Electrical Instruments
PHXII03:CURRENT ELECTRICITY

357324 A potentiometer wire is 100 \(cm\) long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 \(cm\) and 10 \(cm\) from the positive end of the wire in the two cases. The ratio of emf’s is:-

1 \(5:1\)
2 \(5:4\)
3 \(3:4\)
4 \(3:2\)
PHXII03:CURRENT ELECTRICITY

357325 Assertion :
A potentiometer of longer length is used for accurate measurement.
Reason :
The potential gradient for a potentiometer of longer length with a given source of e.m.f becomes small.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII03:CURRENT ELECTRICITY

357326 A potentiometer is used for the comparison of emf of two cells \(E_{1}\) and \(E_{2}\). For cell \(E_{1}\), the no deflection point is obtained at \(20\;cm\) and for \(E_{2}\), the no deflection point is obtained at \(30\;cm\). The ratio of their emfs will be

1 \(2 / 3\)
2 \(3 / 2\)
3 1
4 2
PHXII03:CURRENT ELECTRICITY

357327 In a potentiometer, the null point is received at \({7^{th}}\) wire. If we have to change the null point at the \({9^{th}}\) wire, what should we do?

1 Attach a resistance in series with battery
2 Increase resistance in main circuit
3 Decrease resistance in main circuit
4 Decrease applied emf
PHXII03:CURRENT ELECTRICITY

357324 A potentiometer wire is 100 \(cm\) long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 \(cm\) and 10 \(cm\) from the positive end of the wire in the two cases. The ratio of emf’s is:-

1 \(5:1\)
2 \(5:4\)
3 \(3:4\)
4 \(3:2\)
PHXII03:CURRENT ELECTRICITY

357325 Assertion :
A potentiometer of longer length is used for accurate measurement.
Reason :
The potential gradient for a potentiometer of longer length with a given source of e.m.f becomes small.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII03:CURRENT ELECTRICITY

357326 A potentiometer is used for the comparison of emf of two cells \(E_{1}\) and \(E_{2}\). For cell \(E_{1}\), the no deflection point is obtained at \(20\;cm\) and for \(E_{2}\), the no deflection point is obtained at \(30\;cm\). The ratio of their emfs will be

1 \(2 / 3\)
2 \(3 / 2\)
3 1
4 2
PHXII03:CURRENT ELECTRICITY

357327 In a potentiometer, the null point is received at \({7^{th}}\) wire. If we have to change the null point at the \({9^{th}}\) wire, what should we do?

1 Attach a resistance in series with battery
2 Increase resistance in main circuit
3 Decrease resistance in main circuit
4 Decrease applied emf
PHXII03:CURRENT ELECTRICITY

357324 A potentiometer wire is 100 \(cm\) long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 \(cm\) and 10 \(cm\) from the positive end of the wire in the two cases. The ratio of emf’s is:-

1 \(5:1\)
2 \(5:4\)
3 \(3:4\)
4 \(3:2\)
PHXII03:CURRENT ELECTRICITY

357325 Assertion :
A potentiometer of longer length is used for accurate measurement.
Reason :
The potential gradient for a potentiometer of longer length with a given source of e.m.f becomes small.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII03:CURRENT ELECTRICITY

357326 A potentiometer is used for the comparison of emf of two cells \(E_{1}\) and \(E_{2}\). For cell \(E_{1}\), the no deflection point is obtained at \(20\;cm\) and for \(E_{2}\), the no deflection point is obtained at \(30\;cm\). The ratio of their emfs will be

1 \(2 / 3\)
2 \(3 / 2\)
3 1
4 2
PHXII03:CURRENT ELECTRICITY

357327 In a potentiometer, the null point is received at \({7^{th}}\) wire. If we have to change the null point at the \({9^{th}}\) wire, what should we do?

1 Attach a resistance in series with battery
2 Increase resistance in main circuit
3 Decrease resistance in main circuit
4 Decrease applied emf
PHXII03:CURRENT ELECTRICITY

357324 A potentiometer wire is 100 \(cm\) long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 \(cm\) and 10 \(cm\) from the positive end of the wire in the two cases. The ratio of emf’s is:-

1 \(5:1\)
2 \(5:4\)
3 \(3:4\)
4 \(3:2\)
PHXII03:CURRENT ELECTRICITY

357325 Assertion :
A potentiometer of longer length is used for accurate measurement.
Reason :
The potential gradient for a potentiometer of longer length with a given source of e.m.f becomes small.

1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
PHXII03:CURRENT ELECTRICITY

357326 A potentiometer is used for the comparison of emf of two cells \(E_{1}\) and \(E_{2}\). For cell \(E_{1}\), the no deflection point is obtained at \(20\;cm\) and for \(E_{2}\), the no deflection point is obtained at \(30\;cm\). The ratio of their emfs will be

1 \(2 / 3\)
2 \(3 / 2\)
3 1
4 2
PHXII03:CURRENT ELECTRICITY

357327 In a potentiometer, the null point is received at \({7^{th}}\) wire. If we have to change the null point at the \({9^{th}}\) wire, what should we do?

1 Attach a resistance in series with battery
2 Increase resistance in main circuit
3 Decrease resistance in main circuit
4 Decrease applied emf
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