Explanation:
Number of electrons emitted is inversely proportional to the square of distance, \(i.e.,\) \({n \propto \dfrac{1}{r^{2}}}\).
\(\therefore \;\;\;{n_1} \propto \frac{1}{{{{(1)}^2}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\)
Also, \({n_2} \propto \frac{1}{{{{\left( {\frac{1}{2}} \right)}^2}}}{\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)\)
Dividing eqs. (1) and (2), we get
\({\dfrac{n_{1}}{n_{2}}=\dfrac{1}{4} \Rightarrow n_{2}=4 n_{1}}\).
So correct option is (2)