Explanation:
Since, we know, the energy of an
electron in H-like atom in \(n\)th orbit,
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{E_n} = \frac{{ - 13.6}}{{{n^2}}}{Z^2}\)
For hydrogen atom,
\({\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,{E_{{n_1}}} = \frac{{ - 13.6}}{{{n^2}}}\,\,\,\,\left( {\,\rlap{--} Z = 1} \right)\,\,\,\,\,\,\,\,\left( 1 \right)\)
For \({\text{H}}{{\text{e}}^ + }\) ion,
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{E_{{n_2}}} = \frac{{ - 13.6{{(2)}^2}}}{{{n^2}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( 2 \right)\)
From Eqs. (1) and (2), we get
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{{{E_{{n_2}}}}}{{{E_{{n_1}}}}} = {(2)^2}\)
\( \Rightarrow \,\,\,\,\,\,\,\,{E_{{n_2}}} = 4{E_{{n_1}}}\)