313179
The formation of the oxide ion, \({{\rm{O}}^{{\rm{2 - }}}}{\rm{(g),}}\) from oxygen atom requires first an exothermic and then an endothermic step as shown below:
\({\rm{O(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{\rm{ - }}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = - 141}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
\({{\rm{O}}^{\rm{ - }}}{\rm{(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{{\rm{2 - }}}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = + 780}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
Thus process of formation of \({{\rm{O}}^{{\rm{2 - }}}}\) in gas phase is unfavourable even though \({{\rm{O}}^{{\rm{2 - }}}}\) is isoelectronic with neon. It is due to the fact that.
313179
The formation of the oxide ion, \({{\rm{O}}^{{\rm{2 - }}}}{\rm{(g),}}\) from oxygen atom requires first an exothermic and then an endothermic step as shown below:
\({\rm{O(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{\rm{ - }}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = - 141}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
\({{\rm{O}}^{\rm{ - }}}{\rm{(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{{\rm{2 - }}}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = + 780}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
Thus process of formation of \({{\rm{O}}^{{\rm{2 - }}}}\) in gas phase is unfavourable even though \({{\rm{O}}^{{\rm{2 - }}}}\) is isoelectronic with neon. It is due to the fact that.
313179
The formation of the oxide ion, \({{\rm{O}}^{{\rm{2 - }}}}{\rm{(g),}}\) from oxygen atom requires first an exothermic and then an endothermic step as shown below:
\({\rm{O(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{\rm{ - }}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = - 141}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
\({{\rm{O}}^{\rm{ - }}}{\rm{(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{{\rm{2 - }}}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = + 780}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
Thus process of formation of \({{\rm{O}}^{{\rm{2 - }}}}\) in gas phase is unfavourable even though \({{\rm{O}}^{{\rm{2 - }}}}\) is isoelectronic with neon. It is due to the fact that.
313179
The formation of the oxide ion, \({{\rm{O}}^{{\rm{2 - }}}}{\rm{(g),}}\) from oxygen atom requires first an exothermic and then an endothermic step as shown below:
\({\rm{O(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{\rm{ - }}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = - 141}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
\({{\rm{O}}^{\rm{ - }}}{\rm{(g) + }}{{\rm{e}}^{\rm{ - }}} \to {{\rm{O}}^{{\rm{2 - }}}}{\rm{(g);\Delta }}{{\rm{H}}^{\rm{\Theta }}}{\rm{ = + 780}}\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\)
Thus process of formation of \({{\rm{O}}^{{\rm{2 - }}}}\) in gas phase is unfavourable even though \({{\rm{O}}^{{\rm{2 - }}}}\) is isoelectronic with neon. It is due to the fact that.