300140
\(\frac{\text{N(E)}}{\text{N(S)}}\) is the formula of:
1 Mean
2 Median
3 Mode
4 Probability
Explanation:
Probability Probability of occurrence of event E is P (E) \( = \frac{\text{N(E)}}{\text{N(S)}}\) where n (E) is no. of cases favorable to event E and n (S) is total no. of cases.
DATA HANDLING
300141
The range of observations 2, 3, 5, 9, 8, 7, 6, 5, 7, 4, 3 is:
1 6
2 7
3 5.5
4 11
Explanation:
7 Largest and Smallest term in the given observation are x\(_{\1}\)= 2 and x\(_{\1}\)? = 9 hence Range of the given distribution is = x\(_{\1}\)? - x\(_{\1}\) ?= 7
DATA HANDLING
300142
If the mean of x and \(\frac{1}{\text{x}}\) is M, then the mean of x\(^{\1}\) and \(\frac{1}{\text{x}{^{2}}}\) is:
1 M\(^{\1}\)
2 2M\(^{\1}\)+1
3 2M\(^{\1}\)−1
4 \(\frac{\text{m}^{2}}{4}\)
Explanation:
2M\(^{\1}\)−1
DATA HANDLING
300143
The mean of first seven even natural numbers is:
1 7
2 8
3 9
4 6
Explanation:
8 The first seven even natural numbers are: 2, 4, 6, 8, 10, 12, 14 \(\text{Mean}=\frac{\text{Sum of observations}}{\text{Number of observations}}\) \(=\frac{2+4+6+8+10+12+14}{7}\) \(=\frac{56}{7}\) \(=8\) Thus, the mean of first seven even natural number is 8 Hence, the correct option is (b).
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DATA HANDLING
300140
\(\frac{\text{N(E)}}{\text{N(S)}}\) is the formula of:
1 Mean
2 Median
3 Mode
4 Probability
Explanation:
Probability Probability of occurrence of event E is P (E) \( = \frac{\text{N(E)}}{\text{N(S)}}\) where n (E) is no. of cases favorable to event E and n (S) is total no. of cases.
DATA HANDLING
300141
The range of observations 2, 3, 5, 9, 8, 7, 6, 5, 7, 4, 3 is:
1 6
2 7
3 5.5
4 11
Explanation:
7 Largest and Smallest term in the given observation are x\(_{\1}\)= 2 and x\(_{\1}\)? = 9 hence Range of the given distribution is = x\(_{\1}\)? - x\(_{\1}\) ?= 7
DATA HANDLING
300142
If the mean of x and \(\frac{1}{\text{x}}\) is M, then the mean of x\(^{\1}\) and \(\frac{1}{\text{x}{^{2}}}\) is:
1 M\(^{\1}\)
2 2M\(^{\1}\)+1
3 2M\(^{\1}\)−1
4 \(\frac{\text{m}^{2}}{4}\)
Explanation:
2M\(^{\1}\)−1
DATA HANDLING
300143
The mean of first seven even natural numbers is:
1 7
2 8
3 9
4 6
Explanation:
8 The first seven even natural numbers are: 2, 4, 6, 8, 10, 12, 14 \(\text{Mean}=\frac{\text{Sum of observations}}{\text{Number of observations}}\) \(=\frac{2+4+6+8+10+12+14}{7}\) \(=\frac{56}{7}\) \(=8\) Thus, the mean of first seven even natural number is 8 Hence, the correct option is (b).
300140
\(\frac{\text{N(E)}}{\text{N(S)}}\) is the formula of:
1 Mean
2 Median
3 Mode
4 Probability
Explanation:
Probability Probability of occurrence of event E is P (E) \( = \frac{\text{N(E)}}{\text{N(S)}}\) where n (E) is no. of cases favorable to event E and n (S) is total no. of cases.
DATA HANDLING
300141
The range of observations 2, 3, 5, 9, 8, 7, 6, 5, 7, 4, 3 is:
1 6
2 7
3 5.5
4 11
Explanation:
7 Largest and Smallest term in the given observation are x\(_{\1}\)= 2 and x\(_{\1}\)? = 9 hence Range of the given distribution is = x\(_{\1}\)? - x\(_{\1}\) ?= 7
DATA HANDLING
300142
If the mean of x and \(\frac{1}{\text{x}}\) is M, then the mean of x\(^{\1}\) and \(\frac{1}{\text{x}{^{2}}}\) is:
1 M\(^{\1}\)
2 2M\(^{\1}\)+1
3 2M\(^{\1}\)−1
4 \(\frac{\text{m}^{2}}{4}\)
Explanation:
2M\(^{\1}\)−1
DATA HANDLING
300143
The mean of first seven even natural numbers is:
1 7
2 8
3 9
4 6
Explanation:
8 The first seven even natural numbers are: 2, 4, 6, 8, 10, 12, 14 \(\text{Mean}=\frac{\text{Sum of observations}}{\text{Number of observations}}\) \(=\frac{2+4+6+8+10+12+14}{7}\) \(=\frac{56}{7}\) \(=8\) Thus, the mean of first seven even natural number is 8 Hence, the correct option is (b).
300140
\(\frac{\text{N(E)}}{\text{N(S)}}\) is the formula of:
1 Mean
2 Median
3 Mode
4 Probability
Explanation:
Probability Probability of occurrence of event E is P (E) \( = \frac{\text{N(E)}}{\text{N(S)}}\) where n (E) is no. of cases favorable to event E and n (S) is total no. of cases.
DATA HANDLING
300141
The range of observations 2, 3, 5, 9, 8, 7, 6, 5, 7, 4, 3 is:
1 6
2 7
3 5.5
4 11
Explanation:
7 Largest and Smallest term in the given observation are x\(_{\1}\)= 2 and x\(_{\1}\)? = 9 hence Range of the given distribution is = x\(_{\1}\)? - x\(_{\1}\) ?= 7
DATA HANDLING
300142
If the mean of x and \(\frac{1}{\text{x}}\) is M, then the mean of x\(^{\1}\) and \(\frac{1}{\text{x}{^{2}}}\) is:
1 M\(^{\1}\)
2 2M\(^{\1}\)+1
3 2M\(^{\1}\)−1
4 \(\frac{\text{m}^{2}}{4}\)
Explanation:
2M\(^{\1}\)−1
DATA HANDLING
300143
The mean of first seven even natural numbers is:
1 7
2 8
3 9
4 6
Explanation:
8 The first seven even natural numbers are: 2, 4, 6, 8, 10, 12, 14 \(\text{Mean}=\frac{\text{Sum of observations}}{\text{Number of observations}}\) \(=\frac{2+4+6+8+10+12+14}{7}\) \(=\frac{56}{7}\) \(=8\) Thus, the mean of first seven even natural number is 8 Hence, the correct option is (b).