NEET Test Series from KOTA - 10 Papers In MS WORD
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DATA HANDLING
300307
In a bundle of 20 sticks, there are 4 sticks each of length 1m 50cm, 10 sticks each of length 2m and each of the rest of length 1m. What is the average length of the sticks in the bundle?
300308
The average of 11, 12, 13, 14 and x is 13. The value of x is ........
1 17
2 21
3 15
4 20
Explanation:
15 The average of 11, 12, 13, 14 and x is 13 \(\therefore\frac{11+12+13+14+{\text{x}}}{{5}} = 13\) \(\therefore 50+{\text{x}} = 65{\text{x}} = 15\)
DATA HANDLING
300309
The arithmetic mean of 5 numbers is 27. lf one of the number is excluded the mean of the remaining number is 25. Find the excludednumber:
1 27
2 25
3 30
4 35
Explanation:
35 Sum of 5 numbers = 27 × 5 = 135 when one of the numbers is excluded. sum of remaining 4 numbers = 4 × 25 = 100 Excluded number = 135 - 100 = 35.
DATA HANDLING
300310
M= 1, 2, 3, 4, 5, 6, 7. Each number in set N is generated by dividing each number in set M by 2. Calculate the arithmetic mean of numbers in N:
1 1
2 \(\frac{3}{2}\)
3 \(\frac{7}{4}\)
4 2
5 4
Explanation:
2 Given, M = 1, 2, 3, 4, 5, 6, 7 Each number in set N is generated by dividing each number in set M by 2 N = 0.5, 1, 1.5, 2, 2.5, 3, 3.5 Arithmetic mean of numbers of set N is \( = \frac{0.5+1+1.5+2+2.5+3+3.5}{7} = \frac{14}{7} = {2}\)
300307
In a bundle of 20 sticks, there are 4 sticks each of length 1m 50cm, 10 sticks each of length 2m and each of the rest of length 1m. What is the average length of the sticks in the bundle?
300308
The average of 11, 12, 13, 14 and x is 13. The value of x is ........
1 17
2 21
3 15
4 20
Explanation:
15 The average of 11, 12, 13, 14 and x is 13 \(\therefore\frac{11+12+13+14+{\text{x}}}{{5}} = 13\) \(\therefore 50+{\text{x}} = 65{\text{x}} = 15\)
DATA HANDLING
300309
The arithmetic mean of 5 numbers is 27. lf one of the number is excluded the mean of the remaining number is 25. Find the excludednumber:
1 27
2 25
3 30
4 35
Explanation:
35 Sum of 5 numbers = 27 × 5 = 135 when one of the numbers is excluded. sum of remaining 4 numbers = 4 × 25 = 100 Excluded number = 135 - 100 = 35.
DATA HANDLING
300310
M= 1, 2, 3, 4, 5, 6, 7. Each number in set N is generated by dividing each number in set M by 2. Calculate the arithmetic mean of numbers in N:
1 1
2 \(\frac{3}{2}\)
3 \(\frac{7}{4}\)
4 2
5 4
Explanation:
2 Given, M = 1, 2, 3, 4, 5, 6, 7 Each number in set N is generated by dividing each number in set M by 2 N = 0.5, 1, 1.5, 2, 2.5, 3, 3.5 Arithmetic mean of numbers of set N is \( = \frac{0.5+1+1.5+2+2.5+3+3.5}{7} = \frac{14}{7} = {2}\)
300307
In a bundle of 20 sticks, there are 4 sticks each of length 1m 50cm, 10 sticks each of length 2m and each of the rest of length 1m. What is the average length of the sticks in the bundle?
300308
The average of 11, 12, 13, 14 and x is 13. The value of x is ........
1 17
2 21
3 15
4 20
Explanation:
15 The average of 11, 12, 13, 14 and x is 13 \(\therefore\frac{11+12+13+14+{\text{x}}}{{5}} = 13\) \(\therefore 50+{\text{x}} = 65{\text{x}} = 15\)
DATA HANDLING
300309
The arithmetic mean of 5 numbers is 27. lf one of the number is excluded the mean of the remaining number is 25. Find the excludednumber:
1 27
2 25
3 30
4 35
Explanation:
35 Sum of 5 numbers = 27 × 5 = 135 when one of the numbers is excluded. sum of remaining 4 numbers = 4 × 25 = 100 Excluded number = 135 - 100 = 35.
DATA HANDLING
300310
M= 1, 2, 3, 4, 5, 6, 7. Each number in set N is generated by dividing each number in set M by 2. Calculate the arithmetic mean of numbers in N:
1 1
2 \(\frac{3}{2}\)
3 \(\frac{7}{4}\)
4 2
5 4
Explanation:
2 Given, M = 1, 2, 3, 4, 5, 6, 7 Each number in set N is generated by dividing each number in set M by 2 N = 0.5, 1, 1.5, 2, 2.5, 3, 3.5 Arithmetic mean of numbers of set N is \( = \frac{0.5+1+1.5+2+2.5+3+3.5}{7} = \frac{14}{7} = {2}\)
300307
In a bundle of 20 sticks, there are 4 sticks each of length 1m 50cm, 10 sticks each of length 2m and each of the rest of length 1m. What is the average length of the sticks in the bundle?
300308
The average of 11, 12, 13, 14 and x is 13. The value of x is ........
1 17
2 21
3 15
4 20
Explanation:
15 The average of 11, 12, 13, 14 and x is 13 \(\therefore\frac{11+12+13+14+{\text{x}}}{{5}} = 13\) \(\therefore 50+{\text{x}} = 65{\text{x}} = 15\)
DATA HANDLING
300309
The arithmetic mean of 5 numbers is 27. lf one of the number is excluded the mean of the remaining number is 25. Find the excludednumber:
1 27
2 25
3 30
4 35
Explanation:
35 Sum of 5 numbers = 27 × 5 = 135 when one of the numbers is excluded. sum of remaining 4 numbers = 4 × 25 = 100 Excluded number = 135 - 100 = 35.
DATA HANDLING
300310
M= 1, 2, 3, 4, 5, 6, 7. Each number in set N is generated by dividing each number in set M by 2. Calculate the arithmetic mean of numbers in N:
1 1
2 \(\frac{3}{2}\)
3 \(\frac{7}{4}\)
4 2
5 4
Explanation:
2 Given, M = 1, 2, 3, 4, 5, 6, 7 Each number in set N is generated by dividing each number in set M by 2 N = 0.5, 1, 1.5, 2, 2.5, 3, 3.5 Arithmetic mean of numbers of set N is \( = \frac{0.5+1+1.5+2+2.5+3+3.5}{7} = \frac{14}{7} = {2}\)