300088
The probability of getting a red card from a well shuffled pack of cards is:
1 \(\frac{1}{4}\)
2 \(\frac{1}{2}\)
3 \(\frac{3}{4}\)
4 \(\frac{1}{3}\)
Explanation:
\(\frac{1}{2}\) There are 52 cards in a standard deck. There are four different suits Diamonds (red), Clubs (black), Hearts (red), and Spades (black) each containing 13 cards. \(\therefore \) Number of red cards (favourable outcomes) = 13 + 13 = 26 Therefore Probability of getting a red card \(=\frac{26}{52}=\frac{1}{2}\) Hence, the correct option is (b).
300090
Find the average of 201, 204, 207, 210, 213:
1 204
2 207
3 213
4 208
Explanation:
207 Average of Number \( = \frac{\text{sum of all number}}{\text{total number of number}}\) \(\frac{201+207+210+213+204}{5} = > \frac{1035}{5} = {207}\)
DATA HANDLING
300091
The mean of 33, 53, 32, 35, 47 is:
1 40
2 56
3 55
4 6\(^{\1}\)6!
Explanation:
40 Given observations 33, 53, 32, 35, 47 no. of observations is 5 sum of observations is 33 + 53 + 32 + 35 + 47 = 200 mean is \(\frac{200}{5} = {40}\)
DATA HANDLING
300092
The median of the data 3, 4, 5, 6, 7, 3, 4 is:
1 5
2 3
3 4
4 6
Explanation:
4 We know that, median is the middle most observation. For finding the median of the data firstly, we arrange the data in ascending order, i.e. Ascending order i.e 3, 3, 4, 4, 5, 6, 7. n = 7 (odd) \(\therefore\) Median = Value of \(\Big(\frac{\text{n+1}}{2}\Big)^{\text{th}}\) observation = Value of \(\Big(\frac{7+1}{2}\Big)^{\text{th}}\) observation = 4th observation = 4
300088
The probability of getting a red card from a well shuffled pack of cards is:
1 \(\frac{1}{4}\)
2 \(\frac{1}{2}\)
3 \(\frac{3}{4}\)
4 \(\frac{1}{3}\)
Explanation:
\(\frac{1}{2}\) There are 52 cards in a standard deck. There are four different suits Diamonds (red), Clubs (black), Hearts (red), and Spades (black) each containing 13 cards. \(\therefore \) Number of red cards (favourable outcomes) = 13 + 13 = 26 Therefore Probability of getting a red card \(=\frac{26}{52}=\frac{1}{2}\) Hence, the correct option is (b).
300090
Find the average of 201, 204, 207, 210, 213:
1 204
2 207
3 213
4 208
Explanation:
207 Average of Number \( = \frac{\text{sum of all number}}{\text{total number of number}}\) \(\frac{201+207+210+213+204}{5} = > \frac{1035}{5} = {207}\)
DATA HANDLING
300091
The mean of 33, 53, 32, 35, 47 is:
1 40
2 56
3 55
4 6\(^{\1}\)6!
Explanation:
40 Given observations 33, 53, 32, 35, 47 no. of observations is 5 sum of observations is 33 + 53 + 32 + 35 + 47 = 200 mean is \(\frac{200}{5} = {40}\)
DATA HANDLING
300092
The median of the data 3, 4, 5, 6, 7, 3, 4 is:
1 5
2 3
3 4
4 6
Explanation:
4 We know that, median is the middle most observation. For finding the median of the data firstly, we arrange the data in ascending order, i.e. Ascending order i.e 3, 3, 4, 4, 5, 6, 7. n = 7 (odd) \(\therefore\) Median = Value of \(\Big(\frac{\text{n+1}}{2}\Big)^{\text{th}}\) observation = Value of \(\Big(\frac{7+1}{2}\Big)^{\text{th}}\) observation = 4th observation = 4
300088
The probability of getting a red card from a well shuffled pack of cards is:
1 \(\frac{1}{4}\)
2 \(\frac{1}{2}\)
3 \(\frac{3}{4}\)
4 \(\frac{1}{3}\)
Explanation:
\(\frac{1}{2}\) There are 52 cards in a standard deck. There are four different suits Diamonds (red), Clubs (black), Hearts (red), and Spades (black) each containing 13 cards. \(\therefore \) Number of red cards (favourable outcomes) = 13 + 13 = 26 Therefore Probability of getting a red card \(=\frac{26}{52}=\frac{1}{2}\) Hence, the correct option is (b).
300090
Find the average of 201, 204, 207, 210, 213:
1 204
2 207
3 213
4 208
Explanation:
207 Average of Number \( = \frac{\text{sum of all number}}{\text{total number of number}}\) \(\frac{201+207+210+213+204}{5} = > \frac{1035}{5} = {207}\)
DATA HANDLING
300091
The mean of 33, 53, 32, 35, 47 is:
1 40
2 56
3 55
4 6\(^{\1}\)6!
Explanation:
40 Given observations 33, 53, 32, 35, 47 no. of observations is 5 sum of observations is 33 + 53 + 32 + 35 + 47 = 200 mean is \(\frac{200}{5} = {40}\)
DATA HANDLING
300092
The median of the data 3, 4, 5, 6, 7, 3, 4 is:
1 5
2 3
3 4
4 6
Explanation:
4 We know that, median is the middle most observation. For finding the median of the data firstly, we arrange the data in ascending order, i.e. Ascending order i.e 3, 3, 4, 4, 5, 6, 7. n = 7 (odd) \(\therefore\) Median = Value of \(\Big(\frac{\text{n+1}}{2}\Big)^{\text{th}}\) observation = Value of \(\Big(\frac{7+1}{2}\Big)^{\text{th}}\) observation = 4th observation = 4
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DATA HANDLING
300088
The probability of getting a red card from a well shuffled pack of cards is:
1 \(\frac{1}{4}\)
2 \(\frac{1}{2}\)
3 \(\frac{3}{4}\)
4 \(\frac{1}{3}\)
Explanation:
\(\frac{1}{2}\) There are 52 cards in a standard deck. There are four different suits Diamonds (red), Clubs (black), Hearts (red), and Spades (black) each containing 13 cards. \(\therefore \) Number of red cards (favourable outcomes) = 13 + 13 = 26 Therefore Probability of getting a red card \(=\frac{26}{52}=\frac{1}{2}\) Hence, the correct option is (b).
300090
Find the average of 201, 204, 207, 210, 213:
1 204
2 207
3 213
4 208
Explanation:
207 Average of Number \( = \frac{\text{sum of all number}}{\text{total number of number}}\) \(\frac{201+207+210+213+204}{5} = > \frac{1035}{5} = {207}\)
DATA HANDLING
300091
The mean of 33, 53, 32, 35, 47 is:
1 40
2 56
3 55
4 6\(^{\1}\)6!
Explanation:
40 Given observations 33, 53, 32, 35, 47 no. of observations is 5 sum of observations is 33 + 53 + 32 + 35 + 47 = 200 mean is \(\frac{200}{5} = {40}\)
DATA HANDLING
300092
The median of the data 3, 4, 5, 6, 7, 3, 4 is:
1 5
2 3
3 4
4 6
Explanation:
4 We know that, median is the middle most observation. For finding the median of the data firstly, we arrange the data in ascending order, i.e. Ascending order i.e 3, 3, 4, 4, 5, 6, 7. n = 7 (odd) \(\therefore\) Median = Value of \(\Big(\frac{\text{n+1}}{2}\Big)^{\text{th}}\) observation = Value of \(\Big(\frac{7+1}{2}\Big)^{\text{th}}\) observation = 4th observation = 4
300088
The probability of getting a red card from a well shuffled pack of cards is:
1 \(\frac{1}{4}\)
2 \(\frac{1}{2}\)
3 \(\frac{3}{4}\)
4 \(\frac{1}{3}\)
Explanation:
\(\frac{1}{2}\) There are 52 cards in a standard deck. There are four different suits Diamonds (red), Clubs (black), Hearts (red), and Spades (black) each containing 13 cards. \(\therefore \) Number of red cards (favourable outcomes) = 13 + 13 = 26 Therefore Probability of getting a red card \(=\frac{26}{52}=\frac{1}{2}\) Hence, the correct option is (b).
300090
Find the average of 201, 204, 207, 210, 213:
1 204
2 207
3 213
4 208
Explanation:
207 Average of Number \( = \frac{\text{sum of all number}}{\text{total number of number}}\) \(\frac{201+207+210+213+204}{5} = > \frac{1035}{5} = {207}\)
DATA HANDLING
300091
The mean of 33, 53, 32, 35, 47 is:
1 40
2 56
3 55
4 6\(^{\1}\)6!
Explanation:
40 Given observations 33, 53, 32, 35, 47 no. of observations is 5 sum of observations is 33 + 53 + 32 + 35 + 47 = 200 mean is \(\frac{200}{5} = {40}\)
DATA HANDLING
300092
The median of the data 3, 4, 5, 6, 7, 3, 4 is:
1 5
2 3
3 4
4 6
Explanation:
4 We know that, median is the middle most observation. For finding the median of the data firstly, we arrange the data in ascending order, i.e. Ascending order i.e 3, 3, 4, 4, 5, 6, 7. n = 7 (odd) \(\therefore\) Median = Value of \(\Big(\frac{\text{n+1}}{2}\Big)^{\text{th}}\) observation = Value of \(\Big(\frac{7+1}{2}\Big)^{\text{th}}\) observation = 4th observation = 4