299195
If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2 : 3 which is the smallest of the two angles?
1 72°
2 108°
3 54°
4 36°
Explanation:
72° Let the angles be 2x and 3x Now sum of interior angles on same side of transversal intersecting two parallel lines is 180° 2x + 3x = 180° 5x = 180° x = 36° So the angles are 2x = 2 × 36° = 72° 3x = 3 × 36° = 108° So the smaller angle is 72°.
299195
If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2 : 3 which is the smallest of the two angles?
1 72°
2 108°
3 54°
4 36°
Explanation:
72° Let the angles be 2x and 3x Now sum of interior angles on same side of transversal intersecting two parallel lines is 180° 2x + 3x = 180° 5x = 180° x = 36° So the angles are 2x = 2 × 36° = 72° 3x = 3 × 36° = 108° So the smaller angle is 72°.
299195
If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2 : 3 which is the smallest of the two angles?
1 72°
2 108°
3 54°
4 36°
Explanation:
72° Let the angles be 2x and 3x Now sum of interior angles on same side of transversal intersecting two parallel lines is 180° 2x + 3x = 180° 5x = 180° x = 36° So the angles are 2x = 2 × 36° = 72° 3x = 3 × 36° = 108° So the smaller angle is 72°.
299195
If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2 : 3 which is the smallest of the two angles?
1 72°
2 108°
3 54°
4 36°
Explanation:
72° Let the angles be 2x and 3x Now sum of interior angles on same side of transversal intersecting two parallel lines is 180° 2x + 3x = 180° 5x = 180° x = 36° So the angles are 2x = 2 × 36° = 72° 3x = 3 × 36° = 108° So the smaller angle is 72°.