307319
Compare the energies of following sets of quantum numbers for multielectron system.
\[\begin{array}{l}
{\rm{(I)n}} = 4,l = 1\\
{\rm{(II)n}} = 4,l = 2\\
{\rm{(III)n}} = 3,l = 1\\
{\rm{(IV)n}} = 3,l = 2\\
{\rm{(V)n}} = 4,l = 0
\end{array}\]
Choose the correct answer from the options given below
307320
The electrons identified by quantum numbers \(\mathrm{n}\) and l , are as follows
\[\begin{array}{l}
{\rm{I}}{\rm{.n}} = 4,l = 1\,\,\,\,\,\,\,\,\,\,\,{\rm{II}}{\rm{.n}} = 4,l = 0\\
{\rm{III}}{\rm{.n}} = 3,l = 2\,\,\,\,\,\,\,{\rm{IV}}.{\rm{n}} = 3,l = \end{array}\]
If we arrange them in order of increasing energy, i.e. from lowest to highest, the correct order is
307319
Compare the energies of following sets of quantum numbers for multielectron system.
\[\begin{array}{l}
{\rm{(I)n}} = 4,l = 1\\
{\rm{(II)n}} = 4,l = 2\\
{\rm{(III)n}} = 3,l = 1\\
{\rm{(IV)n}} = 3,l = 2\\
{\rm{(V)n}} = 4,l = 0
\end{array}\]
Choose the correct answer from the options given below
307320
The electrons identified by quantum numbers \(\mathrm{n}\) and l , are as follows
\[\begin{array}{l}
{\rm{I}}{\rm{.n}} = 4,l = 1\,\,\,\,\,\,\,\,\,\,\,{\rm{II}}{\rm{.n}} = 4,l = 0\\
{\rm{III}}{\rm{.n}} = 3,l = 2\,\,\,\,\,\,\,{\rm{IV}}.{\rm{n}} = 3,l = \end{array}\]
If we arrange them in order of increasing energy, i.e. from lowest to highest, the correct order is
307319
Compare the energies of following sets of quantum numbers for multielectron system.
\[\begin{array}{l}
{\rm{(I)n}} = 4,l = 1\\
{\rm{(II)n}} = 4,l = 2\\
{\rm{(III)n}} = 3,l = 1\\
{\rm{(IV)n}} = 3,l = 2\\
{\rm{(V)n}} = 4,l = 0
\end{array}\]
Choose the correct answer from the options given below
307320
The electrons identified by quantum numbers \(\mathrm{n}\) and l , are as follows
\[\begin{array}{l}
{\rm{I}}{\rm{.n}} = 4,l = 1\,\,\,\,\,\,\,\,\,\,\,{\rm{II}}{\rm{.n}} = 4,l = 0\\
{\rm{III}}{\rm{.n}} = 3,l = 2\,\,\,\,\,\,\,{\rm{IV}}.{\rm{n}} = 3,l = \end{array}\]
If we arrange them in order of increasing energy, i.e. from lowest to highest, the correct order is
307319
Compare the energies of following sets of quantum numbers for multielectron system.
\[\begin{array}{l}
{\rm{(I)n}} = 4,l = 1\\
{\rm{(II)n}} = 4,l = 2\\
{\rm{(III)n}} = 3,l = 1\\
{\rm{(IV)n}} = 3,l = 2\\
{\rm{(V)n}} = 4,l = 0
\end{array}\]
Choose the correct answer from the options given below
307320
The electrons identified by quantum numbers \(\mathrm{n}\) and l , are as follows
\[\begin{array}{l}
{\rm{I}}{\rm{.n}} = 4,l = 1\,\,\,\,\,\,\,\,\,\,\,{\rm{II}}{\rm{.n}} = 4,l = 0\\
{\rm{III}}{\rm{.n}} = 3,l = 2\,\,\,\,\,\,\,{\rm{IV}}.{\rm{n}} = 3,l = \end{array}\]
If we arrange them in order of increasing energy, i.e. from lowest to highest, the correct order is