NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII07:ALTERNATING CURRENT
356317
An ideal transformer has a turns ratio of 10 , when the primary is connected to \(220\;V,50\;Hz\,ac\) source, the power output is
1 equal to power input
2 zero
3 10 times the power input
4 \(\dfrac{1}{10}^{\text {th }}\) the power input
Explanation:
Transformer is stated to be ideal. \(\Rightarrow\) Power constant. \(P_{\text {in }}=P_{\text {out }}\). Correct option is (1).
KECT - 2023
PHXII07:ALTERNATING CURRENT
356318
The coefficient of mutual inductance between the primary and secondary coils of transformer is 5 \(H\). A current of 10 \(A\) is cut-off in 0.5 \(s\). The induced \(emf\) is
1 \(10\,V\)
2 \(1\,V\)
3 \(100\,V\)
4 \(5\,V\)
Explanation:
From Faraday’s law of electromagnetic induction, the induced emf is given by \(\varepsilon = - M\frac{{di}}{{dt}}\) Given,\(M = 5H,di = 10A,dt = 0.5\,s\) \(\therefore \varepsilon = - 5 \times \frac{{10}}{{0.5}} = - 100V\)
PHXII07:ALTERNATING CURRENT
356319
For an ideal transformer ratio of output to the input power is always
1 Greater than one
2 Equal to one
3 Less than one
4 Zero
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
356320
In a step-up transformer, the ratio of turns of the primary and the secondary is \({1: 25}\). If the input voltage is \(230\,V\) and the current through the load is \({2 A}\), then the current in the primary coil is
356317
An ideal transformer has a turns ratio of 10 , when the primary is connected to \(220\;V,50\;Hz\,ac\) source, the power output is
1 equal to power input
2 zero
3 10 times the power input
4 \(\dfrac{1}{10}^{\text {th }}\) the power input
Explanation:
Transformer is stated to be ideal. \(\Rightarrow\) Power constant. \(P_{\text {in }}=P_{\text {out }}\). Correct option is (1).
KECT - 2023
PHXII07:ALTERNATING CURRENT
356318
The coefficient of mutual inductance between the primary and secondary coils of transformer is 5 \(H\). A current of 10 \(A\) is cut-off in 0.5 \(s\). The induced \(emf\) is
1 \(10\,V\)
2 \(1\,V\)
3 \(100\,V\)
4 \(5\,V\)
Explanation:
From Faraday’s law of electromagnetic induction, the induced emf is given by \(\varepsilon = - M\frac{{di}}{{dt}}\) Given,\(M = 5H,di = 10A,dt = 0.5\,s\) \(\therefore \varepsilon = - 5 \times \frac{{10}}{{0.5}} = - 100V\)
PHXII07:ALTERNATING CURRENT
356319
For an ideal transformer ratio of output to the input power is always
1 Greater than one
2 Equal to one
3 Less than one
4 Zero
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
356320
In a step-up transformer, the ratio of turns of the primary and the secondary is \({1: 25}\). If the input voltage is \(230\,V\) and the current through the load is \({2 A}\), then the current in the primary coil is
356317
An ideal transformer has a turns ratio of 10 , when the primary is connected to \(220\;V,50\;Hz\,ac\) source, the power output is
1 equal to power input
2 zero
3 10 times the power input
4 \(\dfrac{1}{10}^{\text {th }}\) the power input
Explanation:
Transformer is stated to be ideal. \(\Rightarrow\) Power constant. \(P_{\text {in }}=P_{\text {out }}\). Correct option is (1).
KECT - 2023
PHXII07:ALTERNATING CURRENT
356318
The coefficient of mutual inductance between the primary and secondary coils of transformer is 5 \(H\). A current of 10 \(A\) is cut-off in 0.5 \(s\). The induced \(emf\) is
1 \(10\,V\)
2 \(1\,V\)
3 \(100\,V\)
4 \(5\,V\)
Explanation:
From Faraday’s law of electromagnetic induction, the induced emf is given by \(\varepsilon = - M\frac{{di}}{{dt}}\) Given,\(M = 5H,di = 10A,dt = 0.5\,s\) \(\therefore \varepsilon = - 5 \times \frac{{10}}{{0.5}} = - 100V\)
PHXII07:ALTERNATING CURRENT
356319
For an ideal transformer ratio of output to the input power is always
1 Greater than one
2 Equal to one
3 Less than one
4 Zero
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
356320
In a step-up transformer, the ratio of turns of the primary and the secondary is \({1: 25}\). If the input voltage is \(230\,V\) and the current through the load is \({2 A}\), then the current in the primary coil is
356317
An ideal transformer has a turns ratio of 10 , when the primary is connected to \(220\;V,50\;Hz\,ac\) source, the power output is
1 equal to power input
2 zero
3 10 times the power input
4 \(\dfrac{1}{10}^{\text {th }}\) the power input
Explanation:
Transformer is stated to be ideal. \(\Rightarrow\) Power constant. \(P_{\text {in }}=P_{\text {out }}\). Correct option is (1).
KECT - 2023
PHXII07:ALTERNATING CURRENT
356318
The coefficient of mutual inductance between the primary and secondary coils of transformer is 5 \(H\). A current of 10 \(A\) is cut-off in 0.5 \(s\). The induced \(emf\) is
1 \(10\,V\)
2 \(1\,V\)
3 \(100\,V\)
4 \(5\,V\)
Explanation:
From Faraday’s law of electromagnetic induction, the induced emf is given by \(\varepsilon = - M\frac{{di}}{{dt}}\) Given,\(M = 5H,di = 10A,dt = 0.5\,s\) \(\therefore \varepsilon = - 5 \times \frac{{10}}{{0.5}} = - 100V\)
PHXII07:ALTERNATING CURRENT
356319
For an ideal transformer ratio of output to the input power is always
1 Greater than one
2 Equal to one
3 Less than one
4 Zero
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
356320
In a step-up transformer, the ratio of turns of the primary and the secondary is \({1: 25}\). If the input voltage is \(230\,V\) and the current through the load is \({2 A}\), then the current in the primary coil is
