{+}(\mathrm{g})\) by energy \(\mathrm{E}_{1} \cdot \mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{-}(\mathrm{g})\) of energy \(\mathrm{E}_{2}\). Hence, ionization energy and electron affinity of \(\mathrm{X}(\mathrm{g})\) are:

313201 The electron affinity values are negative for
\({\rm{(I)Be}} \to {\rm{B}}{{\rm{e}}^ - }\,\,\,{\rm{(II)N}} \to {{\rm{N}}^ - }\)
\({\rm{(III)O}} \to {{\rm{O}}^{2 - }}\,\,{\rm{(IV)Na}} \to {\rm{N}}{{\rm{a}}^ - }\)
\({\rm{(V)Al}} \to {\rm{A}}{{\rm{l}}^ - }\)
Choose the most appropriate answer from the options given below.

313202 Ionisation of energy of \({{\rm{F}}^{\rm{ - }}}\,\,{\rm{is}}\,\,{\rm{320}}\,{\rm{kJ}}\,{\rm{/}}\,{\rm{mole}}\). The electron gain enthalpy of fluorine would be

313217 Assertion :
\(\mathrm{F}\) is more electronegative than \(\mathrm{Cl}\).
Reason :
\(\mathrm{F}\) has high electron affinity than \(\mathrm{Cl}\).

313238 In the compound \({\rm{M}}\,{\rm{ - }}\,{\rm{O}}\,{\rm{ - }}\,{\rm{H,}}\,\,{\rm{the}}\,\,{\rm{M}}\,{\rm{ - }}\,{\rm{O}}\) bond will be broken if :

313200 \(\mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{+}(\mathrm{g})\) by energy \(\mathrm{E}_{1} \cdot \mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{-}(\mathrm{g})\) of energy \(\mathrm{E}_{2}\). Hence, ionization energy and electron affinity of \(\mathrm{X}(\mathrm{g})\) are:

313201 The electron affinity values are negative for
\({\rm{(I)Be}} \to {\rm{B}}{{\rm{e}}^ - }\,\,\,{\rm{(II)N}} \to {{\rm{N}}^ - }\)
\({\rm{(III)O}} \to {{\rm{O}}^{2 - }}\,\,{\rm{(IV)Na}} \to {\rm{N}}{{\rm{a}}^ - }\)
\({\rm{(V)Al}} \to {\rm{A}}{{\rm{l}}^ - }\)
Choose the most appropriate answer from the options given below.

313202 Ionisation of energy of \({{\rm{F}}^{\rm{ - }}}\,\,{\rm{is}}\,\,{\rm{320}}\,{\rm{kJ}}\,{\rm{/}}\,{\rm{mole}}\). The electron gain enthalpy of fluorine would be

313217 Assertion :
\(\mathrm{F}\) is more electronegative than \(\mathrm{Cl}\).
Reason :
\(\mathrm{F}\) has high electron affinity than \(\mathrm{Cl}\).

313238 In the compound \({\rm{M}}\,{\rm{ - }}\,{\rm{O}}\,{\rm{ - }}\,{\rm{H,}}\,\,{\rm{the}}\,\,{\rm{M}}\,{\rm{ - }}\,{\rm{O}}\) bond will be broken if :

313200 \(\mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{+}(\mathrm{g})\) by energy \(\mathrm{E}_{1} \cdot \mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{-}(\mathrm{g})\) of energy \(\mathrm{E}_{2}\). Hence, ionization energy and electron affinity of \(\mathrm{X}(\mathrm{g})\) are:

313201 The electron affinity values are negative for
\({\rm{(I)Be}} \to {\rm{B}}{{\rm{e}}^ - }\,\,\,{\rm{(II)N}} \to {{\rm{N}}^ - }\)
\({\rm{(III)O}} \to {{\rm{O}}^{2 - }}\,\,{\rm{(IV)Na}} \to {\rm{N}}{{\rm{a}}^ - }\)
\({\rm{(V)Al}} \to {\rm{A}}{{\rm{l}}^ - }\)
Choose the most appropriate answer from the options given below.

313202 Ionisation of energy of \({{\rm{F}}^{\rm{ - }}}\,\,{\rm{is}}\,\,{\rm{320}}\,{\rm{kJ}}\,{\rm{/}}\,{\rm{mole}}\). The electron gain enthalpy of fluorine would be

313217 Assertion :
\(\mathrm{F}\) is more electronegative than \(\mathrm{Cl}\).
Reason :
\(\mathrm{F}\) has high electron affinity than \(\mathrm{Cl}\).

313238 In the compound \({\rm{M}}\,{\rm{ - }}\,{\rm{O}}\,{\rm{ - }}\,{\rm{H,}}\,\,{\rm{the}}\,\,{\rm{M}}\,{\rm{ - }}\,{\rm{O}}\) bond will be broken if :

313200 \(\mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{+}(\mathrm{g})\) by energy \(\mathrm{E}_{1} \cdot \mathrm{N}_{0} / 2\) atoms of \(\mathrm{X}(\mathrm{g})\) are converted into \(\mathrm{X}^{-}(\mathrm{g})\) of energy \(\mathrm{E}_{2}\). Hence, ionization energy and electron affinity of \(\mathrm{X}(\mathrm{g})\) are:

313201 The electron affinity values are negative for
\({\rm{(I)Be}} \to {\rm{B}}{{\rm{e}}^ - }\,\,\,{\rm{(II)N}} \to {{\rm{N}}^ - }\)
\({\rm{(III)O}} \to {{\rm{O}}^{2 - }}\,\,{\rm{(IV)Na}} \to {\rm{N}}{{\rm{a}}^ - }\)
\({\rm{(V)Al}} \to {\rm{A}}{{\rm{l}}^ - }\)
Choose the most appropriate answer from the options given below.

313202 Ionisation of energy of \({{\rm{F}}^{\rm{ - }}}\,\,{\rm{is}}\,\,{\rm{320}}\,{\rm{kJ}}\,{\rm{/}}\,{\rm{mole}}\). The electron gain enthalpy of fluorine would be

313217 Assertion :
\(\mathrm{F}\) is more electronegative than \(\mathrm{Cl}\).
Reason :
\(\mathrm{F}\) has high electron affinity than \(\mathrm{Cl}\).

313238 In the compound \({\rm{M}}\,{\rm{ - }}\,{\rm{O}}\,{\rm{ - }}\,{\rm{H,}}\,\,{\rm{the}}\,\,{\rm{M}}\,{\rm{ - }}\,{\rm{O}}\) bond will be broken if :