355993
In an \(A.C\) circuit having resistance and capacitance
1 Emf leads the current
2 Current lags behind the emf
3 Both the current and emf are in phase
4 Current leads the emf
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
355994
Assertion : Given circuit: Then \({V_C}\) in the circuit \( = 2\,V\) Reason : Kirchoff voltage law rule can be applied to AC circuits also.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Reason is true as kirchoffs voltage law \((K V L)\) is fundamentally for conservation of electrical energy. Both \(a . c\) and d.c shall follow it. In circuit of 'Assertion' the values of voltages indicated are taken as rms values of those alternating quantities. But, we shall add them vectorially. Across \(C\), we have \(V_{C}=\sqrt{V_{R}+V_{C}}\) \(10=\sqrt{8^{2}+V_{C}^{2}} \Rightarrow V_{C}=4 V\) Assertion is wrong So, correct option is (4).
PHXII07:ALTERNATING CURRENT
355995
A series \({R}\) - \({C}\) combination is connected to an ac voltage of angular frequency \(\omega = 500\,rad{s^{ - 1}}\). If the impedance of the \({R-C}\) circuit is \({R \sqrt{1.25}}\), the time constant of the circuit is
1 \(1\,ms\)
2 \(7\,ms\)
3 \(4\,ms\)
4 \(3\,ms\)
Explanation:
Given, \(\omega = 500\,rad{s^{ - 1}}\) and \({Z=R \sqrt{1.25}}\) As impedance. \({Z=\sqrt{R^{2}+\left(\dfrac{1}{\omega C}\right)^{2}}=R \sqrt{1.25}}\) \({R^{2}(1.25)=R^{2}+\left(\dfrac{1}{\omega C}\right)^{2} \Rightarrow \dfrac{1}{\omega C}=0.5 R}\) or time constant (in millisecond), \(i.e.\) \({R C=\dfrac{1}{0.5 \times 500 {~s}^{-1}}=0.004 {~s}=4 {~ms}}\)
PHXII07:ALTERNATING CURRENT
355996
A resistor and a capacitor are connected in series with an \(a.c.\) source. If the potential drop across the capacitor is 5\(V\) and that across resistor is 12\(V\), the applied voltage is
355993
In an \(A.C\) circuit having resistance and capacitance
1 Emf leads the current
2 Current lags behind the emf
3 Both the current and emf are in phase
4 Current leads the emf
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
355994
Assertion : Given circuit: Then \({V_C}\) in the circuit \( = 2\,V\) Reason : Kirchoff voltage law rule can be applied to AC circuits also.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Reason is true as kirchoffs voltage law \((K V L)\) is fundamentally for conservation of electrical energy. Both \(a . c\) and d.c shall follow it. In circuit of 'Assertion' the values of voltages indicated are taken as rms values of those alternating quantities. But, we shall add them vectorially. Across \(C\), we have \(V_{C}=\sqrt{V_{R}+V_{C}}\) \(10=\sqrt{8^{2}+V_{C}^{2}} \Rightarrow V_{C}=4 V\) Assertion is wrong So, correct option is (4).
PHXII07:ALTERNATING CURRENT
355995
A series \({R}\) - \({C}\) combination is connected to an ac voltage of angular frequency \(\omega = 500\,rad{s^{ - 1}}\). If the impedance of the \({R-C}\) circuit is \({R \sqrt{1.25}}\), the time constant of the circuit is
1 \(1\,ms\)
2 \(7\,ms\)
3 \(4\,ms\)
4 \(3\,ms\)
Explanation:
Given, \(\omega = 500\,rad{s^{ - 1}}\) and \({Z=R \sqrt{1.25}}\) As impedance. \({Z=\sqrt{R^{2}+\left(\dfrac{1}{\omega C}\right)^{2}}=R \sqrt{1.25}}\) \({R^{2}(1.25)=R^{2}+\left(\dfrac{1}{\omega C}\right)^{2} \Rightarrow \dfrac{1}{\omega C}=0.5 R}\) or time constant (in millisecond), \(i.e.\) \({R C=\dfrac{1}{0.5 \times 500 {~s}^{-1}}=0.004 {~s}=4 {~ms}}\)
PHXII07:ALTERNATING CURRENT
355996
A resistor and a capacitor are connected in series with an \(a.c.\) source. If the potential drop across the capacitor is 5\(V\) and that across resistor is 12\(V\), the applied voltage is
355993
In an \(A.C\) circuit having resistance and capacitance
1 Emf leads the current
2 Current lags behind the emf
3 Both the current and emf are in phase
4 Current leads the emf
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
355994
Assertion : Given circuit: Then \({V_C}\) in the circuit \( = 2\,V\) Reason : Kirchoff voltage law rule can be applied to AC circuits also.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Reason is true as kirchoffs voltage law \((K V L)\) is fundamentally for conservation of electrical energy. Both \(a . c\) and d.c shall follow it. In circuit of 'Assertion' the values of voltages indicated are taken as rms values of those alternating quantities. But, we shall add them vectorially. Across \(C\), we have \(V_{C}=\sqrt{V_{R}+V_{C}}\) \(10=\sqrt{8^{2}+V_{C}^{2}} \Rightarrow V_{C}=4 V\) Assertion is wrong So, correct option is (4).
PHXII07:ALTERNATING CURRENT
355995
A series \({R}\) - \({C}\) combination is connected to an ac voltage of angular frequency \(\omega = 500\,rad{s^{ - 1}}\). If the impedance of the \({R-C}\) circuit is \({R \sqrt{1.25}}\), the time constant of the circuit is
1 \(1\,ms\)
2 \(7\,ms\)
3 \(4\,ms\)
4 \(3\,ms\)
Explanation:
Given, \(\omega = 500\,rad{s^{ - 1}}\) and \({Z=R \sqrt{1.25}}\) As impedance. \({Z=\sqrt{R^{2}+\left(\dfrac{1}{\omega C}\right)^{2}}=R \sqrt{1.25}}\) \({R^{2}(1.25)=R^{2}+\left(\dfrac{1}{\omega C}\right)^{2} \Rightarrow \dfrac{1}{\omega C}=0.5 R}\) or time constant (in millisecond), \(i.e.\) \({R C=\dfrac{1}{0.5 \times 500 {~s}^{-1}}=0.004 {~s}=4 {~ms}}\)
PHXII07:ALTERNATING CURRENT
355996
A resistor and a capacitor are connected in series with an \(a.c.\) source. If the potential drop across the capacitor is 5\(V\) and that across resistor is 12\(V\), the applied voltage is
355993
In an \(A.C\) circuit having resistance and capacitance
1 Emf leads the current
2 Current lags behind the emf
3 Both the current and emf are in phase
4 Current leads the emf
Explanation:
Conceptual Question
PHXII07:ALTERNATING CURRENT
355994
Assertion : Given circuit: Then \({V_C}\) in the circuit \( = 2\,V\) Reason : Kirchoff voltage law rule can be applied to AC circuits also.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Reason is true as kirchoffs voltage law \((K V L)\) is fundamentally for conservation of electrical energy. Both \(a . c\) and d.c shall follow it. In circuit of 'Assertion' the values of voltages indicated are taken as rms values of those alternating quantities. But, we shall add them vectorially. Across \(C\), we have \(V_{C}=\sqrt{V_{R}+V_{C}}\) \(10=\sqrt{8^{2}+V_{C}^{2}} \Rightarrow V_{C}=4 V\) Assertion is wrong So, correct option is (4).
PHXII07:ALTERNATING CURRENT
355995
A series \({R}\) - \({C}\) combination is connected to an ac voltage of angular frequency \(\omega = 500\,rad{s^{ - 1}}\). If the impedance of the \({R-C}\) circuit is \({R \sqrt{1.25}}\), the time constant of the circuit is
1 \(1\,ms\)
2 \(7\,ms\)
3 \(4\,ms\)
4 \(3\,ms\)
Explanation:
Given, \(\omega = 500\,rad{s^{ - 1}}\) and \({Z=R \sqrt{1.25}}\) As impedance. \({Z=\sqrt{R^{2}+\left(\dfrac{1}{\omega C}\right)^{2}}=R \sqrt{1.25}}\) \({R^{2}(1.25)=R^{2}+\left(\dfrac{1}{\omega C}\right)^{2} \Rightarrow \dfrac{1}{\omega C}=0.5 R}\) or time constant (in millisecond), \(i.e.\) \({R C=\dfrac{1}{0.5 \times 500 {~s}^{-1}}=0.004 {~s}=4 {~ms}}\)
PHXII07:ALTERNATING CURRENT
355996
A resistor and a capacitor are connected in series with an \(a.c.\) source. If the potential drop across the capacitor is 5\(V\) and that across resistor is 12\(V\), the applied voltage is
