356431
The ratio of magnetic dipole moment to angular momentum in a hydrogen atom is
1 \(\frac{e}{m}\)
2 \(\frac{e}{{2m}}\)
3 \(\frac{e}{{3m}}\)
4 \(\frac{{2e}}{m}\)
Explanation:
Magnetic moment \(\mu = iA = \frac{q}{T}\pi {r^2} = \frac{{q\omega {r^2}}}{2}\) Angular momentum \(L = m{r^2}\omega \) \(\frac{\mu }{L} = \frac{q}{{2m}} = \frac{e}{{2m}}\)
PHXII12:ATOMS
356432
Let the \(PE\) of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be
1 \(23.8\,eV\)
2 \(27.2\,eV\)
3 \(10.2\,eV\)
4 \(12.6\,eV\)
Explanation:
When the \(P\).\(E\) is taken as zero (Old-Frame) at infinity then the values of \(P\).\(E\), \(K\).\(E\) & \(T\).\(E\) for \(H\)-atom are shown as follows \(P.E = 2T.E\,\& K.E = - T.E\) \({\rm{T}}{\rm{.E}} = \frac{{ - 13.6eV}}{{{n^2}}}\) The above relations between \(P\).\(E\), \(T\).\(E\) & \(K\).\(E\) are not valid in the new frame. Note: If we change the reference point for \(P\).\(E\) then the absolute \(K\).\(E\) and difference in \(T\).\(E\) must remain same.
PHXII12:ATOMS
356433
Statement A : The total energy of an electron revolving in any stationary orbit is negative. Statement B : Kinetic energy of revolving electron can be \(( - ve)\) also.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Energy can have positive or negative values. In the atom the electrons are bound. The negative energy of the revolving electrons does not allow the electrons to leave the atom. Kinetic energy of the electron is always \(( + )ve\). So option (1) is correct.
356431
The ratio of magnetic dipole moment to angular momentum in a hydrogen atom is
1 \(\frac{e}{m}\)
2 \(\frac{e}{{2m}}\)
3 \(\frac{e}{{3m}}\)
4 \(\frac{{2e}}{m}\)
Explanation:
Magnetic moment \(\mu = iA = \frac{q}{T}\pi {r^2} = \frac{{q\omega {r^2}}}{2}\) Angular momentum \(L = m{r^2}\omega \) \(\frac{\mu }{L} = \frac{q}{{2m}} = \frac{e}{{2m}}\)
PHXII12:ATOMS
356432
Let the \(PE\) of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be
1 \(23.8\,eV\)
2 \(27.2\,eV\)
3 \(10.2\,eV\)
4 \(12.6\,eV\)
Explanation:
When the \(P\).\(E\) is taken as zero (Old-Frame) at infinity then the values of \(P\).\(E\), \(K\).\(E\) & \(T\).\(E\) for \(H\)-atom are shown as follows \(P.E = 2T.E\,\& K.E = - T.E\) \({\rm{T}}{\rm{.E}} = \frac{{ - 13.6eV}}{{{n^2}}}\) The above relations between \(P\).\(E\), \(T\).\(E\) & \(K\).\(E\) are not valid in the new frame. Note: If we change the reference point for \(P\).\(E\) then the absolute \(K\).\(E\) and difference in \(T\).\(E\) must remain same.
PHXII12:ATOMS
356433
Statement A : The total energy of an electron revolving in any stationary orbit is negative. Statement B : Kinetic energy of revolving electron can be \(( - ve)\) also.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Energy can have positive or negative values. In the atom the electrons are bound. The negative energy of the revolving electrons does not allow the electrons to leave the atom. Kinetic energy of the electron is always \(( + )ve\). So option (1) is correct.
356431
The ratio of magnetic dipole moment to angular momentum in a hydrogen atom is
1 \(\frac{e}{m}\)
2 \(\frac{e}{{2m}}\)
3 \(\frac{e}{{3m}}\)
4 \(\frac{{2e}}{m}\)
Explanation:
Magnetic moment \(\mu = iA = \frac{q}{T}\pi {r^2} = \frac{{q\omega {r^2}}}{2}\) Angular momentum \(L = m{r^2}\omega \) \(\frac{\mu }{L} = \frac{q}{{2m}} = \frac{e}{{2m}}\)
PHXII12:ATOMS
356432
Let the \(PE\) of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be
1 \(23.8\,eV\)
2 \(27.2\,eV\)
3 \(10.2\,eV\)
4 \(12.6\,eV\)
Explanation:
When the \(P\).\(E\) is taken as zero (Old-Frame) at infinity then the values of \(P\).\(E\), \(K\).\(E\) & \(T\).\(E\) for \(H\)-atom are shown as follows \(P.E = 2T.E\,\& K.E = - T.E\) \({\rm{T}}{\rm{.E}} = \frac{{ - 13.6eV}}{{{n^2}}}\) The above relations between \(P\).\(E\), \(T\).\(E\) & \(K\).\(E\) are not valid in the new frame. Note: If we change the reference point for \(P\).\(E\) then the absolute \(K\).\(E\) and difference in \(T\).\(E\) must remain same.
PHXII12:ATOMS
356433
Statement A : The total energy of an electron revolving in any stationary orbit is negative. Statement B : Kinetic energy of revolving electron can be \(( - ve)\) also.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Energy can have positive or negative values. In the atom the electrons are bound. The negative energy of the revolving electrons does not allow the electrons to leave the atom. Kinetic energy of the electron is always \(( + )ve\). So option (1) is correct.
356431
The ratio of magnetic dipole moment to angular momentum in a hydrogen atom is
1 \(\frac{e}{m}\)
2 \(\frac{e}{{2m}}\)
3 \(\frac{e}{{3m}}\)
4 \(\frac{{2e}}{m}\)
Explanation:
Magnetic moment \(\mu = iA = \frac{q}{T}\pi {r^2} = \frac{{q\omega {r^2}}}{2}\) Angular momentum \(L = m{r^2}\omega \) \(\frac{\mu }{L} = \frac{q}{{2m}} = \frac{e}{{2m}}\)
PHXII12:ATOMS
356432
Let the \(PE\) of hydrogen atom in the ground state be zero. Then its total energy in the first excited state will be
1 \(23.8\,eV\)
2 \(27.2\,eV\)
3 \(10.2\,eV\)
4 \(12.6\,eV\)
Explanation:
When the \(P\).\(E\) is taken as zero (Old-Frame) at infinity then the values of \(P\).\(E\), \(K\).\(E\) & \(T\).\(E\) for \(H\)-atom are shown as follows \(P.E = 2T.E\,\& K.E = - T.E\) \({\rm{T}}{\rm{.E}} = \frac{{ - 13.6eV}}{{{n^2}}}\) The above relations between \(P\).\(E\), \(T\).\(E\) & \(K\).\(E\) are not valid in the new frame. Note: If we change the reference point for \(P\).\(E\) then the absolute \(K\).\(E\) and difference in \(T\).\(E\) must remain same.
PHXII12:ATOMS
356433
Statement A : The total energy of an electron revolving in any stationary orbit is negative. Statement B : Kinetic energy of revolving electron can be \(( - ve)\) also.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Energy can have positive or negative values. In the atom the electrons are bound. The negative energy of the revolving electrons does not allow the electrons to leave the atom. Kinetic energy of the electron is always \(( + )ve\). So option (1) is correct.
