307010
n g of a substance X reacts with m g of substance Y to form p g of substance R and q g of substance S.
This reaction can be represented as follow : \({\rm{X + Y = R + S}}\)
The relation which can be established in the amounts of the reactants and the products will be
307011
Liquid benzene burns in oxygen according to following equation
\({\rm{2}}{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{6}}}{\rm{ + 15}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{12C}}{{\rm{O}}_{\rm{2}}}{\rm{(g) + 6}}{{\rm{H}}_{\rm{2}}}{\rm{O(g)}}\)
How many litres of oxygen are required for complete combustion of 39 g of liquid benzene?
307010
n g of a substance X reacts with m g of substance Y to form p g of substance R and q g of substance S.
This reaction can be represented as follow : \({\rm{X + Y = R + S}}\)
The relation which can be established in the amounts of the reactants and the products will be
307011
Liquid benzene burns in oxygen according to following equation
\({\rm{2}}{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{6}}}{\rm{ + 15}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{12C}}{{\rm{O}}_{\rm{2}}}{\rm{(g) + 6}}{{\rm{H}}_{\rm{2}}}{\rm{O(g)}}\)
How many litres of oxygen are required for complete combustion of 39 g of liquid benzene?
307010
n g of a substance X reacts with m g of substance Y to form p g of substance R and q g of substance S.
This reaction can be represented as follow : \({\rm{X + Y = R + S}}\)
The relation which can be established in the amounts of the reactants and the products will be
307011
Liquid benzene burns in oxygen according to following equation
\({\rm{2}}{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{6}}}{\rm{ + 15}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{12C}}{{\rm{O}}_{\rm{2}}}{\rm{(g) + 6}}{{\rm{H}}_{\rm{2}}}{\rm{O(g)}}\)
How many litres of oxygen are required for complete combustion of 39 g of liquid benzene?
307010
n g of a substance X reacts with m g of substance Y to form p g of substance R and q g of substance S.
This reaction can be represented as follow : \({\rm{X + Y = R + S}}\)
The relation which can be established in the amounts of the reactants and the products will be
307011
Liquid benzene burns in oxygen according to following equation
\({\rm{2}}{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{6}}}{\rm{ + 15}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{12C}}{{\rm{O}}_{\rm{2}}}{\rm{(g) + 6}}{{\rm{H}}_{\rm{2}}}{\rm{O(g)}}\)
How many litres of oxygen are required for complete combustion of 39 g of liquid benzene?
307010
n g of a substance X reacts with m g of substance Y to form p g of substance R and q g of substance S.
This reaction can be represented as follow : \({\rm{X + Y = R + S}}\)
The relation which can be established in the amounts of the reactants and the products will be
307011
Liquid benzene burns in oxygen according to following equation
\({\rm{2}}{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{6}}}{\rm{ + 15}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{12C}}{{\rm{O}}_{\rm{2}}}{\rm{(g) + 6}}{{\rm{H}}_{\rm{2}}}{\rm{O(g)}}\)
How many litres of oxygen are required for complete combustion of 39 g of liquid benzene?