307086
In the final answer of the expression \(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}\), the number of significant figures is :
1 1
2 2
3 3
4 4
Explanation:
\(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}{\rm{ = }}\frac{{{\rm{9}}{\rm{.0 \times 1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}}}{{{\rm{1}}{\rm{.37}}}}\) Least precise term viz 9.0 has only two significant figures. Hence, final answer will have two significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307087
Given the numbers : \(161 \mathrm{~cm}, 0.161 \mathrm{~cm}, 0.0161 \mathrm{~cm}\). The number of significant figures for the three numbers are
1 3, 4 and 5 respectively
2 3, 3 and 4 respectively
3 3, 3 and 3 respectively
4 3, 4 and 4 respectively
Explanation:
Each has three significant figures. When zero is used to locate the decimal point, it is not considered as significant figure.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307088
Arrange the numbers in increasing no. of significant figures. 0.002600, 2.6000, 2.6, 0.260
1 2.6 < 0.260 < 0.002600 < 2.6000
2 2.6000 < 2.6 < 0.002600 < 0.260
3 0.260 < 2.6 < 0.002600 < 2.6000
4 0.002600 < 0.260 < 2.6 < 2.6000
Explanation:
2.6 has two significant figures. 0.260 has four significant figures. 0.002600 has four significant figures. 2.6000 has five significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307089
How many significant figures are there in following measurement: 1.0056 m?
1 5
2 4
3 6
4 3
Explanation:
Any zeros between two significant digits are significant. Number of significant figures in 1.0056 is 5.
307086
In the final answer of the expression \(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}\), the number of significant figures is :
1 1
2 2
3 3
4 4
Explanation:
\(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}{\rm{ = }}\frac{{{\rm{9}}{\rm{.0 \times 1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}}}{{{\rm{1}}{\rm{.37}}}}\) Least precise term viz 9.0 has only two significant figures. Hence, final answer will have two significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307087
Given the numbers : \(161 \mathrm{~cm}, 0.161 \mathrm{~cm}, 0.0161 \mathrm{~cm}\). The number of significant figures for the three numbers are
1 3, 4 and 5 respectively
2 3, 3 and 4 respectively
3 3, 3 and 3 respectively
4 3, 4 and 4 respectively
Explanation:
Each has three significant figures. When zero is used to locate the decimal point, it is not considered as significant figure.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307088
Arrange the numbers in increasing no. of significant figures. 0.002600, 2.6000, 2.6, 0.260
1 2.6 < 0.260 < 0.002600 < 2.6000
2 2.6000 < 2.6 < 0.002600 < 0.260
3 0.260 < 2.6 < 0.002600 < 2.6000
4 0.002600 < 0.260 < 2.6 < 2.6000
Explanation:
2.6 has two significant figures. 0.260 has four significant figures. 0.002600 has four significant figures. 2.6000 has five significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307089
How many significant figures are there in following measurement: 1.0056 m?
1 5
2 4
3 6
4 3
Explanation:
Any zeros between two significant digits are significant. Number of significant figures in 1.0056 is 5.
307086
In the final answer of the expression \(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}\), the number of significant figures is :
1 1
2 2
3 3
4 4
Explanation:
\(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}{\rm{ = }}\frac{{{\rm{9}}{\rm{.0 \times 1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}}}{{{\rm{1}}{\rm{.37}}}}\) Least precise term viz 9.0 has only two significant figures. Hence, final answer will have two significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307087
Given the numbers : \(161 \mathrm{~cm}, 0.161 \mathrm{~cm}, 0.0161 \mathrm{~cm}\). The number of significant figures for the three numbers are
1 3, 4 and 5 respectively
2 3, 3 and 4 respectively
3 3, 3 and 3 respectively
4 3, 4 and 4 respectively
Explanation:
Each has three significant figures. When zero is used to locate the decimal point, it is not considered as significant figure.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307088
Arrange the numbers in increasing no. of significant figures. 0.002600, 2.6000, 2.6, 0.260
1 2.6 < 0.260 < 0.002600 < 2.6000
2 2.6000 < 2.6 < 0.002600 < 0.260
3 0.260 < 2.6 < 0.002600 < 2.6000
4 0.002600 < 0.260 < 2.6 < 2.6000
Explanation:
2.6 has two significant figures. 0.260 has four significant figures. 0.002600 has four significant figures. 2.6000 has five significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307089
How many significant figures are there in following measurement: 1.0056 m?
1 5
2 4
3 6
4 3
Explanation:
Any zeros between two significant digits are significant. Number of significant figures in 1.0056 is 5.
307086
In the final answer of the expression \(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}\), the number of significant figures is :
1 1
2 2
3 3
4 4
Explanation:
\(\frac{{\left( {{\rm{29}}{\rm{.2 - 20}}{\rm{.2}}} \right)\left( {{\rm{1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}} \right)}}{{{\rm{1}}{\rm{.37}}}}{\rm{ = }}\frac{{{\rm{9}}{\rm{.0 \times 1}}{\rm{.79 \times 1}}{{\rm{0}}^{\rm{5}}}}}{{{\rm{1}}{\rm{.37}}}}\) Least precise term viz 9.0 has only two significant figures. Hence, final answer will have two significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307087
Given the numbers : \(161 \mathrm{~cm}, 0.161 \mathrm{~cm}, 0.0161 \mathrm{~cm}\). The number of significant figures for the three numbers are
1 3, 4 and 5 respectively
2 3, 3 and 4 respectively
3 3, 3 and 3 respectively
4 3, 4 and 4 respectively
Explanation:
Each has three significant figures. When zero is used to locate the decimal point, it is not considered as significant figure.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307088
Arrange the numbers in increasing no. of significant figures. 0.002600, 2.6000, 2.6, 0.260
1 2.6 < 0.260 < 0.002600 < 2.6000
2 2.6000 < 2.6 < 0.002600 < 0.260
3 0.260 < 2.6 < 0.002600 < 2.6000
4 0.002600 < 0.260 < 2.6 < 2.6000
Explanation:
2.6 has two significant figures. 0.260 has four significant figures. 0.002600 has four significant figures. 2.6000 has five significant figures.
CHXI01:SOME BASIC CONCEPTS OF CHEMISTRY
307089
How many significant figures are there in following measurement: 1.0056 m?
1 5
2 4
3 6
4 3
Explanation:
Any zeros between two significant digits are significant. Number of significant figures in 1.0056 is 5.
