297600
The sides A B, B C, C A of a triangle ABC have 3, 4 and 5 interior points respectively on them. The number of triangles that can be constructed using these points as vertices is:
1 205
2 210
3 315
4 216
Explanation:
205 Total number of points 12. If no three points are co-linear then total number of the triangles would be \(^{1}\)C\(_{\1}\) But 3 points on AB, 4 points on BC and 5 points on CA are co-linear. So, total number of triangles formed should be = \(^{1}\)C\(_{\1}\) - \(^{1}\)C\(_{\1}\) + \(^{1}\)C\(_{\1}\)? + \(^{1}\)C\(_{\1}\)?) = 220 - (1 + 4 + 10) = 205?
PRACTICAL GEOMETRY
297601
Which of the following letters of English alphabets have more than 2 lines of symmetry?
1
20
31
42
Explanation:
3 The letter 0 has more than two lines of symmetry. 4
PRACTICAL GEOMETRY
297602
Which of the following is criterion for the construction of a triangle?
1 SSS
2 AAA
3 RRR
4 SSA
Explanation:
SSS
PRACTICAL GEOMETRY
297603
Mark \((\checkmark)\) against the correct answer. Two poles of heights 6 m and 11m stand vertically on a plane ground. If the distance between their feet is 12m, what is the distance between their tops?
1 13m.
2 14m.
3 15m.
4 12.8m.
Explanation:
13m. 5 Let AB and CD are two poles such that AB = 6m, CD = 11m and distance between two poles BD = 12m From A, draw AE||BD AE = BD = 12m CE = CD - ED = 11 - 6 = 5 m Now in right \(\triangle\text{AEC}\) AC\(^{1}\) = AE\(^{1}\) + CE = (12)\(^{1}\) + (5)\(^{1}\) = 144 + 25 = 169 = (13)\(^{1}\) AC = 13m Distance between tops of poles = 13m
297600
The sides A B, B C, C A of a triangle ABC have 3, 4 and 5 interior points respectively on them. The number of triangles that can be constructed using these points as vertices is:
1 205
2 210
3 315
4 216
Explanation:
205 Total number of points 12. If no three points are co-linear then total number of the triangles would be \(^{1}\)C\(_{\1}\) But 3 points on AB, 4 points on BC and 5 points on CA are co-linear. So, total number of triangles formed should be = \(^{1}\)C\(_{\1}\) - \(^{1}\)C\(_{\1}\) + \(^{1}\)C\(_{\1}\)? + \(^{1}\)C\(_{\1}\)?) = 220 - (1 + 4 + 10) = 205?
PRACTICAL GEOMETRY
297601
Which of the following letters of English alphabets have more than 2 lines of symmetry?
1
20
31
42
Explanation:
3 The letter 0 has more than two lines of symmetry. 4
PRACTICAL GEOMETRY
297602
Which of the following is criterion for the construction of a triangle?
1 SSS
2 AAA
3 RRR
4 SSA
Explanation:
SSS
PRACTICAL GEOMETRY
297603
Mark \((\checkmark)\) against the correct answer. Two poles of heights 6 m and 11m stand vertically on a plane ground. If the distance between their feet is 12m, what is the distance between their tops?
1 13m.
2 14m.
3 15m.
4 12.8m.
Explanation:
13m. 5 Let AB and CD are two poles such that AB = 6m, CD = 11m and distance between two poles BD = 12m From A, draw AE||BD AE = BD = 12m CE = CD - ED = 11 - 6 = 5 m Now in right \(\triangle\text{AEC}\) AC\(^{1}\) = AE\(^{1}\) + CE = (12)\(^{1}\) + (5)\(^{1}\) = 144 + 25 = 169 = (13)\(^{1}\) AC = 13m Distance between tops of poles = 13m
297600
The sides A B, B C, C A of a triangle ABC have 3, 4 and 5 interior points respectively on them. The number of triangles that can be constructed using these points as vertices is:
1 205
2 210
3 315
4 216
Explanation:
205 Total number of points 12. If no three points are co-linear then total number of the triangles would be \(^{1}\)C\(_{\1}\) But 3 points on AB, 4 points on BC and 5 points on CA are co-linear. So, total number of triangles formed should be = \(^{1}\)C\(_{\1}\) - \(^{1}\)C\(_{\1}\) + \(^{1}\)C\(_{\1}\)? + \(^{1}\)C\(_{\1}\)?) = 220 - (1 + 4 + 10) = 205?
PRACTICAL GEOMETRY
297601
Which of the following letters of English alphabets have more than 2 lines of symmetry?
1
20
31
42
Explanation:
3 The letter 0 has more than two lines of symmetry. 4
PRACTICAL GEOMETRY
297602
Which of the following is criterion for the construction of a triangle?
1 SSS
2 AAA
3 RRR
4 SSA
Explanation:
SSS
PRACTICAL GEOMETRY
297603
Mark \((\checkmark)\) against the correct answer. Two poles of heights 6 m and 11m stand vertically on a plane ground. If the distance between their feet is 12m, what is the distance between their tops?
1 13m.
2 14m.
3 15m.
4 12.8m.
Explanation:
13m. 5 Let AB and CD are two poles such that AB = 6m, CD = 11m and distance between two poles BD = 12m From A, draw AE||BD AE = BD = 12m CE = CD - ED = 11 - 6 = 5 m Now in right \(\triangle\text{AEC}\) AC\(^{1}\) = AE\(^{1}\) + CE = (12)\(^{1}\) + (5)\(^{1}\) = 144 + 25 = 169 = (13)\(^{1}\) AC = 13m Distance between tops of poles = 13m
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PRACTICAL GEOMETRY
297600
The sides A B, B C, C A of a triangle ABC have 3, 4 and 5 interior points respectively on them. The number of triangles that can be constructed using these points as vertices is:
1 205
2 210
3 315
4 216
Explanation:
205 Total number of points 12. If no three points are co-linear then total number of the triangles would be \(^{1}\)C\(_{\1}\) But 3 points on AB, 4 points on BC and 5 points on CA are co-linear. So, total number of triangles formed should be = \(^{1}\)C\(_{\1}\) - \(^{1}\)C\(_{\1}\) + \(^{1}\)C\(_{\1}\)? + \(^{1}\)C\(_{\1}\)?) = 220 - (1 + 4 + 10) = 205?
PRACTICAL GEOMETRY
297601
Which of the following letters of English alphabets have more than 2 lines of symmetry?
1
20
31
42
Explanation:
3 The letter 0 has more than two lines of symmetry. 4
PRACTICAL GEOMETRY
297602
Which of the following is criterion for the construction of a triangle?
1 SSS
2 AAA
3 RRR
4 SSA
Explanation:
SSS
PRACTICAL GEOMETRY
297603
Mark \((\checkmark)\) against the correct answer. Two poles of heights 6 m and 11m stand vertically on a plane ground. If the distance between their feet is 12m, what is the distance between their tops?
1 13m.
2 14m.
3 15m.
4 12.8m.
Explanation:
13m. 5 Let AB and CD are two poles such that AB = 6m, CD = 11m and distance between two poles BD = 12m From A, draw AE||BD AE = BD = 12m CE = CD - ED = 11 - 6 = 5 m Now in right \(\triangle\text{AEC}\) AC\(^{1}\) = AE\(^{1}\) + CE = (12)\(^{1}\) + (5)\(^{1}\) = 144 + 25 = 169 = (13)\(^{1}\) AC = 13m Distance between tops of poles = 13m
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