357618
In the following diagram if \(V_{2}>V_{1}\) then (for same photo metal)
1 \(\lambda_{1}=\sqrt{\lambda_{2}}\)
2 \(\lambda_{1} < \lambda_{2}\)
3 \(\lambda_{1}=\lambda_{2}\)
4 \(\lambda_{1}>\lambda_{2}\)
Explanation:
Conceptual Question
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357619
When the distance of a point light source from a photocell is \(r_{1}\), photoelectric current is \(I_{1}\). If the distance becomes \(r_{2}\), then the current is \(I_{2}\). The ratio \(\left(I_{1}: I_{2}\right)\) is equal to
1 \(r_{2}^{2}: r_{1}^{2}\)
2 \(r_{2}: r_{1}\)
3 \(r_{1}^{2}: r_{2}^{2}\)
4 \(r_{1}: r_{2}\)
Explanation:
Photo electric current \((I) \propto\) intensity and, intensity \(\propto \dfrac{1}{r}\). \(\Rightarrow(I) \propto \dfrac{1}{r^{2}} \Rightarrow \dfrac{I_{1}}{I_{2}}=\dfrac{r_{2}^{2}}{r_{1}^{2}}\).
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357620
Light of power \(1.5\,mW\) and wavelength \(400\,nm\) is directed at a photoelectric cell. If \({0.10 \%}\) of the incident photons produce photoelectrons, the current in the cell is
1 \(0.36\,\mu A\)
2 \(0.48\,{\mkern 1mu} \mu A\)
3 \(0.42\,mA\)
4 \(0.32\,mA\)
Explanation:
Number of photoelectron emitted per second, \({n=\dfrac{P}{h c / \lambda}}\) \({=\dfrac{1.5 \times 10^{-3} {~W} \times\left(10^{-3}\right)}{\dfrac{1240({~nm})({eV})}{400({~nm})} \times e({~V} / {s})}}\) \({=\dfrac{0.48}{e} \times 10^{-6}}\) \({\therefore}\) Photo current \({=n e=0.48 \mu {A}}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357621
The number of photoelectrons emitted for light of a frequency \(v\) (higher than the threshold frequency \(v_{0}\) ) is proportional to
1 Intensity of light
2 Threshold frequency \(\left(v_{0}\right)\)
3 Frequency of light
4 \(v-v_{0}\)
Explanation:
If intensity increases, number of photoelectrons increases.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357622
The variation of stopping potential \(\left(V_{0}\right)\) as a function of the frequency \((v)\) of the incident light for a metal is shown in figure. The work function of the surface is
1 \(18.6\,eV\)
2 \(2.07\,eV\)
3 \(2.98\,eV\)
4 \(1.36\,eV\)
Explanation:
From the graph it is evident that threshold frequency \({v_0} = 5 \times {10^4}\;Hz\). \(\therefore \quad \phi=h v_{0}\) \( = 6.6 \times {10^{ - 34}} \times 5 \times {10^{14}} = 33 \times {10^{ - 20}}\;J\) \(\phi = \frac{{33 \times {{10}^{ - 20}}}}{{1.6 \times {{10}^{ - 19}}}} = 2.07eV\)
357618
In the following diagram if \(V_{2}>V_{1}\) then (for same photo metal)
1 \(\lambda_{1}=\sqrt{\lambda_{2}}\)
2 \(\lambda_{1} < \lambda_{2}\)
3 \(\lambda_{1}=\lambda_{2}\)
4 \(\lambda_{1}>\lambda_{2}\)
Explanation:
Conceptual Question
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357619
When the distance of a point light source from a photocell is \(r_{1}\), photoelectric current is \(I_{1}\). If the distance becomes \(r_{2}\), then the current is \(I_{2}\). The ratio \(\left(I_{1}: I_{2}\right)\) is equal to
1 \(r_{2}^{2}: r_{1}^{2}\)
2 \(r_{2}: r_{1}\)
3 \(r_{1}^{2}: r_{2}^{2}\)
4 \(r_{1}: r_{2}\)
Explanation:
Photo electric current \((I) \propto\) intensity and, intensity \(\propto \dfrac{1}{r}\). \(\Rightarrow(I) \propto \dfrac{1}{r^{2}} \Rightarrow \dfrac{I_{1}}{I_{2}}=\dfrac{r_{2}^{2}}{r_{1}^{2}}\).
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357620
Light of power \(1.5\,mW\) and wavelength \(400\,nm\) is directed at a photoelectric cell. If \({0.10 \%}\) of the incident photons produce photoelectrons, the current in the cell is
1 \(0.36\,\mu A\)
2 \(0.48\,{\mkern 1mu} \mu A\)
3 \(0.42\,mA\)
4 \(0.32\,mA\)
Explanation:
Number of photoelectron emitted per second, \({n=\dfrac{P}{h c / \lambda}}\) \({=\dfrac{1.5 \times 10^{-3} {~W} \times\left(10^{-3}\right)}{\dfrac{1240({~nm})({eV})}{400({~nm})} \times e({~V} / {s})}}\) \({=\dfrac{0.48}{e} \times 10^{-6}}\) \({\therefore}\) Photo current \({=n e=0.48 \mu {A}}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357621
The number of photoelectrons emitted for light of a frequency \(v\) (higher than the threshold frequency \(v_{0}\) ) is proportional to
1 Intensity of light
2 Threshold frequency \(\left(v_{0}\right)\)
3 Frequency of light
4 \(v-v_{0}\)
Explanation:
If intensity increases, number of photoelectrons increases.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357622
The variation of stopping potential \(\left(V_{0}\right)\) as a function of the frequency \((v)\) of the incident light for a metal is shown in figure. The work function of the surface is
1 \(18.6\,eV\)
2 \(2.07\,eV\)
3 \(2.98\,eV\)
4 \(1.36\,eV\)
Explanation:
From the graph it is evident that threshold frequency \({v_0} = 5 \times {10^4}\;Hz\). \(\therefore \quad \phi=h v_{0}\) \( = 6.6 \times {10^{ - 34}} \times 5 \times {10^{14}} = 33 \times {10^{ - 20}}\;J\) \(\phi = \frac{{33 \times {{10}^{ - 20}}}}{{1.6 \times {{10}^{ - 19}}}} = 2.07eV\)
357618
In the following diagram if \(V_{2}>V_{1}\) then (for same photo metal)
1 \(\lambda_{1}=\sqrt{\lambda_{2}}\)
2 \(\lambda_{1} < \lambda_{2}\)
3 \(\lambda_{1}=\lambda_{2}\)
4 \(\lambda_{1}>\lambda_{2}\)
Explanation:
Conceptual Question
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357619
When the distance of a point light source from a photocell is \(r_{1}\), photoelectric current is \(I_{1}\). If the distance becomes \(r_{2}\), then the current is \(I_{2}\). The ratio \(\left(I_{1}: I_{2}\right)\) is equal to
1 \(r_{2}^{2}: r_{1}^{2}\)
2 \(r_{2}: r_{1}\)
3 \(r_{1}^{2}: r_{2}^{2}\)
4 \(r_{1}: r_{2}\)
Explanation:
Photo electric current \((I) \propto\) intensity and, intensity \(\propto \dfrac{1}{r}\). \(\Rightarrow(I) \propto \dfrac{1}{r^{2}} \Rightarrow \dfrac{I_{1}}{I_{2}}=\dfrac{r_{2}^{2}}{r_{1}^{2}}\).
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357620
Light of power \(1.5\,mW\) and wavelength \(400\,nm\) is directed at a photoelectric cell. If \({0.10 \%}\) of the incident photons produce photoelectrons, the current in the cell is
1 \(0.36\,\mu A\)
2 \(0.48\,{\mkern 1mu} \mu A\)
3 \(0.42\,mA\)
4 \(0.32\,mA\)
Explanation:
Number of photoelectron emitted per second, \({n=\dfrac{P}{h c / \lambda}}\) \({=\dfrac{1.5 \times 10^{-3} {~W} \times\left(10^{-3}\right)}{\dfrac{1240({~nm})({eV})}{400({~nm})} \times e({~V} / {s})}}\) \({=\dfrac{0.48}{e} \times 10^{-6}}\) \({\therefore}\) Photo current \({=n e=0.48 \mu {A}}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357621
The number of photoelectrons emitted for light of a frequency \(v\) (higher than the threshold frequency \(v_{0}\) ) is proportional to
1 Intensity of light
2 Threshold frequency \(\left(v_{0}\right)\)
3 Frequency of light
4 \(v-v_{0}\)
Explanation:
If intensity increases, number of photoelectrons increases.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357622
The variation of stopping potential \(\left(V_{0}\right)\) as a function of the frequency \((v)\) of the incident light for a metal is shown in figure. The work function of the surface is
1 \(18.6\,eV\)
2 \(2.07\,eV\)
3 \(2.98\,eV\)
4 \(1.36\,eV\)
Explanation:
From the graph it is evident that threshold frequency \({v_0} = 5 \times {10^4}\;Hz\). \(\therefore \quad \phi=h v_{0}\) \( = 6.6 \times {10^{ - 34}} \times 5 \times {10^{14}} = 33 \times {10^{ - 20}}\;J\) \(\phi = \frac{{33 \times {{10}^{ - 20}}}}{{1.6 \times {{10}^{ - 19}}}} = 2.07eV\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII11:DUAL NATURE OF RADIATION AND MATTER
357618
In the following diagram if \(V_{2}>V_{1}\) then (for same photo metal)
1 \(\lambda_{1}=\sqrt{\lambda_{2}}\)
2 \(\lambda_{1} < \lambda_{2}\)
3 \(\lambda_{1}=\lambda_{2}\)
4 \(\lambda_{1}>\lambda_{2}\)
Explanation:
Conceptual Question
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357619
When the distance of a point light source from a photocell is \(r_{1}\), photoelectric current is \(I_{1}\). If the distance becomes \(r_{2}\), then the current is \(I_{2}\). The ratio \(\left(I_{1}: I_{2}\right)\) is equal to
1 \(r_{2}^{2}: r_{1}^{2}\)
2 \(r_{2}: r_{1}\)
3 \(r_{1}^{2}: r_{2}^{2}\)
4 \(r_{1}: r_{2}\)
Explanation:
Photo electric current \((I) \propto\) intensity and, intensity \(\propto \dfrac{1}{r}\). \(\Rightarrow(I) \propto \dfrac{1}{r^{2}} \Rightarrow \dfrac{I_{1}}{I_{2}}=\dfrac{r_{2}^{2}}{r_{1}^{2}}\).
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357620
Light of power \(1.5\,mW\) and wavelength \(400\,nm\) is directed at a photoelectric cell. If \({0.10 \%}\) of the incident photons produce photoelectrons, the current in the cell is
1 \(0.36\,\mu A\)
2 \(0.48\,{\mkern 1mu} \mu A\)
3 \(0.42\,mA\)
4 \(0.32\,mA\)
Explanation:
Number of photoelectron emitted per second, \({n=\dfrac{P}{h c / \lambda}}\) \({=\dfrac{1.5 \times 10^{-3} {~W} \times\left(10^{-3}\right)}{\dfrac{1240({~nm})({eV})}{400({~nm})} \times e({~V} / {s})}}\) \({=\dfrac{0.48}{e} \times 10^{-6}}\) \({\therefore}\) Photo current \({=n e=0.48 \mu {A}}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357621
The number of photoelectrons emitted for light of a frequency \(v\) (higher than the threshold frequency \(v_{0}\) ) is proportional to
1 Intensity of light
2 Threshold frequency \(\left(v_{0}\right)\)
3 Frequency of light
4 \(v-v_{0}\)
Explanation:
If intensity increases, number of photoelectrons increases.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357622
The variation of stopping potential \(\left(V_{0}\right)\) as a function of the frequency \((v)\) of the incident light for a metal is shown in figure. The work function of the surface is
1 \(18.6\,eV\)
2 \(2.07\,eV\)
3 \(2.98\,eV\)
4 \(1.36\,eV\)
Explanation:
From the graph it is evident that threshold frequency \({v_0} = 5 \times {10^4}\;Hz\). \(\therefore \quad \phi=h v_{0}\) \( = 6.6 \times {10^{ - 34}} \times 5 \times {10^{14}} = 33 \times {10^{ - 20}}\;J\) \(\phi = \frac{{33 \times {{10}^{ - 20}}}}{{1.6 \times {{10}^{ - 19}}}} = 2.07eV\)
357618
In the following diagram if \(V_{2}>V_{1}\) then (for same photo metal)
1 \(\lambda_{1}=\sqrt{\lambda_{2}}\)
2 \(\lambda_{1} < \lambda_{2}\)
3 \(\lambda_{1}=\lambda_{2}\)
4 \(\lambda_{1}>\lambda_{2}\)
Explanation:
Conceptual Question
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357619
When the distance of a point light source from a photocell is \(r_{1}\), photoelectric current is \(I_{1}\). If the distance becomes \(r_{2}\), then the current is \(I_{2}\). The ratio \(\left(I_{1}: I_{2}\right)\) is equal to
1 \(r_{2}^{2}: r_{1}^{2}\)
2 \(r_{2}: r_{1}\)
3 \(r_{1}^{2}: r_{2}^{2}\)
4 \(r_{1}: r_{2}\)
Explanation:
Photo electric current \((I) \propto\) intensity and, intensity \(\propto \dfrac{1}{r}\). \(\Rightarrow(I) \propto \dfrac{1}{r^{2}} \Rightarrow \dfrac{I_{1}}{I_{2}}=\dfrac{r_{2}^{2}}{r_{1}^{2}}\).
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357620
Light of power \(1.5\,mW\) and wavelength \(400\,nm\) is directed at a photoelectric cell. If \({0.10 \%}\) of the incident photons produce photoelectrons, the current in the cell is
1 \(0.36\,\mu A\)
2 \(0.48\,{\mkern 1mu} \mu A\)
3 \(0.42\,mA\)
4 \(0.32\,mA\)
Explanation:
Number of photoelectron emitted per second, \({n=\dfrac{P}{h c / \lambda}}\) \({=\dfrac{1.5 \times 10^{-3} {~W} \times\left(10^{-3}\right)}{\dfrac{1240({~nm})({eV})}{400({~nm})} \times e({~V} / {s})}}\) \({=\dfrac{0.48}{e} \times 10^{-6}}\) \({\therefore}\) Photo current \({=n e=0.48 \mu {A}}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357621
The number of photoelectrons emitted for light of a frequency \(v\) (higher than the threshold frequency \(v_{0}\) ) is proportional to
1 Intensity of light
2 Threshold frequency \(\left(v_{0}\right)\)
3 Frequency of light
4 \(v-v_{0}\)
Explanation:
If intensity increases, number of photoelectrons increases.
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357622
The variation of stopping potential \(\left(V_{0}\right)\) as a function of the frequency \((v)\) of the incident light for a metal is shown in figure. The work function of the surface is
1 \(18.6\,eV\)
2 \(2.07\,eV\)
3 \(2.98\,eV\)
4 \(1.36\,eV\)
Explanation:
From the graph it is evident that threshold frequency \({v_0} = 5 \times {10^4}\;Hz\). \(\therefore \quad \phi=h v_{0}\) \( = 6.6 \times {10^{ - 34}} \times 5 \times {10^{14}} = 33 \times {10^{ - 20}}\;J\) \(\phi = \frac{{33 \times {{10}^{ - 20}}}}{{1.6 \times {{10}^{ - 19}}}} = 2.07eV\)
