307097
A species X contains 9 protons, 10 electrons, 11 neutrons. Then it is
1 A neutral atom
2 An anion
3 An isotope
4 A cation
Explanation:
The number of electrons is more than number of protons. Hence it is an anion.
CHXI02:STRUCTURE OF ATOM
307098
In which of the following, the number of protons is greater than the number of neutrons but number of protons is less than the number of electrons?
1 \(\mathrm{\mathrm{D}_{3} \mathrm{O}^{+}}\)
2 \(\mathrm{\mathrm{SO}_{2}}\)
3 \(\mathrm{\mathrm{H}_{2} \mathrm{O}}\)
4 \(\mathrm{\mathrm{OH}^{-}}\)
Explanation:
In \(\mathrm{\mathrm{OH}^{-}}\), number of protons \(\mathrm{=8+1=9}\) number of neutrons \(\mathrm{=8+0=8}\) number of electrons \(\mathrm{=8+1+1=10}\)
CHXI02:STRUCTURE OF ATOM
307099
Atoms consists of protons, neutrons, and electrons. If the mass of neutrons and electrons were made half and two times, respectively to their actual masses, then the atomic mass of \({ }_{6} \mathrm{C}^{12}\) will
1 remain approximately the same
2 become approximately two times
3 remain approximately half
4 be reduced by \(25 \%\)
Explanation:
\({ }_{6} \mathrm{C}^{12}\) has 6 protons, 6 neutrons and 6 electrons. Electrons mass is not considered in atomic mass. Neutrons mass is mode half means \(=6 \times \dfrac{1}{2}=3\). Now, total mass will become 6 protons +3 neutrons \(=9\). \(\therefore\) decrease in atomic mass \(=12-9=3\) \(\therefore \%\) decrease in mass \(=\dfrac{3}{12} \times 100=25 \%\)
CHXI02:STRUCTURE OF ATOM
307100
The number of protons, neutrons and electrons in the ion \({ }_{16}^{32} \mathrm{~S}^{2-}\) respectively are
1 \(18,16,16\)
2 \(16,16,16\)
3 \(16,18,16\)
4 \(16,16,18\)
Explanation:
No. of Protons \(=16\) (atomic number) No. of Neutrons \({\text{ = 32 - 16 = 16(A - Z)}}\) No. of electrons \(=16+2=18\left(2 \mathrm{e}^{-}\right.\)gained \()\)
KCET - 2023
CHXI02:STRUCTURE OF ATOM
307101
An element with mass number 81 contains 31.7% more neutron as compared to potons.Its symbol is
1 \(_{{\rm{40}}}{{\rm{X}}^{{\rm{81}}}}\)
2 \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
3 \(_{81}{{\rm{X}}^{{\rm{31}}{\rm{.7}}}}\)
4 \(_{40}{{\rm{X}}^{81}}\)
Explanation:
Let,the number of protons=x \(\therefore \)Number of neutrons =\({\rm{x}} + \frac{{31.7{\rm{x}}}}{{100}} = \frac{{131.7{\rm{x}}}}{{100}}\) Mass number=number of protons+number of neurons \(81 = {\rm{x}} + \frac{{131.7{\rm{x}}}}{{100}}\) x=35 Thus,the symbol of the element is \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
307097
A species X contains 9 protons, 10 electrons, 11 neutrons. Then it is
1 A neutral atom
2 An anion
3 An isotope
4 A cation
Explanation:
The number of electrons is more than number of protons. Hence it is an anion.
CHXI02:STRUCTURE OF ATOM
307098
In which of the following, the number of protons is greater than the number of neutrons but number of protons is less than the number of electrons?
1 \(\mathrm{\mathrm{D}_{3} \mathrm{O}^{+}}\)
2 \(\mathrm{\mathrm{SO}_{2}}\)
3 \(\mathrm{\mathrm{H}_{2} \mathrm{O}}\)
4 \(\mathrm{\mathrm{OH}^{-}}\)
Explanation:
In \(\mathrm{\mathrm{OH}^{-}}\), number of protons \(\mathrm{=8+1=9}\) number of neutrons \(\mathrm{=8+0=8}\) number of electrons \(\mathrm{=8+1+1=10}\)
CHXI02:STRUCTURE OF ATOM
307099
Atoms consists of protons, neutrons, and electrons. If the mass of neutrons and electrons were made half and two times, respectively to their actual masses, then the atomic mass of \({ }_{6} \mathrm{C}^{12}\) will
1 remain approximately the same
2 become approximately two times
3 remain approximately half
4 be reduced by \(25 \%\)
Explanation:
\({ }_{6} \mathrm{C}^{12}\) has 6 protons, 6 neutrons and 6 electrons. Electrons mass is not considered in atomic mass. Neutrons mass is mode half means \(=6 \times \dfrac{1}{2}=3\). Now, total mass will become 6 protons +3 neutrons \(=9\). \(\therefore\) decrease in atomic mass \(=12-9=3\) \(\therefore \%\) decrease in mass \(=\dfrac{3}{12} \times 100=25 \%\)
CHXI02:STRUCTURE OF ATOM
307100
The number of protons, neutrons and electrons in the ion \({ }_{16}^{32} \mathrm{~S}^{2-}\) respectively are
1 \(18,16,16\)
2 \(16,16,16\)
3 \(16,18,16\)
4 \(16,16,18\)
Explanation:
No. of Protons \(=16\) (atomic number) No. of Neutrons \({\text{ = 32 - 16 = 16(A - Z)}}\) No. of electrons \(=16+2=18\left(2 \mathrm{e}^{-}\right.\)gained \()\)
KCET - 2023
CHXI02:STRUCTURE OF ATOM
307101
An element with mass number 81 contains 31.7% more neutron as compared to potons.Its symbol is
1 \(_{{\rm{40}}}{{\rm{X}}^{{\rm{81}}}}\)
2 \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
3 \(_{81}{{\rm{X}}^{{\rm{31}}{\rm{.7}}}}\)
4 \(_{40}{{\rm{X}}^{81}}\)
Explanation:
Let,the number of protons=x \(\therefore \)Number of neutrons =\({\rm{x}} + \frac{{31.7{\rm{x}}}}{{100}} = \frac{{131.7{\rm{x}}}}{{100}}\) Mass number=number of protons+number of neurons \(81 = {\rm{x}} + \frac{{131.7{\rm{x}}}}{{100}}\) x=35 Thus,the symbol of the element is \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
307097
A species X contains 9 protons, 10 electrons, 11 neutrons. Then it is
1 A neutral atom
2 An anion
3 An isotope
4 A cation
Explanation:
The number of electrons is more than number of protons. Hence it is an anion.
CHXI02:STRUCTURE OF ATOM
307098
In which of the following, the number of protons is greater than the number of neutrons but number of protons is less than the number of electrons?
1 \(\mathrm{\mathrm{D}_{3} \mathrm{O}^{+}}\)
2 \(\mathrm{\mathrm{SO}_{2}}\)
3 \(\mathrm{\mathrm{H}_{2} \mathrm{O}}\)
4 \(\mathrm{\mathrm{OH}^{-}}\)
Explanation:
In \(\mathrm{\mathrm{OH}^{-}}\), number of protons \(\mathrm{=8+1=9}\) number of neutrons \(\mathrm{=8+0=8}\) number of electrons \(\mathrm{=8+1+1=10}\)
CHXI02:STRUCTURE OF ATOM
307099
Atoms consists of protons, neutrons, and electrons. If the mass of neutrons and electrons were made half and two times, respectively to their actual masses, then the atomic mass of \({ }_{6} \mathrm{C}^{12}\) will
1 remain approximately the same
2 become approximately two times
3 remain approximately half
4 be reduced by \(25 \%\)
Explanation:
\({ }_{6} \mathrm{C}^{12}\) has 6 protons, 6 neutrons and 6 electrons. Electrons mass is not considered in atomic mass. Neutrons mass is mode half means \(=6 \times \dfrac{1}{2}=3\). Now, total mass will become 6 protons +3 neutrons \(=9\). \(\therefore\) decrease in atomic mass \(=12-9=3\) \(\therefore \%\) decrease in mass \(=\dfrac{3}{12} \times 100=25 \%\)
CHXI02:STRUCTURE OF ATOM
307100
The number of protons, neutrons and electrons in the ion \({ }_{16}^{32} \mathrm{~S}^{2-}\) respectively are
1 \(18,16,16\)
2 \(16,16,16\)
3 \(16,18,16\)
4 \(16,16,18\)
Explanation:
No. of Protons \(=16\) (atomic number) No. of Neutrons \({\text{ = 32 - 16 = 16(A - Z)}}\) No. of electrons \(=16+2=18\left(2 \mathrm{e}^{-}\right.\)gained \()\)
KCET - 2023
CHXI02:STRUCTURE OF ATOM
307101
An element with mass number 81 contains 31.7% more neutron as compared to potons.Its symbol is
1 \(_{{\rm{40}}}{{\rm{X}}^{{\rm{81}}}}\)
2 \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
3 \(_{81}{{\rm{X}}^{{\rm{31}}{\rm{.7}}}}\)
4 \(_{40}{{\rm{X}}^{81}}\)
Explanation:
Let,the number of protons=x \(\therefore \)Number of neutrons =\({\rm{x}} + \frac{{31.7{\rm{x}}}}{{100}} = \frac{{131.7{\rm{x}}}}{{100}}\) Mass number=number of protons+number of neurons \(81 = {\rm{x}} + \frac{{131.7{\rm{x}}}}{{100}}\) x=35 Thus,the symbol of the element is \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
307097
A species X contains 9 protons, 10 electrons, 11 neutrons. Then it is
1 A neutral atom
2 An anion
3 An isotope
4 A cation
Explanation:
The number of electrons is more than number of protons. Hence it is an anion.
CHXI02:STRUCTURE OF ATOM
307098
In which of the following, the number of protons is greater than the number of neutrons but number of protons is less than the number of electrons?
1 \(\mathrm{\mathrm{D}_{3} \mathrm{O}^{+}}\)
2 \(\mathrm{\mathrm{SO}_{2}}\)
3 \(\mathrm{\mathrm{H}_{2} \mathrm{O}}\)
4 \(\mathrm{\mathrm{OH}^{-}}\)
Explanation:
In \(\mathrm{\mathrm{OH}^{-}}\), number of protons \(\mathrm{=8+1=9}\) number of neutrons \(\mathrm{=8+0=8}\) number of electrons \(\mathrm{=8+1+1=10}\)
CHXI02:STRUCTURE OF ATOM
307099
Atoms consists of protons, neutrons, and electrons. If the mass of neutrons and electrons were made half and two times, respectively to their actual masses, then the atomic mass of \({ }_{6} \mathrm{C}^{12}\) will
1 remain approximately the same
2 become approximately two times
3 remain approximately half
4 be reduced by \(25 \%\)
Explanation:
\({ }_{6} \mathrm{C}^{12}\) has 6 protons, 6 neutrons and 6 electrons. Electrons mass is not considered in atomic mass. Neutrons mass is mode half means \(=6 \times \dfrac{1}{2}=3\). Now, total mass will become 6 protons +3 neutrons \(=9\). \(\therefore\) decrease in atomic mass \(=12-9=3\) \(\therefore \%\) decrease in mass \(=\dfrac{3}{12} \times 100=25 \%\)
CHXI02:STRUCTURE OF ATOM
307100
The number of protons, neutrons and electrons in the ion \({ }_{16}^{32} \mathrm{~S}^{2-}\) respectively are
1 \(18,16,16\)
2 \(16,16,16\)
3 \(16,18,16\)
4 \(16,16,18\)
Explanation:
No. of Protons \(=16\) (atomic number) No. of Neutrons \({\text{ = 32 - 16 = 16(A - Z)}}\) No. of electrons \(=16+2=18\left(2 \mathrm{e}^{-}\right.\)gained \()\)
KCET - 2023
CHXI02:STRUCTURE OF ATOM
307101
An element with mass number 81 contains 31.7% more neutron as compared to potons.Its symbol is
1 \(_{{\rm{40}}}{{\rm{X}}^{{\rm{81}}}}\)
2 \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
3 \(_{81}{{\rm{X}}^{{\rm{31}}{\rm{.7}}}}\)
4 \(_{40}{{\rm{X}}^{81}}\)
Explanation:
Let,the number of protons=x \(\therefore \)Number of neutrons =\({\rm{x}} + \frac{{31.7{\rm{x}}}}{{100}} = \frac{{131.7{\rm{x}}}}{{100}}\) Mass number=number of protons+number of neurons \(81 = {\rm{x}} + \frac{{131.7{\rm{x}}}}{{100}}\) x=35 Thus,the symbol of the element is \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
307097
A species X contains 9 protons, 10 electrons, 11 neutrons. Then it is
1 A neutral atom
2 An anion
3 An isotope
4 A cation
Explanation:
The number of electrons is more than number of protons. Hence it is an anion.
CHXI02:STRUCTURE OF ATOM
307098
In which of the following, the number of protons is greater than the number of neutrons but number of protons is less than the number of electrons?
1 \(\mathrm{\mathrm{D}_{3} \mathrm{O}^{+}}\)
2 \(\mathrm{\mathrm{SO}_{2}}\)
3 \(\mathrm{\mathrm{H}_{2} \mathrm{O}}\)
4 \(\mathrm{\mathrm{OH}^{-}}\)
Explanation:
In \(\mathrm{\mathrm{OH}^{-}}\), number of protons \(\mathrm{=8+1=9}\) number of neutrons \(\mathrm{=8+0=8}\) number of electrons \(\mathrm{=8+1+1=10}\)
CHXI02:STRUCTURE OF ATOM
307099
Atoms consists of protons, neutrons, and electrons. If the mass of neutrons and electrons were made half and two times, respectively to their actual masses, then the atomic mass of \({ }_{6} \mathrm{C}^{12}\) will
1 remain approximately the same
2 become approximately two times
3 remain approximately half
4 be reduced by \(25 \%\)
Explanation:
\({ }_{6} \mathrm{C}^{12}\) has 6 protons, 6 neutrons and 6 electrons. Electrons mass is not considered in atomic mass. Neutrons mass is mode half means \(=6 \times \dfrac{1}{2}=3\). Now, total mass will become 6 protons +3 neutrons \(=9\). \(\therefore\) decrease in atomic mass \(=12-9=3\) \(\therefore \%\) decrease in mass \(=\dfrac{3}{12} \times 100=25 \%\)
CHXI02:STRUCTURE OF ATOM
307100
The number of protons, neutrons and electrons in the ion \({ }_{16}^{32} \mathrm{~S}^{2-}\) respectively are
1 \(18,16,16\)
2 \(16,16,16\)
3 \(16,18,16\)
4 \(16,16,18\)
Explanation:
No. of Protons \(=16\) (atomic number) No. of Neutrons \({\text{ = 32 - 16 = 16(A - Z)}}\) No. of electrons \(=16+2=18\left(2 \mathrm{e}^{-}\right.\)gained \()\)
KCET - 2023
CHXI02:STRUCTURE OF ATOM
307101
An element with mass number 81 contains 31.7% more neutron as compared to potons.Its symbol is
1 \(_{{\rm{40}}}{{\rm{X}}^{{\rm{81}}}}\)
2 \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
3 \(_{81}{{\rm{X}}^{{\rm{31}}{\rm{.7}}}}\)
4 \(_{40}{{\rm{X}}^{81}}\)
Explanation:
Let,the number of protons=x \(\therefore \)Number of neutrons =\({\rm{x}} + \frac{{31.7{\rm{x}}}}{{100}} = \frac{{131.7{\rm{x}}}}{{100}}\) Mass number=number of protons+number of neurons \(81 = {\rm{x}} + \frac{{131.7{\rm{x}}}}{{100}}\) x=35 Thus,the symbol of the element is \(_{35}{{\rm{X}}^{{\rm{81}}}}\)
