Combination of Resistors
PHXII03:CURRENT ELECTRICITY

356949 Two wires of the same metal have same length, but their cross-sections are in the ratio 3:1. They are joined in series. The resistance of thicker wire is \(10\Omega \).The total resistance of the combination will be

1 \(20\Omega \)
2 \(10\Omega \)
3 \(100\Omega \)
4 \(40\Omega \)
PHXII03:CURRENT ELECTRICITY

356950 Three resistances of one ohm each are connected in parallel. Such connection is again connected with \(\dfrac{5}{3} \Omega\) resistor in series. The resultant resistance will be

1 \(2\,\Omega \)
2 \(5\,\Omega \)
3 \(8\,\Omega \)
4 \(10\,\Omega \)
PHXII03:CURRENT ELECTRICITY

356951 A uniform wire of resistance \(R\) and length \(L\) is cut into four equal parts, each of length \(L / 4\), which are then connected in parallel combination. The effective resistance of the combination will be

1 \(R\)
2 \(4 R\)
3 \(\dfrac{R}{4}\)
4 \(\dfrac{R}{16}\)
PHXII03:CURRENT ELECTRICITY

356952 Effective resistance between \(A\) and \(B\) in the following circuit
supporting img

1 \(10\Omega \)
2 \(20\Omega \)
3 \(5\Omega \)
4 \(\frac{{20}}{3}\Omega \)
PHXII03:CURRENT ELECTRICITY

356953 The lowest resistance which can be obtained by connecting 10 resistors each of 1/10 \(ohm\) is

1 \(1/250{\kern 1pt} \Omega \)
2 \(1/200{\kern 1pt} \Omega \)
3 \(1/100{\kern 1pt} \Omega \)
4 \(1/10{\kern 1pt} \Omega \)
PHXII03:CURRENT ELECTRICITY

356949 Two wires of the same metal have same length, but their cross-sections are in the ratio 3:1. They are joined in series. The resistance of thicker wire is \(10\Omega \).The total resistance of the combination will be

1 \(20\Omega \)
2 \(10\Omega \)
3 \(100\Omega \)
4 \(40\Omega \)
PHXII03:CURRENT ELECTRICITY

356950 Three resistances of one ohm each are connected in parallel. Such connection is again connected with \(\dfrac{5}{3} \Omega\) resistor in series. The resultant resistance will be

1 \(2\,\Omega \)
2 \(5\,\Omega \)
3 \(8\,\Omega \)
4 \(10\,\Omega \)
PHXII03:CURRENT ELECTRICITY

356951 A uniform wire of resistance \(R\) and length \(L\) is cut into four equal parts, each of length \(L / 4\), which are then connected in parallel combination. The effective resistance of the combination will be

1 \(R\)
2 \(4 R\)
3 \(\dfrac{R}{4}\)
4 \(\dfrac{R}{16}\)
PHXII03:CURRENT ELECTRICITY

356952 Effective resistance between \(A\) and \(B\) in the following circuit
supporting img

1 \(10\Omega \)
2 \(20\Omega \)
3 \(5\Omega \)
4 \(\frac{{20}}{3}\Omega \)
PHXII03:CURRENT ELECTRICITY

356953 The lowest resistance which can be obtained by connecting 10 resistors each of 1/10 \(ohm\) is

1 \(1/250{\kern 1pt} \Omega \)
2 \(1/200{\kern 1pt} \Omega \)
3 \(1/100{\kern 1pt} \Omega \)
4 \(1/10{\kern 1pt} \Omega \)
PHXII03:CURRENT ELECTRICITY

356949 Two wires of the same metal have same length, but their cross-sections are in the ratio 3:1. They are joined in series. The resistance of thicker wire is \(10\Omega \).The total resistance of the combination will be

1 \(20\Omega \)
2 \(10\Omega \)
3 \(100\Omega \)
4 \(40\Omega \)
PHXII03:CURRENT ELECTRICITY

356950 Three resistances of one ohm each are connected in parallel. Such connection is again connected with \(\dfrac{5}{3} \Omega\) resistor in series. The resultant resistance will be

1 \(2\,\Omega \)
2 \(5\,\Omega \)
3 \(8\,\Omega \)
4 \(10\,\Omega \)
PHXII03:CURRENT ELECTRICITY

356951 A uniform wire of resistance \(R\) and length \(L\) is cut into four equal parts, each of length \(L / 4\), which are then connected in parallel combination. The effective resistance of the combination will be

1 \(R\)
2 \(4 R\)
3 \(\dfrac{R}{4}\)
4 \(\dfrac{R}{16}\)
PHXII03:CURRENT ELECTRICITY

356952 Effective resistance between \(A\) and \(B\) in the following circuit
supporting img

1 \(10\Omega \)
2 \(20\Omega \)
3 \(5\Omega \)
4 \(\frac{{20}}{3}\Omega \)
PHXII03:CURRENT ELECTRICITY

356953 The lowest resistance which can be obtained by connecting 10 resistors each of 1/10 \(ohm\) is

1 \(1/250{\kern 1pt} \Omega \)
2 \(1/200{\kern 1pt} \Omega \)
3 \(1/100{\kern 1pt} \Omega \)
4 \(1/10{\kern 1pt} \Omega \)
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PHXII03:CURRENT ELECTRICITY

356949 Two wires of the same metal have same length, but their cross-sections are in the ratio 3:1. They are joined in series. The resistance of thicker wire is \(10\Omega \).The total resistance of the combination will be

1 \(20\Omega \)
2 \(10\Omega \)
3 \(100\Omega \)
4 \(40\Omega \)
PHXII03:CURRENT ELECTRICITY

356950 Three resistances of one ohm each are connected in parallel. Such connection is again connected with \(\dfrac{5}{3} \Omega\) resistor in series. The resultant resistance will be

1 \(2\,\Omega \)
2 \(5\,\Omega \)
3 \(8\,\Omega \)
4 \(10\,\Omega \)
PHXII03:CURRENT ELECTRICITY

356951 A uniform wire of resistance \(R\) and length \(L\) is cut into four equal parts, each of length \(L / 4\), which are then connected in parallel combination. The effective resistance of the combination will be

1 \(R\)
2 \(4 R\)
3 \(\dfrac{R}{4}\)
4 \(\dfrac{R}{16}\)
PHXII03:CURRENT ELECTRICITY

356952 Effective resistance between \(A\) and \(B\) in the following circuit
supporting img

1 \(10\Omega \)
2 \(20\Omega \)
3 \(5\Omega \)
4 \(\frac{{20}}{3}\Omega \)
PHXII03:CURRENT ELECTRICITY

356953 The lowest resistance which can be obtained by connecting 10 resistors each of 1/10 \(ohm\) is

1 \(1/250{\kern 1pt} \Omega \)
2 \(1/200{\kern 1pt} \Omega \)
3 \(1/100{\kern 1pt} \Omega \)
4 \(1/10{\kern 1pt} \Omega \)
PHXII03:CURRENT ELECTRICITY

356949 Two wires of the same metal have same length, but their cross-sections are in the ratio 3:1. They are joined in series. The resistance of thicker wire is \(10\Omega \).The total resistance of the combination will be

1 \(20\Omega \)
2 \(10\Omega \)
3 \(100\Omega \)
4 \(40\Omega \)
PHXII03:CURRENT ELECTRICITY

356950 Three resistances of one ohm each are connected in parallel. Such connection is again connected with \(\dfrac{5}{3} \Omega\) resistor in series. The resultant resistance will be

1 \(2\,\Omega \)
2 \(5\,\Omega \)
3 \(8\,\Omega \)
4 \(10\,\Omega \)
PHXII03:CURRENT ELECTRICITY

356951 A uniform wire of resistance \(R\) and length \(L\) is cut into four equal parts, each of length \(L / 4\), which are then connected in parallel combination. The effective resistance of the combination will be

1 \(R\)
2 \(4 R\)
3 \(\dfrac{R}{4}\)
4 \(\dfrac{R}{16}\)
PHXII03:CURRENT ELECTRICITY

356952 Effective resistance between \(A\) and \(B\) in the following circuit
supporting img

1 \(10\Omega \)
2 \(20\Omega \)
3 \(5\Omega \)
4 \(\frac{{20}}{3}\Omega \)
PHXII03:CURRENT ELECTRICITY

356953 The lowest resistance which can be obtained by connecting 10 resistors each of 1/10 \(ohm\) is

1 \(1/250{\kern 1pt} \Omega \)
2 \(1/200{\kern 1pt} \Omega \)
3 \(1/100{\kern 1pt} \Omega \)
4 \(1/10{\kern 1pt} \Omega \)