300067
The average of the four even numbers between 31 and 39 is:
1 35
2 21
3 20
4 19
Explanation:
35 Average is the sum of the data values divided by the total values. the 4 even numbers between 31 and 39 are 32, 34, 36, 38. \(\therefore\) average of even numbers between 31 and 39 \( = \frac{39 + 34 + 36 + 38}{4} = \frac{140}{4} = {35}\)
DATA HANDLING
300068
The median of the data 9, 12, 11, 10, 8, 9, 11 is:
1 10
2 11
3 9
4 None of these
Explanation:
10 Arranging the given data in increasing order, we get 8, 9, 9, 10, 11, 11, 12 As the number of observations is odd (7), the median is the middle term which is 10 Hence, the correct option is (a).
DATA HANDLING
300255
The arithinetic mean of 5, 6, 8, 9, 12, 13, 17 is:
1 20
2 15
3 10
4 25
Explanation:
10 Mean \( =\frac{ \text{Sum of observations}}{\text{Total number of observations}} = \frac{5+6+8+9+12+13+17}{7} = \frac{70}{7} = {10}\)
DATA HANDLING
300300
Taras three bowling scores in a tournament were 167, 178, and 186. What was her average score for the tournament?
1 176
2 177
3 178
4 179
5 180
Explanation:
177 Three bowling scores of tournament are 167, 178 and 186. \(\text{Average score will be } = \frac{167+178+186}{3} = {177}\)
DATA HANDLING
300253
The mean of ten items is x and if each item is increased by 4, then its mean will be ........
1 x + 4
2 4x
3 10x
4 10 + x
Explanation:
x + 4 \(\text{We know x} = \frac{\text{sum}}{10}\) Thus = 10x If each term is increased by 4, new sum = sum + 10 × 4 new sum = 10x + 40 New mean \( = \frac{10{\text{x}}+40}{10}\therefore {\text{new mean}} = \text{x+4}\)
300067
The average of the four even numbers between 31 and 39 is:
1 35
2 21
3 20
4 19
Explanation:
35 Average is the sum of the data values divided by the total values. the 4 even numbers between 31 and 39 are 32, 34, 36, 38. \(\therefore\) average of even numbers between 31 and 39 \( = \frac{39 + 34 + 36 + 38}{4} = \frac{140}{4} = {35}\)
DATA HANDLING
300068
The median of the data 9, 12, 11, 10, 8, 9, 11 is:
1 10
2 11
3 9
4 None of these
Explanation:
10 Arranging the given data in increasing order, we get 8, 9, 9, 10, 11, 11, 12 As the number of observations is odd (7), the median is the middle term which is 10 Hence, the correct option is (a).
DATA HANDLING
300255
The arithinetic mean of 5, 6, 8, 9, 12, 13, 17 is:
1 20
2 15
3 10
4 25
Explanation:
10 Mean \( =\frac{ \text{Sum of observations}}{\text{Total number of observations}} = \frac{5+6+8+9+12+13+17}{7} = \frac{70}{7} = {10}\)
DATA HANDLING
300300
Taras three bowling scores in a tournament were 167, 178, and 186. What was her average score for the tournament?
1 176
2 177
3 178
4 179
5 180
Explanation:
177 Three bowling scores of tournament are 167, 178 and 186. \(\text{Average score will be } = \frac{167+178+186}{3} = {177}\)
DATA HANDLING
300253
The mean of ten items is x and if each item is increased by 4, then its mean will be ........
1 x + 4
2 4x
3 10x
4 10 + x
Explanation:
x + 4 \(\text{We know x} = \frac{\text{sum}}{10}\) Thus = 10x If each term is increased by 4, new sum = sum + 10 × 4 new sum = 10x + 40 New mean \( = \frac{10{\text{x}}+40}{10}\therefore {\text{new mean}} = \text{x+4}\)
300067
The average of the four even numbers between 31 and 39 is:
1 35
2 21
3 20
4 19
Explanation:
35 Average is the sum of the data values divided by the total values. the 4 even numbers between 31 and 39 are 32, 34, 36, 38. \(\therefore\) average of even numbers between 31 and 39 \( = \frac{39 + 34 + 36 + 38}{4} = \frac{140}{4} = {35}\)
DATA HANDLING
300068
The median of the data 9, 12, 11, 10, 8, 9, 11 is:
1 10
2 11
3 9
4 None of these
Explanation:
10 Arranging the given data in increasing order, we get 8, 9, 9, 10, 11, 11, 12 As the number of observations is odd (7), the median is the middle term which is 10 Hence, the correct option is (a).
DATA HANDLING
300255
The arithinetic mean of 5, 6, 8, 9, 12, 13, 17 is:
1 20
2 15
3 10
4 25
Explanation:
10 Mean \( =\frac{ \text{Sum of observations}}{\text{Total number of observations}} = \frac{5+6+8+9+12+13+17}{7} = \frac{70}{7} = {10}\)
DATA HANDLING
300300
Taras three bowling scores in a tournament were 167, 178, and 186. What was her average score for the tournament?
1 176
2 177
3 178
4 179
5 180
Explanation:
177 Three bowling scores of tournament are 167, 178 and 186. \(\text{Average score will be } = \frac{167+178+186}{3} = {177}\)
DATA HANDLING
300253
The mean of ten items is x and if each item is increased by 4, then its mean will be ........
1 x + 4
2 4x
3 10x
4 10 + x
Explanation:
x + 4 \(\text{We know x} = \frac{\text{sum}}{10}\) Thus = 10x If each term is increased by 4, new sum = sum + 10 × 4 new sum = 10x + 40 New mean \( = \frac{10{\text{x}}+40}{10}\therefore {\text{new mean}} = \text{x+4}\)
300067
The average of the four even numbers between 31 and 39 is:
1 35
2 21
3 20
4 19
Explanation:
35 Average is the sum of the data values divided by the total values. the 4 even numbers between 31 and 39 are 32, 34, 36, 38. \(\therefore\) average of even numbers between 31 and 39 \( = \frac{39 + 34 + 36 + 38}{4} = \frac{140}{4} = {35}\)
DATA HANDLING
300068
The median of the data 9, 12, 11, 10, 8, 9, 11 is:
1 10
2 11
3 9
4 None of these
Explanation:
10 Arranging the given data in increasing order, we get 8, 9, 9, 10, 11, 11, 12 As the number of observations is odd (7), the median is the middle term which is 10 Hence, the correct option is (a).
DATA HANDLING
300255
The arithinetic mean of 5, 6, 8, 9, 12, 13, 17 is:
1 20
2 15
3 10
4 25
Explanation:
10 Mean \( =\frac{ \text{Sum of observations}}{\text{Total number of observations}} = \frac{5+6+8+9+12+13+17}{7} = \frac{70}{7} = {10}\)
DATA HANDLING
300300
Taras three bowling scores in a tournament were 167, 178, and 186. What was her average score for the tournament?
1 176
2 177
3 178
4 179
5 180
Explanation:
177 Three bowling scores of tournament are 167, 178 and 186. \(\text{Average score will be } = \frac{167+178+186}{3} = {177}\)
DATA HANDLING
300253
The mean of ten items is x and if each item is increased by 4, then its mean will be ........
1 x + 4
2 4x
3 10x
4 10 + x
Explanation:
x + 4 \(\text{We know x} = \frac{\text{sum}}{10}\) Thus = 10x If each term is increased by 4, new sum = sum + 10 × 4 new sum = 10x + 40 New mean \( = \frac{10{\text{x}}+40}{10}\therefore {\text{new mean}} = \text{x+4}\)
300067
The average of the four even numbers between 31 and 39 is:
1 35
2 21
3 20
4 19
Explanation:
35 Average is the sum of the data values divided by the total values. the 4 even numbers between 31 and 39 are 32, 34, 36, 38. \(\therefore\) average of even numbers between 31 and 39 \( = \frac{39 + 34 + 36 + 38}{4} = \frac{140}{4} = {35}\)
DATA HANDLING
300068
The median of the data 9, 12, 11, 10, 8, 9, 11 is:
1 10
2 11
3 9
4 None of these
Explanation:
10 Arranging the given data in increasing order, we get 8, 9, 9, 10, 11, 11, 12 As the number of observations is odd (7), the median is the middle term which is 10 Hence, the correct option is (a).
DATA HANDLING
300255
The arithinetic mean of 5, 6, 8, 9, 12, 13, 17 is:
1 20
2 15
3 10
4 25
Explanation:
10 Mean \( =\frac{ \text{Sum of observations}}{\text{Total number of observations}} = \frac{5+6+8+9+12+13+17}{7} = \frac{70}{7} = {10}\)
DATA HANDLING
300300
Taras three bowling scores in a tournament were 167, 178, and 186. What was her average score for the tournament?
1 176
2 177
3 178
4 179
5 180
Explanation:
177 Three bowling scores of tournament are 167, 178 and 186. \(\text{Average score will be } = \frac{167+178+186}{3} = {177}\)
DATA HANDLING
300253
The mean of ten items is x and if each item is increased by 4, then its mean will be ........
1 x + 4
2 4x
3 10x
4 10 + x
Explanation:
x + 4 \(\text{We know x} = \frac{\text{sum}}{10}\) Thus = 10x If each term is increased by 4, new sum = sum + 10 × 4 new sum = 10x + 40 New mean \( = \frac{10{\text{x}}+40}{10}\therefore {\text{new mean}} = \text{x+4}\)
