356875 To get a maximum current through a resistance of \(2.5\,\Omega \), one can use m rows of cells each row having n cells. The internal resistance of each cell is \(0.5\,\Omega \). What are the values of \(m\) and \(n\), if the total number of cells are 20?

356876 A student is asked to connect four cells of emf of 1 \(V\) and internal resistance 0.5 \(ohm\) in series with an exernal resistance of 1 \(ohm\). But one cell is wrongly connected by him with its terminal reversed. Then the current in the circuit is

356877 ‘\(n\)’ identical cells, each of internal resistance (\(r\)) are first connected in parallel and then connected in series across a resistance (\(R\)). If the current through \(R\) is the same in both cases, then

356878 \(n\) identical cells, each of emf \(E\) and internal resistance \(r\), are connected in series a cell \(A\) is joined with reverse polarity. The potential difference across each cell, except \(A\) is

356879 In the network shown the potential difference between  \(A\) and \(B\)  is
$\left( \begin{array}{l}
R = {r_1} = {r_2} = {r_3} = 1\Omega ,{E_1} = 3V,\;\\
\,\,\,\,\,\,\,\,\,\,{E_2} = 2V,\;{E_3} = 1V
\end{array} \right)$

356875 To get a maximum current through a resistance of \(2.5\,\Omega \), one can use m rows of cells each row having n cells. The internal resistance of each cell is \(0.5\,\Omega \). What are the values of \(m\) and \(n\), if the total number of cells are 20?

356876 A student is asked to connect four cells of emf of 1 \(V\) and internal resistance 0.5 \(ohm\) in series with an exernal resistance of 1 \(ohm\). But one cell is wrongly connected by him with its terminal reversed. Then the current in the circuit is

356877 ‘\(n\)’ identical cells, each of internal resistance (\(r\)) are first connected in parallel and then connected in series across a resistance (\(R\)). If the current through \(R\) is the same in both cases, then

356878 \(n\) identical cells, each of emf \(E\) and internal resistance \(r\), are connected in series a cell \(A\) is joined with reverse polarity. The potential difference across each cell, except \(A\) is

356879 In the network shown the potential difference between  \(A\) and \(B\)  is
$\left( \begin{array}{l}
R = {r_1} = {r_2} = {r_3} = 1\Omega ,{E_1} = 3V,\;\\
\,\,\,\,\,\,\,\,\,\,{E_2} = 2V,\;{E_3} = 1V
\end{array} \right)$

356875 To get a maximum current through a resistance of \(2.5\,\Omega \), one can use m rows of cells each row having n cells. The internal resistance of each cell is \(0.5\,\Omega \). What are the values of \(m\) and \(n\), if the total number of cells are 20?

356876 A student is asked to connect four cells of emf of 1 \(V\) and internal resistance 0.5 \(ohm\) in series with an exernal resistance of 1 \(ohm\). But one cell is wrongly connected by him with its terminal reversed. Then the current in the circuit is

356877 ‘\(n\)’ identical cells, each of internal resistance (\(r\)) are first connected in parallel and then connected in series across a resistance (\(R\)). If the current through \(R\) is the same in both cases, then

356878 \(n\) identical cells, each of emf \(E\) and internal resistance \(r\), are connected in series a cell \(A\) is joined with reverse polarity. The potential difference across each cell, except \(A\) is

356879 In the network shown the potential difference between  \(A\) and \(B\)  is
$\left( \begin{array}{l}
R = {r_1} = {r_2} = {r_3} = 1\Omega ,{E_1} = 3V,\;\\
\,\,\,\,\,\,\,\,\,\,{E_2} = 2V,\;{E_3} = 1V
\end{array} \right)$

356875 To get a maximum current through a resistance of \(2.5\,\Omega \), one can use m rows of cells each row having n cells. The internal resistance of each cell is \(0.5\,\Omega \). What are the values of \(m\) and \(n\), if the total number of cells are 20?

356876 A student is asked to connect four cells of emf of 1 \(V\) and internal resistance 0.5 \(ohm\) in series with an exernal resistance of 1 \(ohm\). But one cell is wrongly connected by him with its terminal reversed. Then the current in the circuit is

356877 ‘\(n\)’ identical cells, each of internal resistance (\(r\)) are first connected in parallel and then connected in series across a resistance (\(R\)). If the current through \(R\) is the same in both cases, then

356878 \(n\) identical cells, each of emf \(E\) and internal resistance \(r\), are connected in series a cell \(A\) is joined with reverse polarity. The potential difference across each cell, except \(A\) is

356879 In the network shown the potential difference between  \(A\) and \(B\)  is
$\left( \begin{array}{l}
R = {r_1} = {r_2} = {r_3} = 1\Omega ,{E_1} = 3V,\;\\
\,\,\,\,\,\,\,\,\,\,{E_2} = 2V,\;{E_3} = 1V
\end{array} \right)$

356875 To get a maximum current through a resistance of \(2.5\,\Omega \), one can use m rows of cells each row having n cells. The internal resistance of each cell is \(0.5\,\Omega \). What are the values of \(m\) and \(n\), if the total number of cells are 20?

356876 A student is asked to connect four cells of emf of 1 \(V\) and internal resistance 0.5 \(ohm\) in series with an exernal resistance of 1 \(ohm\). But one cell is wrongly connected by him with its terminal reversed. Then the current in the circuit is

356877 ‘\(n\)’ identical cells, each of internal resistance (\(r\)) are first connected in parallel and then connected in series across a resistance (\(R\)). If the current through \(R\) is the same in both cases, then

356878 \(n\) identical cells, each of emf \(E\) and internal resistance \(r\), are connected in series a cell \(A\) is joined with reverse polarity. The potential difference across each cell, except \(A\) is

356879 In the network shown the potential difference between  \(A\) and \(B\)  is
$\left( \begin{array}{l}
R = {r_1} = {r_2} = {r_3} = 1\Omega ,{E_1} = 3V,\;\\
\,\,\,\,\,\,\,\,\,\,{E_2} = 2V,\;{E_3} = 1V
\end{array} \right)$