307426 The dimension of Planck’s constant are same as

307427 Ionisation energy of gaseous Na atoms is \({\rm{495}}{\rm{.5}}\,{\rm{kJ}}\,{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\). The lowest possible frequency of light that ionises a sodium atom is \({\rm{(h = 6}}{\rm{.626 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js,}}\,\,{{\rm{N}}_{\rm{A}}}{\rm{ = 6}}{\rm{.022 \times 1}}{{\rm{0}}^{{\rm{23}}}}{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}{\rm{)}}\)

307428 Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?

307429 Excited hydrogen atom emits light in the ultraviolet region at \({\rm{2}}{\rm{.47 \times 1}}{{\rm{0}}^{{\rm{15}}}}{\rm{Hz}}{\rm{.}}\) With this frequency, the energy of a single photon is: \({\rm{(h = 6}}{\rm{.63 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js)}}\)

307426 The dimension of Planck’s constant are same as

307427 Ionisation energy of gaseous Na atoms is \({\rm{495}}{\rm{.5}}\,{\rm{kJ}}\,{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\). The lowest possible frequency of light that ionises a sodium atom is \({\rm{(h = 6}}{\rm{.626 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js,}}\,\,{{\rm{N}}_{\rm{A}}}{\rm{ = 6}}{\rm{.022 \times 1}}{{\rm{0}}^{{\rm{23}}}}{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}{\rm{)}}\)

307428 Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?

307429 Excited hydrogen atom emits light in the ultraviolet region at \({\rm{2}}{\rm{.47 \times 1}}{{\rm{0}}^{{\rm{15}}}}{\rm{Hz}}{\rm{.}}\) With this frequency, the energy of a single photon is: \({\rm{(h = 6}}{\rm{.63 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js)}}\)

307426 The dimension of Planck’s constant are same as

307427 Ionisation energy of gaseous Na atoms is \({\rm{495}}{\rm{.5}}\,{\rm{kJ}}\,{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\). The lowest possible frequency of light that ionises a sodium atom is \({\rm{(h = 6}}{\rm{.626 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js,}}\,\,{{\rm{N}}_{\rm{A}}}{\rm{ = 6}}{\rm{.022 \times 1}}{{\rm{0}}^{{\rm{23}}}}{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}{\rm{)}}\)

307428 Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?

307429 Excited hydrogen atom emits light in the ultraviolet region at \({\rm{2}}{\rm{.47 \times 1}}{{\rm{0}}^{{\rm{15}}}}{\rm{Hz}}{\rm{.}}\) With this frequency, the energy of a single photon is: \({\rm{(h = 6}}{\rm{.63 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js)}}\)

307426 The dimension of Planck’s constant are same as

307427 Ionisation energy of gaseous Na atoms is \({\rm{495}}{\rm{.5}}\,{\rm{kJ}}\,{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\). The lowest possible frequency of light that ionises a sodium atom is \({\rm{(h = 6}}{\rm{.626 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js,}}\,\,{{\rm{N}}_{\rm{A}}}{\rm{ = 6}}{\rm{.022 \times 1}}{{\rm{0}}^{{\rm{23}}}}{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}{\rm{)}}\)

307428 Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. What is the ionization energy of sodium per atom?

307429 Excited hydrogen atom emits light in the ultraviolet region at \({\rm{2}}{\rm{.47 \times 1}}{{\rm{0}}^{{\rm{15}}}}{\rm{Hz}}{\rm{.}}\) With this frequency, the energy of a single photon is: \({\rm{(h = 6}}{\rm{.63 \times 1}}{{\rm{0}}^{{\rm{ - 34}}}}{\rm{Js)}}\)