Coulomb's Law
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NEET DIGITAL LIBRARY
PHXII01:ELECTRIC CHARGES AND FIELDS

358104 Two identical metal spheres possesses \( + 60\,C\) and \( - 20\,C\) of charges. They are brought in contact and the then separated by \(10\,cm\). The force between them is

1 \(36 \times {10^{13}}\,N\)
2 \(36 \times {10^{14}}\,N\)
3 \(36 \times {10^{12}}\,N\)
4 \(3.6 \times {10^{12}}\,N\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358105 Charges on two spheres are \( + 10\,\mu C\) and \( - 5\,\mu C\) respectively. They experience a force \(F\). If each of them is given an additional charge \( + 2\,\mu C\) then new force between them keeping the same distance is

1 \(18\,F\)
2 \(\dfrac{F}{25}\)
3 \(\frac{{18\,F}}{{25}}\)
4 \(\dfrac{25}{18} F\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358106 Force between \({A}\) and \({B}\) is \({F}\) as shown in the figure. If \({50 \%}\) charge \({A}\) of is transferred to \({B}\), then force between \({A}\) and \({B}\) is
supporting img

1 \({\dfrac{F}{3}}\)
2 \({4 F}\)
3 \({\dfrac{5 F}{2}}\)
4 \({2 F}\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358107 Force between two identical charges placed at a distance of \(r\) in vacuum is \(F\). Now a slab of dielectric of dielectric contrant 4 is inserted between these two charges. If the thickness of the slab is \(r/2\), then the force between the charges will become

1 \(F\)
2 \(\frac{3}{5}F\)
3 \(\frac{4}{9}F\)
4 \(\frac{F}{2}\)
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PHXII01:ELECTRIC CHARGES AND FIELDS

358104 Two identical metal spheres possesses \( + 60\,C\) and \( - 20\,C\) of charges. They are brought in contact and the then separated by \(10\,cm\). The force between them is

1 \(36 \times {10^{13}}\,N\)
2 \(36 \times {10^{14}}\,N\)
3 \(36 \times {10^{12}}\,N\)
4 \(3.6 \times {10^{12}}\,N\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358105 Charges on two spheres are \( + 10\,\mu C\) and \( - 5\,\mu C\) respectively. They experience a force \(F\). If each of them is given an additional charge \( + 2\,\mu C\) then new force between them keeping the same distance is

1 \(18\,F\)
2 \(\dfrac{F}{25}\)
3 \(\frac{{18\,F}}{{25}}\)
4 \(\dfrac{25}{18} F\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358106 Force between \({A}\) and \({B}\) is \({F}\) as shown in the figure. If \({50 \%}\) charge \({A}\) of is transferred to \({B}\), then force between \({A}\) and \({B}\) is
supporting img

1 \({\dfrac{F}{3}}\)
2 \({4 F}\)
3 \({\dfrac{5 F}{2}}\)
4 \({2 F}\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358107 Force between two identical charges placed at a distance of \(r\) in vacuum is \(F\). Now a slab of dielectric of dielectric contrant 4 is inserted between these two charges. If the thickness of the slab is \(r/2\), then the force between the charges will become

1 \(F\)
2 \(\frac{3}{5}F\)
3 \(\frac{4}{9}F\)
4 \(\frac{F}{2}\)
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII01:ELECTRIC CHARGES AND FIELDS

358104 Two identical metal spheres possesses \( + 60\,C\) and \( - 20\,C\) of charges. They are brought in contact and the then separated by \(10\,cm\). The force between them is

1 \(36 \times {10^{13}}\,N\)
2 \(36 \times {10^{14}}\,N\)
3 \(36 \times {10^{12}}\,N\)
4 \(3.6 \times {10^{12}}\,N\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358105 Charges on two spheres are \( + 10\,\mu C\) and \( - 5\,\mu C\) respectively. They experience a force \(F\). If each of them is given an additional charge \( + 2\,\mu C\) then new force between them keeping the same distance is

1 \(18\,F\)
2 \(\dfrac{F}{25}\)
3 \(\frac{{18\,F}}{{25}}\)
4 \(\dfrac{25}{18} F\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358106 Force between \({A}\) and \({B}\) is \({F}\) as shown in the figure. If \({50 \%}\) charge \({A}\) of is transferred to \({B}\), then force between \({A}\) and \({B}\) is
supporting img

1 \({\dfrac{F}{3}}\)
2 \({4 F}\)
3 \({\dfrac{5 F}{2}}\)
4 \({2 F}\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358107 Force between two identical charges placed at a distance of \(r\) in vacuum is \(F\). Now a slab of dielectric of dielectric contrant 4 is inserted between these two charges. If the thickness of the slab is \(r/2\), then the force between the charges will become

1 \(F\)
2 \(\frac{3}{5}F\)
3 \(\frac{4}{9}F\)
4 \(\frac{F}{2}\)
NEET DIGITAL LIBRARY
PHXII01:ELECTRIC CHARGES AND FIELDS

358104 Two identical metal spheres possesses \( + 60\,C\) and \( - 20\,C\) of charges. They are brought in contact and the then separated by \(10\,cm\). The force between them is

1 \(36 \times {10^{13}}\,N\)
2 \(36 \times {10^{14}}\,N\)
3 \(36 \times {10^{12}}\,N\)
4 \(3.6 \times {10^{12}}\,N\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358105 Charges on two spheres are \( + 10\,\mu C\) and \( - 5\,\mu C\) respectively. They experience a force \(F\). If each of them is given an additional charge \( + 2\,\mu C\) then new force between them keeping the same distance is

1 \(18\,F\)
2 \(\dfrac{F}{25}\)
3 \(\frac{{18\,F}}{{25}}\)
4 \(\dfrac{25}{18} F\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358106 Force between \({A}\) and \({B}\) is \({F}\) as shown in the figure. If \({50 \%}\) charge \({A}\) of is transferred to \({B}\), then force between \({A}\) and \({B}\) is
supporting img

1 \({\dfrac{F}{3}}\)
2 \({4 F}\)
3 \({\dfrac{5 F}{2}}\)
4 \({2 F}\)
PHXII01:ELECTRIC CHARGES AND FIELDS

358107 Force between two identical charges placed at a distance of \(r\) in vacuum is \(F\). Now a slab of dielectric of dielectric contrant 4 is inserted between these two charges. If the thickness of the slab is \(r/2\), then the force between the charges will become

1 \(F\)
2 \(\frac{3}{5}F\)
3 \(\frac{4}{9}F\)
4 \(\frac{F}{2}\)
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