Bohr Model of the Hydrogen Atom
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PHXII12:ATOMS

356387 Assuming the atom is in the ground state, the expression for the magnetic field at a point nucleus in hydrogen atom due to circular motion of elecrton is
[ \(\mu_{0} \rightarrow\) permeability of free space,
\(m \rightarrow\) mass of electrons]
\(\left[\epsilon_{0} \rightarrow\right.\) permittivity of free space,
\(h \rightarrow\) planck's constant]

1 \(\dfrac{\mu_{0} e^{3} \pi m^{2}}{8 \varepsilon_{0}{ }^{2} h^{4}}\)
2 \(\dfrac{\mu_{0} e^{2} \pi m^{4}}{6 \varepsilon_{0}{ }^{3} h^{4}}\)
3 \(\dfrac{\mu_{0} e^{7} \pi m^{2}}{8 \varepsilon_{0}{ }^{3} h^{5}}\)
4 \(\dfrac{\mu_{0} e^{3} \pi m^{3}}{6 \varepsilon_{0}{ }^{3} h^{3}}\)
MHTCET - 2022
PHXII12:ATOMS

356388 As the electron in Bohr's orbit of hydrogen atom passes from state \(n=2\) to \(n=1\), the kinetic energy \((K)\) and the potential energy \((U)\) changes as

1 \(K\) four fold, \(U\) also four fold
2 \(K\) two fold, \(U\) also two fold
3 \(K\) four fold, \(U\) two fold
4 \(K\) two fold, \(U\) four fold
PHXII12:ATOMS

356389 The ionization potential of a hydrogen atom is 13.6 \(eV\) . What will be the energy of electron in the second orbit?

1 10.02 \(eV\)
2 \( - 3.40\,eV\)
3 1.51 \(eV\)
4 \( - 0.85\,eV\)
PHXII12:ATOMS

356390 The ground state energy of hydrogen atom is \( - 13.6eV\). The kinetic energy of the electron in this state is:

1 \(1.85\,eV\)
2 \(13.6\,eV\)
3 \(6.8\,eV\)
4 \(3.4\,eV\)
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PHXII12:ATOMS

356387 Assuming the atom is in the ground state, the expression for the magnetic field at a point nucleus in hydrogen atom due to circular motion of elecrton is
[ \(\mu_{0} \rightarrow\) permeability of free space,
\(m \rightarrow\) mass of electrons]
\(\left[\epsilon_{0} \rightarrow\right.\) permittivity of free space,
\(h \rightarrow\) planck's constant]

1 \(\dfrac{\mu_{0} e^{3} \pi m^{2}}{8 \varepsilon_{0}{ }^{2} h^{4}}\)
2 \(\dfrac{\mu_{0} e^{2} \pi m^{4}}{6 \varepsilon_{0}{ }^{3} h^{4}}\)
3 \(\dfrac{\mu_{0} e^{7} \pi m^{2}}{8 \varepsilon_{0}{ }^{3} h^{5}}\)
4 \(\dfrac{\mu_{0} e^{3} \pi m^{3}}{6 \varepsilon_{0}{ }^{3} h^{3}}\)
MHTCET - 2022
PHXII12:ATOMS

356388 As the electron in Bohr's orbit of hydrogen atom passes from state \(n=2\) to \(n=1\), the kinetic energy \((K)\) and the potential energy \((U)\) changes as

1 \(K\) four fold, \(U\) also four fold
2 \(K\) two fold, \(U\) also two fold
3 \(K\) four fold, \(U\) two fold
4 \(K\) two fold, \(U\) four fold
PHXII12:ATOMS

356389 The ionization potential of a hydrogen atom is 13.6 \(eV\) . What will be the energy of electron in the second orbit?

1 10.02 \(eV\)
2 \( - 3.40\,eV\)
3 1.51 \(eV\)
4 \( - 0.85\,eV\)
PHXII12:ATOMS

356390 The ground state energy of hydrogen atom is \( - 13.6eV\). The kinetic energy of the electron in this state is:

1 \(1.85\,eV\)
2 \(13.6\,eV\)
3 \(6.8\,eV\)
4 \(3.4\,eV\)
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PHXII12:ATOMS

356387 Assuming the atom is in the ground state, the expression for the magnetic field at a point nucleus in hydrogen atom due to circular motion of elecrton is
[ \(\mu_{0} \rightarrow\) permeability of free space,
\(m \rightarrow\) mass of electrons]
\(\left[\epsilon_{0} \rightarrow\right.\) permittivity of free space,
\(h \rightarrow\) planck's constant]

1 \(\dfrac{\mu_{0} e^{3} \pi m^{2}}{8 \varepsilon_{0}{ }^{2} h^{4}}\)
2 \(\dfrac{\mu_{0} e^{2} \pi m^{4}}{6 \varepsilon_{0}{ }^{3} h^{4}}\)
3 \(\dfrac{\mu_{0} e^{7} \pi m^{2}}{8 \varepsilon_{0}{ }^{3} h^{5}}\)
4 \(\dfrac{\mu_{0} e^{3} \pi m^{3}}{6 \varepsilon_{0}{ }^{3} h^{3}}\)
MHTCET - 2022
PHXII12:ATOMS

356388 As the electron in Bohr's orbit of hydrogen atom passes from state \(n=2\) to \(n=1\), the kinetic energy \((K)\) and the potential energy \((U)\) changes as

1 \(K\) four fold, \(U\) also four fold
2 \(K\) two fold, \(U\) also two fold
3 \(K\) four fold, \(U\) two fold
4 \(K\) two fold, \(U\) four fold
PHXII12:ATOMS

356389 The ionization potential of a hydrogen atom is 13.6 \(eV\) . What will be the energy of electron in the second orbit?

1 10.02 \(eV\)
2 \( - 3.40\,eV\)
3 1.51 \(eV\)
4 \( - 0.85\,eV\)
PHXII12:ATOMS

356390 The ground state energy of hydrogen atom is \( - 13.6eV\). The kinetic energy of the electron in this state is:

1 \(1.85\,eV\)
2 \(13.6\,eV\)
3 \(6.8\,eV\)
4 \(3.4\,eV\)
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PHXII12:ATOMS

356387 Assuming the atom is in the ground state, the expression for the magnetic field at a point nucleus in hydrogen atom due to circular motion of elecrton is
[ \(\mu_{0} \rightarrow\) permeability of free space,
\(m \rightarrow\) mass of electrons]
\(\left[\epsilon_{0} \rightarrow\right.\) permittivity of free space,
\(h \rightarrow\) planck's constant]

1 \(\dfrac{\mu_{0} e^{3} \pi m^{2}}{8 \varepsilon_{0}{ }^{2} h^{4}}\)
2 \(\dfrac{\mu_{0} e^{2} \pi m^{4}}{6 \varepsilon_{0}{ }^{3} h^{4}}\)
3 \(\dfrac{\mu_{0} e^{7} \pi m^{2}}{8 \varepsilon_{0}{ }^{3} h^{5}}\)
4 \(\dfrac{\mu_{0} e^{3} \pi m^{3}}{6 \varepsilon_{0}{ }^{3} h^{3}}\)
MHTCET - 2022
PHXII12:ATOMS

356388 As the electron in Bohr's orbit of hydrogen atom passes from state \(n=2\) to \(n=1\), the kinetic energy \((K)\) and the potential energy \((U)\) changes as

1 \(K\) four fold, \(U\) also four fold
2 \(K\) two fold, \(U\) also two fold
3 \(K\) four fold, \(U\) two fold
4 \(K\) two fold, \(U\) four fold
PHXII12:ATOMS

356389 The ionization potential of a hydrogen atom is 13.6 \(eV\) . What will be the energy of electron in the second orbit?

1 10.02 \(eV\)
2 \( - 3.40\,eV\)
3 1.51 \(eV\)
4 \( - 0.85\,eV\)
PHXII12:ATOMS

356390 The ground state energy of hydrogen atom is \( - 13.6eV\). The kinetic energy of the electron in this state is:

1 \(1.85\,eV\)
2 \(13.6\,eV\)
3 \(6.8\,eV\)
4 \(3.4\,eV\)
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