356485
The angular momentum of an electron in a hydrogen atom is proportional to (where \(r\) is the radius of the orbit of electron)
1 \(\dfrac{1}{\sqrt{r}}\)
2 \(\dfrac{1}{r}\)
3 \(\sqrt{r}\)
4 \(r\)
Explanation:
Angular momentum of an electron in a hydrogen atom. \(L=\dfrac{n h}{2 \pi}\) \( \Rightarrow L \propto n \propto \sqrt r \left( {\because r \propto {n^2} \Rightarrow n \propto \sqrt r } \right)\quad \quad (1)\)
JEE - 2024
PHXII12:ATOMS
356486
The energy of hydrogen atom in ground state is \(13.6\,eV\) The ionisation energy of singly ionised helium \(H{e^{2 + }}\) will be
1 \(13.6\,eV\)
2 \(3.4\,eV\)
3 \(27.2\,eV\)
4 \(54.4\,eV\)
Explanation:
Energy of ionised \(H{e^{2 + }}\), \(E = \left( {{E_0}} \right){Z^2} = (13.6)(4) = 54.4\,eV\)
AIIMS - 2009
PHXII12:ATOMS
356487
Read the Statement - A and Statement - B carefully to mark correct options given below Statement A : Atoms are electrically neutral as they contain equal number of positive and negative charges. Statement B : Atoms of each element are stable and emit their characteristic spectrum.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is true as atoms are electrically neutral because they contain equal number of positive and negative charges. Statement B is wrong as atom of some of the elements are stable and emit characteristic spectrum. But this statement is not true for every atom. Correct option is (1).
NEET - 2024
PHXII12:ATOMS
356488
If the speed of an electron of hydrogen atom in the ground state is \(2.2 \times {10^6}m/s\), then its speed in the third excited state will be
1 \(5.5 \times {10^6}m/s\)
2 \(5.5 \times {10^5}m/s\)
3 \(8.8 \times {10^5}m/s\)
4 \(6.8 \times {10^6}m/s\)
Explanation:
Speed of electron of hydrogen atom in ground state, \({v_1} = 2.2 \times {10^6}m/s\) Since,\(v \propto \frac{1}{n}\) \(\therefore \frac{{{v_1}}}{{{v_2}}} = \frac{{{n_1}}}{{{n_2}}} = \frac{{2.2 \times {{10}^6}}}{{{v_2}}}\) [ for third excited state,\({n_2} = 4\) ] \( \Rightarrow {v_2} = \frac{{2.2 \times {{10}^6}}}{4} = 0.55 \times {10^6}m/s\) \( = 5.5 \times {10^5}m/s\)
MHTCET - 2019
PHXII12:ATOMS
356489
The electron in hydrogen atom jumps from \({1^{st}}\) orbit to the \({5^{th}}\) orbit. Change in angular momentum of electron is
1 \(\frac{{2h}}{\pi }\)
2 \(\frac{{3h}}{{2\pi }}\)
3 \(\frac{h}{\pi }\)
4 \(\frac{h}{{2\pi }}\)
Explanation:
Angular momentum of electron is \(L = \frac{{nh}}{{2\pi }}\) change in \(L\) is \(\Delta L = \frac{{5h}}{{2\pi }} - \frac{h}{{2\pi }} = \frac{{2h}}{\pi }\)
356485
The angular momentum of an electron in a hydrogen atom is proportional to (where \(r\) is the radius of the orbit of electron)
1 \(\dfrac{1}{\sqrt{r}}\)
2 \(\dfrac{1}{r}\)
3 \(\sqrt{r}\)
4 \(r\)
Explanation:
Angular momentum of an electron in a hydrogen atom. \(L=\dfrac{n h}{2 \pi}\) \( \Rightarrow L \propto n \propto \sqrt r \left( {\because r \propto {n^2} \Rightarrow n \propto \sqrt r } \right)\quad \quad (1)\)
JEE - 2024
PHXII12:ATOMS
356486
The energy of hydrogen atom in ground state is \(13.6\,eV\) The ionisation energy of singly ionised helium \(H{e^{2 + }}\) will be
1 \(13.6\,eV\)
2 \(3.4\,eV\)
3 \(27.2\,eV\)
4 \(54.4\,eV\)
Explanation:
Energy of ionised \(H{e^{2 + }}\), \(E = \left( {{E_0}} \right){Z^2} = (13.6)(4) = 54.4\,eV\)
AIIMS - 2009
PHXII12:ATOMS
356487
Read the Statement - A and Statement - B carefully to mark correct options given below Statement A : Atoms are electrically neutral as they contain equal number of positive and negative charges. Statement B : Atoms of each element are stable and emit their characteristic spectrum.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is true as atoms are electrically neutral because they contain equal number of positive and negative charges. Statement B is wrong as atom of some of the elements are stable and emit characteristic spectrum. But this statement is not true for every atom. Correct option is (1).
NEET - 2024
PHXII12:ATOMS
356488
If the speed of an electron of hydrogen atom in the ground state is \(2.2 \times {10^6}m/s\), then its speed in the third excited state will be
1 \(5.5 \times {10^6}m/s\)
2 \(5.5 \times {10^5}m/s\)
3 \(8.8 \times {10^5}m/s\)
4 \(6.8 \times {10^6}m/s\)
Explanation:
Speed of electron of hydrogen atom in ground state, \({v_1} = 2.2 \times {10^6}m/s\) Since,\(v \propto \frac{1}{n}\) \(\therefore \frac{{{v_1}}}{{{v_2}}} = \frac{{{n_1}}}{{{n_2}}} = \frac{{2.2 \times {{10}^6}}}{{{v_2}}}\) [ for third excited state,\({n_2} = 4\) ] \( \Rightarrow {v_2} = \frac{{2.2 \times {{10}^6}}}{4} = 0.55 \times {10^6}m/s\) \( = 5.5 \times {10^5}m/s\)
MHTCET - 2019
PHXII12:ATOMS
356489
The electron in hydrogen atom jumps from \({1^{st}}\) orbit to the \({5^{th}}\) orbit. Change in angular momentum of electron is
1 \(\frac{{2h}}{\pi }\)
2 \(\frac{{3h}}{{2\pi }}\)
3 \(\frac{h}{\pi }\)
4 \(\frac{h}{{2\pi }}\)
Explanation:
Angular momentum of electron is \(L = \frac{{nh}}{{2\pi }}\) change in \(L\) is \(\Delta L = \frac{{5h}}{{2\pi }} - \frac{h}{{2\pi }} = \frac{{2h}}{\pi }\)
356485
The angular momentum of an electron in a hydrogen atom is proportional to (where \(r\) is the radius of the orbit of electron)
1 \(\dfrac{1}{\sqrt{r}}\)
2 \(\dfrac{1}{r}\)
3 \(\sqrt{r}\)
4 \(r\)
Explanation:
Angular momentum of an electron in a hydrogen atom. \(L=\dfrac{n h}{2 \pi}\) \( \Rightarrow L \propto n \propto \sqrt r \left( {\because r \propto {n^2} \Rightarrow n \propto \sqrt r } \right)\quad \quad (1)\)
JEE - 2024
PHXII12:ATOMS
356486
The energy of hydrogen atom in ground state is \(13.6\,eV\) The ionisation energy of singly ionised helium \(H{e^{2 + }}\) will be
1 \(13.6\,eV\)
2 \(3.4\,eV\)
3 \(27.2\,eV\)
4 \(54.4\,eV\)
Explanation:
Energy of ionised \(H{e^{2 + }}\), \(E = \left( {{E_0}} \right){Z^2} = (13.6)(4) = 54.4\,eV\)
AIIMS - 2009
PHXII12:ATOMS
356487
Read the Statement - A and Statement - B carefully to mark correct options given below Statement A : Atoms are electrically neutral as they contain equal number of positive and negative charges. Statement B : Atoms of each element are stable and emit their characteristic spectrum.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is true as atoms are electrically neutral because they contain equal number of positive and negative charges. Statement B is wrong as atom of some of the elements are stable and emit characteristic spectrum. But this statement is not true for every atom. Correct option is (1).
NEET - 2024
PHXII12:ATOMS
356488
If the speed of an electron of hydrogen atom in the ground state is \(2.2 \times {10^6}m/s\), then its speed in the third excited state will be
1 \(5.5 \times {10^6}m/s\)
2 \(5.5 \times {10^5}m/s\)
3 \(8.8 \times {10^5}m/s\)
4 \(6.8 \times {10^6}m/s\)
Explanation:
Speed of electron of hydrogen atom in ground state, \({v_1} = 2.2 \times {10^6}m/s\) Since,\(v \propto \frac{1}{n}\) \(\therefore \frac{{{v_1}}}{{{v_2}}} = \frac{{{n_1}}}{{{n_2}}} = \frac{{2.2 \times {{10}^6}}}{{{v_2}}}\) [ for third excited state,\({n_2} = 4\) ] \( \Rightarrow {v_2} = \frac{{2.2 \times {{10}^6}}}{4} = 0.55 \times {10^6}m/s\) \( = 5.5 \times {10^5}m/s\)
MHTCET - 2019
PHXII12:ATOMS
356489
The electron in hydrogen atom jumps from \({1^{st}}\) orbit to the \({5^{th}}\) orbit. Change in angular momentum of electron is
1 \(\frac{{2h}}{\pi }\)
2 \(\frac{{3h}}{{2\pi }}\)
3 \(\frac{h}{\pi }\)
4 \(\frac{h}{{2\pi }}\)
Explanation:
Angular momentum of electron is \(L = \frac{{nh}}{{2\pi }}\) change in \(L\) is \(\Delta L = \frac{{5h}}{{2\pi }} - \frac{h}{{2\pi }} = \frac{{2h}}{\pi }\)
356485
The angular momentum of an electron in a hydrogen atom is proportional to (where \(r\) is the radius of the orbit of electron)
1 \(\dfrac{1}{\sqrt{r}}\)
2 \(\dfrac{1}{r}\)
3 \(\sqrt{r}\)
4 \(r\)
Explanation:
Angular momentum of an electron in a hydrogen atom. \(L=\dfrac{n h}{2 \pi}\) \( \Rightarrow L \propto n \propto \sqrt r \left( {\because r \propto {n^2} \Rightarrow n \propto \sqrt r } \right)\quad \quad (1)\)
JEE - 2024
PHXII12:ATOMS
356486
The energy of hydrogen atom in ground state is \(13.6\,eV\) The ionisation energy of singly ionised helium \(H{e^{2 + }}\) will be
1 \(13.6\,eV\)
2 \(3.4\,eV\)
3 \(27.2\,eV\)
4 \(54.4\,eV\)
Explanation:
Energy of ionised \(H{e^{2 + }}\), \(E = \left( {{E_0}} \right){Z^2} = (13.6)(4) = 54.4\,eV\)
AIIMS - 2009
PHXII12:ATOMS
356487
Read the Statement - A and Statement - B carefully to mark correct options given below Statement A : Atoms are electrically neutral as they contain equal number of positive and negative charges. Statement B : Atoms of each element are stable and emit their characteristic spectrum.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is true as atoms are electrically neutral because they contain equal number of positive and negative charges. Statement B is wrong as atom of some of the elements are stable and emit characteristic spectrum. But this statement is not true for every atom. Correct option is (1).
NEET - 2024
PHXII12:ATOMS
356488
If the speed of an electron of hydrogen atom in the ground state is \(2.2 \times {10^6}m/s\), then its speed in the third excited state will be
1 \(5.5 \times {10^6}m/s\)
2 \(5.5 \times {10^5}m/s\)
3 \(8.8 \times {10^5}m/s\)
4 \(6.8 \times {10^6}m/s\)
Explanation:
Speed of electron of hydrogen atom in ground state, \({v_1} = 2.2 \times {10^6}m/s\) Since,\(v \propto \frac{1}{n}\) \(\therefore \frac{{{v_1}}}{{{v_2}}} = \frac{{{n_1}}}{{{n_2}}} = \frac{{2.2 \times {{10}^6}}}{{{v_2}}}\) [ for third excited state,\({n_2} = 4\) ] \( \Rightarrow {v_2} = \frac{{2.2 \times {{10}^6}}}{4} = 0.55 \times {10^6}m/s\) \( = 5.5 \times {10^5}m/s\)
MHTCET - 2019
PHXII12:ATOMS
356489
The electron in hydrogen atom jumps from \({1^{st}}\) orbit to the \({5^{th}}\) orbit. Change in angular momentum of electron is
1 \(\frac{{2h}}{\pi }\)
2 \(\frac{{3h}}{{2\pi }}\)
3 \(\frac{h}{\pi }\)
4 \(\frac{h}{{2\pi }}\)
Explanation:
Angular momentum of electron is \(L = \frac{{nh}}{{2\pi }}\) change in \(L\) is \(\Delta L = \frac{{5h}}{{2\pi }} - \frac{h}{{2\pi }} = \frac{{2h}}{\pi }\)
356485
The angular momentum of an electron in a hydrogen atom is proportional to (where \(r\) is the radius of the orbit of electron)
1 \(\dfrac{1}{\sqrt{r}}\)
2 \(\dfrac{1}{r}\)
3 \(\sqrt{r}\)
4 \(r\)
Explanation:
Angular momentum of an electron in a hydrogen atom. \(L=\dfrac{n h}{2 \pi}\) \( \Rightarrow L \propto n \propto \sqrt r \left( {\because r \propto {n^2} \Rightarrow n \propto \sqrt r } \right)\quad \quad (1)\)
JEE - 2024
PHXII12:ATOMS
356486
The energy of hydrogen atom in ground state is \(13.6\,eV\) The ionisation energy of singly ionised helium \(H{e^{2 + }}\) will be
1 \(13.6\,eV\)
2 \(3.4\,eV\)
3 \(27.2\,eV\)
4 \(54.4\,eV\)
Explanation:
Energy of ionised \(H{e^{2 + }}\), \(E = \left( {{E_0}} \right){Z^2} = (13.6)(4) = 54.4\,eV\)
AIIMS - 2009
PHXII12:ATOMS
356487
Read the Statement - A and Statement - B carefully to mark correct options given below Statement A : Atoms are electrically neutral as they contain equal number of positive and negative charges. Statement B : Atoms of each element are stable and emit their characteristic spectrum.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is true as atoms are electrically neutral because they contain equal number of positive and negative charges. Statement B is wrong as atom of some of the elements are stable and emit characteristic spectrum. But this statement is not true for every atom. Correct option is (1).
NEET - 2024
PHXII12:ATOMS
356488
If the speed of an electron of hydrogen atom in the ground state is \(2.2 \times {10^6}m/s\), then its speed in the third excited state will be
1 \(5.5 \times {10^6}m/s\)
2 \(5.5 \times {10^5}m/s\)
3 \(8.8 \times {10^5}m/s\)
4 \(6.8 \times {10^6}m/s\)
Explanation:
Speed of electron of hydrogen atom in ground state, \({v_1} = 2.2 \times {10^6}m/s\) Since,\(v \propto \frac{1}{n}\) \(\therefore \frac{{{v_1}}}{{{v_2}}} = \frac{{{n_1}}}{{{n_2}}} = \frac{{2.2 \times {{10}^6}}}{{{v_2}}}\) [ for third excited state,\({n_2} = 4\) ] \( \Rightarrow {v_2} = \frac{{2.2 \times {{10}^6}}}{4} = 0.55 \times {10^6}m/s\) \( = 5.5 \times {10^5}m/s\)
MHTCET - 2019
PHXII12:ATOMS
356489
The electron in hydrogen atom jumps from \({1^{st}}\) orbit to the \({5^{th}}\) orbit. Change in angular momentum of electron is
1 \(\frac{{2h}}{\pi }\)
2 \(\frac{{3h}}{{2\pi }}\)
3 \(\frac{h}{\pi }\)
4 \(\frac{h}{{2\pi }}\)
Explanation:
Angular momentum of electron is \(L = \frac{{nh}}{{2\pi }}\) change in \(L\) is \(\Delta L = \frac{{5h}}{{2\pi }} - \frac{h}{{2\pi }} = \frac{{2h}}{\pi }\)
