357600 Wavelength associated with a photon having energy \(4.14\,eV\) is

357601 A radio transmitter radiated \(1\;kW\) power at a wavelength \(198.6\;m\). How many photons does it emit per second?

357602 A photon in motion has a mass:

357603 Minimum light intensity that can be perceived by normal human eye is about \({10^{ - 10}}W{m^{ - 2}}\). What is the minimum number of photons of wavelength \(660\;nm\) that must enter the pupil in \(1\;s\) for one to see the object? Area of cross-section of the pupil is \({10^{ - 4}}\;{m^2}\).

357600 Wavelength associated with a photon having energy \(4.14\,eV\) is

357601 A radio transmitter radiated \(1\;kW\) power at a wavelength \(198.6\;m\). How many photons does it emit per second?

357602 A photon in motion has a mass:

357603 Minimum light intensity that can be perceived by normal human eye is about \({10^{ - 10}}W{m^{ - 2}}\). What is the minimum number of photons of wavelength \(660\;nm\) that must enter the pupil in \(1\;s\) for one to see the object? Area of cross-section of the pupil is \({10^{ - 4}}\;{m^2}\).

357600 Wavelength associated with a photon having energy \(4.14\,eV\) is

357601 A radio transmitter radiated \(1\;kW\) power at a wavelength \(198.6\;m\). How many photons does it emit per second?

357602 A photon in motion has a mass:

357603 Minimum light intensity that can be perceived by normal human eye is about \({10^{ - 10}}W{m^{ - 2}}\). What is the minimum number of photons of wavelength \(660\;nm\) that must enter the pupil in \(1\;s\) for one to see the object? Area of cross-section of the pupil is \({10^{ - 4}}\;{m^2}\).

357600 Wavelength associated with a photon having energy \(4.14\,eV\) is

357601 A radio transmitter radiated \(1\;kW\) power at a wavelength \(198.6\;m\). How many photons does it emit per second?

357602 A photon in motion has a mass:

357603 Minimum light intensity that can be perceived by normal human eye is about \({10^{ - 10}}W{m^{ - 2}}\). What is the minimum number of photons of wavelength \(660\;nm\) that must enter the pupil in \(1\;s\) for one to see the object? Area of cross-section of the pupil is \({10^{ - 4}}\;{m^2}\).