356765
The maximum peak-to-peak voltage of an \(AM\) wave is \(16mV\) and the minimum peak-to-peak voltage is \(4mV\). The modulation factor is equal to
356766
The speech signal of \(3 \mathrm{kHz}\) is used to modulate a carrier signal of frequency \(1 \mathrm{MHz}\), using amplitude modulation. The frequencies of the side bands will be
1 \(1.954MHz\) and \(2.0MHz\)
2 \(40.5MHz\) and \(27.6MHz\)
3 \(5MHz\) and \(0.997MHz\)
4 \(1.003MHz\) and \(0.997MHz\)
Explanation:
side band \(=(\omega+\Delta \omega)\) and \((\omega-\Delta \omega)\) \(\begin{aligned}& =(1+0.003) \text { and }(1-0.003) \\& =1.003 \text { and } 0.997\end{aligned}\)
NCERT Exemplar
PHXII15:COMMUNICATION SYSTEMS
356767
The physical quantities of the wave used for modulation
1 Amplitude only
2 Amplitude and frequency
3 Amplitude, frequency and phase
4 Only frequency
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356768
The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of \(14\,mV\) and \(6\,mV\) respectively is
356765
The maximum peak-to-peak voltage of an \(AM\) wave is \(16mV\) and the minimum peak-to-peak voltage is \(4mV\). The modulation factor is equal to
356766
The speech signal of \(3 \mathrm{kHz}\) is used to modulate a carrier signal of frequency \(1 \mathrm{MHz}\), using amplitude modulation. The frequencies of the side bands will be
1 \(1.954MHz\) and \(2.0MHz\)
2 \(40.5MHz\) and \(27.6MHz\)
3 \(5MHz\) and \(0.997MHz\)
4 \(1.003MHz\) and \(0.997MHz\)
Explanation:
side band \(=(\omega+\Delta \omega)\) and \((\omega-\Delta \omega)\) \(\begin{aligned}& =(1+0.003) \text { and }(1-0.003) \\& =1.003 \text { and } 0.997\end{aligned}\)
NCERT Exemplar
PHXII15:COMMUNICATION SYSTEMS
356767
The physical quantities of the wave used for modulation
1 Amplitude only
2 Amplitude and frequency
3 Amplitude, frequency and phase
4 Only frequency
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356768
The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of \(14\,mV\) and \(6\,mV\) respectively is
356765
The maximum peak-to-peak voltage of an \(AM\) wave is \(16mV\) and the minimum peak-to-peak voltage is \(4mV\). The modulation factor is equal to
356766
The speech signal of \(3 \mathrm{kHz}\) is used to modulate a carrier signal of frequency \(1 \mathrm{MHz}\), using amplitude modulation. The frequencies of the side bands will be
1 \(1.954MHz\) and \(2.0MHz\)
2 \(40.5MHz\) and \(27.6MHz\)
3 \(5MHz\) and \(0.997MHz\)
4 \(1.003MHz\) and \(0.997MHz\)
Explanation:
side band \(=(\omega+\Delta \omega)\) and \((\omega-\Delta \omega)\) \(\begin{aligned}& =(1+0.003) \text { and }(1-0.003) \\& =1.003 \text { and } 0.997\end{aligned}\)
NCERT Exemplar
PHXII15:COMMUNICATION SYSTEMS
356767
The physical quantities of the wave used for modulation
1 Amplitude only
2 Amplitude and frequency
3 Amplitude, frequency and phase
4 Only frequency
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356768
The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of \(14\,mV\) and \(6\,mV\) respectively is
356765
The maximum peak-to-peak voltage of an \(AM\) wave is \(16mV\) and the minimum peak-to-peak voltage is \(4mV\). The modulation factor is equal to
356766
The speech signal of \(3 \mathrm{kHz}\) is used to modulate a carrier signal of frequency \(1 \mathrm{MHz}\), using amplitude modulation. The frequencies of the side bands will be
1 \(1.954MHz\) and \(2.0MHz\)
2 \(40.5MHz\) and \(27.6MHz\)
3 \(5MHz\) and \(0.997MHz\)
4 \(1.003MHz\) and \(0.997MHz\)
Explanation:
side band \(=(\omega+\Delta \omega)\) and \((\omega-\Delta \omega)\) \(\begin{aligned}& =(1+0.003) \text { and }(1-0.003) \\& =1.003 \text { and } 0.997\end{aligned}\)
NCERT Exemplar
PHXII15:COMMUNICATION SYSTEMS
356767
The physical quantities of the wave used for modulation
1 Amplitude only
2 Amplitude and frequency
3 Amplitude, frequency and phase
4 Only frequency
Explanation:
Conceptual Question
PHXII15:COMMUNICATION SYSTEMS
356768
The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of \(14\,mV\) and \(6\,mV\) respectively is
