307351 The uncertainty in the position of an electron moving with a velocity of 1×104cms−1 (accurate up 0.011%) will be
Δx=h4πmΔv=6.63×10−344×3.14×9.1×10−31×104×0.011×10−2=0.528cm
307352 A cricket ball weighing 10 g is to be located with 0.1Ao. What is the uncertainty in its velocity?
Δx.mΔv=h4πΔx= location of ball =0.1Ao=0.1×10−10mm= mass of ball =100g=0.1kgΔv= uncertainty in velocityh=6.626×10−34Js0.1×10−10×0.1×Δv=6.626×10−344×3.14Δv=0.527×10−22ms−1
307353 The uncertainties in the position and velocity of a particle are 10−10m and 5.27×10−24ms−1, respectively. The mass of the particle is (h=6.625×10−34kgm2s−1)
Δx.(mΔv)=h4πor m=h4π×1Δx.Δv=6.625×10−34kgm2s−14×3.14(10−10m)(5.27×10−24ms−1)=0.10kg.
307354 Calculate the uncertainty in velocity of an electron if its uncertainty in position of the order of 1Ao
Δv=h4πm.Δx=6.625×10−34kgm2s−14×3.14×9.1×10−31kg×1×10−10m=5.8×105m/s
