04. DECIMALS
04. DECIMALS

290910 The number of digits in the decimal expansion of 16\(^{1}\) 5\(^{1}\) is.

1 16
2 17
3 18
4 19
04. DECIMALS

290911 The value of 0.0001289 - 0.0000000274 × 1293 + 0.0000419032 is _________?

1 0.0135375
2 0.000153357
3 135375000
4 0.166632277
04. DECIMALS

290912 Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion (A): 5kg=5000gm.
Reason (R): The unit of measurement for weight is that of force , which in the international sysrtem of units is Newton.

1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
04. DECIMALS

290913 Mark \((\checkmark)\) against the correct answer in the following:
The place value of 3 in 16.534 is:

1 \(\frac{3}{10}\)
2 \(\frac{3}{100}\)
3 \(\frac{3}{1000}\)
4 \(3\)
04. DECIMALS

290910 The number of digits in the decimal expansion of 16\(^{1}\) 5\(^{1}\) is.

1 16
2 17
3 18
4 19
04. DECIMALS

290911 The value of 0.0001289 - 0.0000000274 × 1293 + 0.0000419032 is _________?

1 0.0135375
2 0.000153357
3 135375000
4 0.166632277
04. DECIMALS

290912 Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion (A): 5kg=5000gm.
Reason (R): The unit of measurement for weight is that of force , which in the international sysrtem of units is Newton.

1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
04. DECIMALS

290913 Mark \((\checkmark)\) against the correct answer in the following:
The place value of 3 in 16.534 is:

1 \(\frac{3}{10}\)
2 \(\frac{3}{100}\)
3 \(\frac{3}{1000}\)
4 \(3\)
04. DECIMALS

290910 The number of digits in the decimal expansion of 16\(^{1}\) 5\(^{1}\) is.

1 16
2 17
3 18
4 19
04. DECIMALS

290911 The value of 0.0001289 - 0.0000000274 × 1293 + 0.0000419032 is _________?

1 0.0135375
2 0.000153357
3 135375000
4 0.166632277
04. DECIMALS

290912 Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion (A): 5kg=5000gm.
Reason (R): The unit of measurement for weight is that of force , which in the international sysrtem of units is Newton.

1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
04. DECIMALS

290913 Mark \((\checkmark)\) against the correct answer in the following:
The place value of 3 in 16.534 is:

1 \(\frac{3}{10}\)
2 \(\frac{3}{100}\)
3 \(\frac{3}{1000}\)
4 \(3\)
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04. DECIMALS

290910 The number of digits in the decimal expansion of 16\(^{1}\) 5\(^{1}\) is.

1 16
2 17
3 18
4 19
04. DECIMALS

290911 The value of 0.0001289 - 0.0000000274 × 1293 + 0.0000419032 is _________?

1 0.0135375
2 0.000153357
3 135375000
4 0.166632277
04. DECIMALS

290912 Directions: In the following questions, the Assertions (A) and Reason(s) (R) have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion (A): 5kg=5000gm.
Reason (R): The unit of measurement for weight is that of force , which in the international sysrtem of units is Newton.

1 Both A and R are true and R is the correct explanation of A.
2 Both A and R are true but R is not the correct explanation of A.
3 A is true but R is false.
4 A is false but R is true.
04. DECIMALS

290913 Mark \((\checkmark)\) against the correct answer in the following:
The place value of 3 in 16.534 is:

1 \(\frac{3}{10}\)
2 \(\frac{3}{100}\)
3 \(\frac{3}{1000}\)
4 \(3\)