297939
If \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac{3}{4},\) then x =
1 9
2 -6
3 -9
4 4
Explanation:
-9 As, \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac34\) \(\Rightarrow\frac{\text{x}}{6}+\frac{\text{x}}{4}-\frac{\text{x}}{2}=\frac{3}{4}\) (By transposing \(\frac{\text{x}}{2}\) to L.H.S.) \(\Rightarrow\frac{2\text{x}}{12}+\frac{3\text{x}}{12}-\frac{6\text{x}}{12}=\frac{3}{4}\) \(\Rightarrow\frac{2\text{x}+3\text{x}-6\text{x}}{12}=\frac34\) \(\Rightarrow\frac{-\text{x}}{12}=\frac34\) \(\Rightarrow-\text{x}\times4=3\times12\) (By cross multiplication) \(\Rightarrow-4\text{x}=36\) \(\Rightarrow\text{x}=\frac{36}{-4}\) \(\therefore\text{x}=-9\) Hence, the correct alternative is option (c).
SIMPLE EQUATIONS
298040
The value of x that satisfies the equation \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{ x - 13}}\) is
1 4
2 3
3 2
4 1
Explanation:
4 If x = 4 the \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{x-13}}?\frac{4}{4-3}+\frac{5}{4-3}=\frac{9}{4-13}? \frac{4}{1}+\frac{5}{1}=\frac{9}{9}?4-5=-1?-1=-1\) LHS=RHSHence x=4 satisfies the equation.
SIMPLE EQUATIONS
298041
Indu and Ramadhir can complete a task in 25 days and 50 days respectively. How long would Indu take to complete the task if Ramadhir assists her every second day ??
1 10 days
2 12days
3 15 days
4 20 days
Explanation:
20 days Indu can complete task in 25 days Indus speed = x Ramadhir can complete task in 50 days Ramadhirs speed \(=\text{ x } \frac{25}{50} = \frac{\text{x}}{2}\) every second day If Ramadhir assist Indu then Indus speed \(=\text{x}+\frac{\text{x}}{4}=\frac{\text{5x}}{4}\) Task completion time \(=\frac{\text{25x}}{\frac{\text{5x}}{4}}=\) 20 days
SIMPLE EQUATIONS
298042
Mark against the correct answer in the following: A number when multiplied by 5 is increased by 80. The number is:
1 15
2 20
3 25
4 30
Explanation:
20 Let the number = x According to the condition, 5x = 80 + x 5x - x = 80 4x = 80 x = 20 Number = 20
297939
If \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac{3}{4},\) then x =
1 9
2 -6
3 -9
4 4
Explanation:
-9 As, \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac34\) \(\Rightarrow\frac{\text{x}}{6}+\frac{\text{x}}{4}-\frac{\text{x}}{2}=\frac{3}{4}\) (By transposing \(\frac{\text{x}}{2}\) to L.H.S.) \(\Rightarrow\frac{2\text{x}}{12}+\frac{3\text{x}}{12}-\frac{6\text{x}}{12}=\frac{3}{4}\) \(\Rightarrow\frac{2\text{x}+3\text{x}-6\text{x}}{12}=\frac34\) \(\Rightarrow\frac{-\text{x}}{12}=\frac34\) \(\Rightarrow-\text{x}\times4=3\times12\) (By cross multiplication) \(\Rightarrow-4\text{x}=36\) \(\Rightarrow\text{x}=\frac{36}{-4}\) \(\therefore\text{x}=-9\) Hence, the correct alternative is option (c).
SIMPLE EQUATIONS
298040
The value of x that satisfies the equation \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{ x - 13}}\) is
1 4
2 3
3 2
4 1
Explanation:
4 If x = 4 the \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{x-13}}?\frac{4}{4-3}+\frac{5}{4-3}=\frac{9}{4-13}? \frac{4}{1}+\frac{5}{1}=\frac{9}{9}?4-5=-1?-1=-1\) LHS=RHSHence x=4 satisfies the equation.
SIMPLE EQUATIONS
298041
Indu and Ramadhir can complete a task in 25 days and 50 days respectively. How long would Indu take to complete the task if Ramadhir assists her every second day ??
1 10 days
2 12days
3 15 days
4 20 days
Explanation:
20 days Indu can complete task in 25 days Indus speed = x Ramadhir can complete task in 50 days Ramadhirs speed \(=\text{ x } \frac{25}{50} = \frac{\text{x}}{2}\) every second day If Ramadhir assist Indu then Indus speed \(=\text{x}+\frac{\text{x}}{4}=\frac{\text{5x}}{4}\) Task completion time \(=\frac{\text{25x}}{\frac{\text{5x}}{4}}=\) 20 days
SIMPLE EQUATIONS
298042
Mark against the correct answer in the following: A number when multiplied by 5 is increased by 80. The number is:
1 15
2 20
3 25
4 30
Explanation:
20 Let the number = x According to the condition, 5x = 80 + x 5x - x = 80 4x = 80 x = 20 Number = 20
297939
If \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac{3}{4},\) then x =
1 9
2 -6
3 -9
4 4
Explanation:
-9 As, \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac34\) \(\Rightarrow\frac{\text{x}}{6}+\frac{\text{x}}{4}-\frac{\text{x}}{2}=\frac{3}{4}\) (By transposing \(\frac{\text{x}}{2}\) to L.H.S.) \(\Rightarrow\frac{2\text{x}}{12}+\frac{3\text{x}}{12}-\frac{6\text{x}}{12}=\frac{3}{4}\) \(\Rightarrow\frac{2\text{x}+3\text{x}-6\text{x}}{12}=\frac34\) \(\Rightarrow\frac{-\text{x}}{12}=\frac34\) \(\Rightarrow-\text{x}\times4=3\times12\) (By cross multiplication) \(\Rightarrow-4\text{x}=36\) \(\Rightarrow\text{x}=\frac{36}{-4}\) \(\therefore\text{x}=-9\) Hence, the correct alternative is option (c).
SIMPLE EQUATIONS
298040
The value of x that satisfies the equation \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{ x - 13}}\) is
1 4
2 3
3 2
4 1
Explanation:
4 If x = 4 the \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{x-13}}?\frac{4}{4-3}+\frac{5}{4-3}=\frac{9}{4-13}? \frac{4}{1}+\frac{5}{1}=\frac{9}{9}?4-5=-1?-1=-1\) LHS=RHSHence x=4 satisfies the equation.
SIMPLE EQUATIONS
298041
Indu and Ramadhir can complete a task in 25 days and 50 days respectively. How long would Indu take to complete the task if Ramadhir assists her every second day ??
1 10 days
2 12days
3 15 days
4 20 days
Explanation:
20 days Indu can complete task in 25 days Indus speed = x Ramadhir can complete task in 50 days Ramadhirs speed \(=\text{ x } \frac{25}{50} = \frac{\text{x}}{2}\) every second day If Ramadhir assist Indu then Indus speed \(=\text{x}+\frac{\text{x}}{4}=\frac{\text{5x}}{4}\) Task completion time \(=\frac{\text{25x}}{\frac{\text{5x}}{4}}=\) 20 days
SIMPLE EQUATIONS
298042
Mark against the correct answer in the following: A number when multiplied by 5 is increased by 80. The number is:
1 15
2 20
3 25
4 30
Explanation:
20 Let the number = x According to the condition, 5x = 80 + x 5x - x = 80 4x = 80 x = 20 Number = 20
297939
If \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac{3}{4},\) then x =
1 9
2 -6
3 -9
4 4
Explanation:
-9 As, \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac34\) \(\Rightarrow\frac{\text{x}}{6}+\frac{\text{x}}{4}-\frac{\text{x}}{2}=\frac{3}{4}\) (By transposing \(\frac{\text{x}}{2}\) to L.H.S.) \(\Rightarrow\frac{2\text{x}}{12}+\frac{3\text{x}}{12}-\frac{6\text{x}}{12}=\frac{3}{4}\) \(\Rightarrow\frac{2\text{x}+3\text{x}-6\text{x}}{12}=\frac34\) \(\Rightarrow\frac{-\text{x}}{12}=\frac34\) \(\Rightarrow-\text{x}\times4=3\times12\) (By cross multiplication) \(\Rightarrow-4\text{x}=36\) \(\Rightarrow\text{x}=\frac{36}{-4}\) \(\therefore\text{x}=-9\) Hence, the correct alternative is option (c).
SIMPLE EQUATIONS
298040
The value of x that satisfies the equation \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{ x - 13}}\) is
1 4
2 3
3 2
4 1
Explanation:
4 If x = 4 the \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{x-13}}?\frac{4}{4-3}+\frac{5}{4-3}=\frac{9}{4-13}? \frac{4}{1}+\frac{5}{1}=\frac{9}{9}?4-5=-1?-1=-1\) LHS=RHSHence x=4 satisfies the equation.
SIMPLE EQUATIONS
298041
Indu and Ramadhir can complete a task in 25 days and 50 days respectively. How long would Indu take to complete the task if Ramadhir assists her every second day ??
1 10 days
2 12days
3 15 days
4 20 days
Explanation:
20 days Indu can complete task in 25 days Indus speed = x Ramadhir can complete task in 50 days Ramadhirs speed \(=\text{ x } \frac{25}{50} = \frac{\text{x}}{2}\) every second day If Ramadhir assist Indu then Indus speed \(=\text{x}+\frac{\text{x}}{4}=\frac{\text{5x}}{4}\) Task completion time \(=\frac{\text{25x}}{\frac{\text{5x}}{4}}=\) 20 days
SIMPLE EQUATIONS
298042
Mark against the correct answer in the following: A number when multiplied by 5 is increased by 80. The number is:
1 15
2 20
3 25
4 30
Explanation:
20 Let the number = x According to the condition, 5x = 80 + x 5x - x = 80 4x = 80 x = 20 Number = 20
297939
If \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac{3}{4},\) then x =
1 9
2 -6
3 -9
4 4
Explanation:
-9 As, \(\frac{\text{x}}{6}+\frac{\text{x}}{4}=\frac{\text{x}}{2}+\frac34\) \(\Rightarrow\frac{\text{x}}{6}+\frac{\text{x}}{4}-\frac{\text{x}}{2}=\frac{3}{4}\) (By transposing \(\frac{\text{x}}{2}\) to L.H.S.) \(\Rightarrow\frac{2\text{x}}{12}+\frac{3\text{x}}{12}-\frac{6\text{x}}{12}=\frac{3}{4}\) \(\Rightarrow\frac{2\text{x}+3\text{x}-6\text{x}}{12}=\frac34\) \(\Rightarrow\frac{-\text{x}}{12}=\frac34\) \(\Rightarrow-\text{x}\times4=3\times12\) (By cross multiplication) \(\Rightarrow-4\text{x}=36\) \(\Rightarrow\text{x}=\frac{36}{-4}\) \(\therefore\text{x}=-9\) Hence, the correct alternative is option (c).
SIMPLE EQUATIONS
298040
The value of x that satisfies the equation \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{ x - 13}}\) is
1 4
2 3
3 2
4 1
Explanation:
4 If x = 4 the \(\frac{4}{\text{x-3}}+\frac{5}{\text{x-5}}=\frac{9}{\text{x-13}}?\frac{4}{4-3}+\frac{5}{4-3}=\frac{9}{4-13}? \frac{4}{1}+\frac{5}{1}=\frac{9}{9}?4-5=-1?-1=-1\) LHS=RHSHence x=4 satisfies the equation.
SIMPLE EQUATIONS
298041
Indu and Ramadhir can complete a task in 25 days and 50 days respectively. How long would Indu take to complete the task if Ramadhir assists her every second day ??
1 10 days
2 12days
3 15 days
4 20 days
Explanation:
20 days Indu can complete task in 25 days Indus speed = x Ramadhir can complete task in 50 days Ramadhirs speed \(=\text{ x } \frac{25}{50} = \frac{\text{x}}{2}\) every second day If Ramadhir assist Indu then Indus speed \(=\text{x}+\frac{\text{x}}{4}=\frac{\text{5x}}{4}\) Task completion time \(=\frac{\text{25x}}{\frac{\text{5x}}{4}}=\) 20 days
SIMPLE EQUATIONS
298042
Mark against the correct answer in the following: A number when multiplied by 5 is increased by 80. The number is:
1 15
2 20
3 25
4 30
Explanation:
20 Let the number = x According to the condition, 5x = 80 + x 5x - x = 80 4x = 80 x = 20 Number = 20
