290216
Length of a rectangle is 8 cm longer than its width. A square of side x centimeters is cut out of it. If x centimeters is half the width of the rectangle, then the remaining area in square centimeters is
1 3x\(^{1}\) + 16x
2 2x\(^{1}\) + 8x
3 3x\(^{1}\) + 8x
4 2x\(^{1}\) + 16x
Explanation:
3x\(^{1}\) + 16x If\ width=W,length=8+W\\ W=\dfrac x 2........ given\\\\ Total\ area\ of\ rectangle=W(8+W)\\ =2x(8+2x)\\\\ =16x+{ 4x }^{ 2 }-{ x }^{ 2 }\\\\ ={ 3x }^{ 2 }+16x\\\\If width=W,length=8+WW=2x?........givenTotal area of rectangle=W(8+W)=2x(8+2x)=16x+4x2-x2=3x2+16x
09. MENSURATION
290217
If the side of a square park is 5m then its perimeter is:
1 10m
2 25m
3 20m
4 15m
Explanation:
20m We know, Perimeter = 4 × side = 4 × 5 = 20m
09. MENSURATION
290218
If the perimeter of a square is (4y + 12)m, then the length of its diagonal is:
1 \(\frac{\text{y+3}}{\sqrt{2}}\text{m}\)
2 \(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\)
3 \(\sqrt{2} \big(\text{4y} + {12}\big)\text{m}\)
4 \(\frac{4\text{y}+12}{\sqrt2}\text{m}\)
Explanation:
\(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\) Consider the given perimeter of the square is = ( 4y + 12 )m We know, perimeter of the square = 4 × side (4y + 12) = 4 × side. \(\text{ side } \frac{4\text{y}+12}{4} = \text{y} + {3}\) Now, length of diagonal of the square \( = \sqrt{(\text{side})^{2} + (\text{side}^{2})}\) \(= \sqrt{(\text{y+3}^{2} + (\text{y + 3})^{2}}\) \( = \sqrt{2}.(\text{y} + {3})\text{m}\)
09. MENSURATION
290219
The perimeter and area of square is same. find its side:
1 4
2 8
3 16
4 64
Explanation:
4 Let the side of square be a Perimeter is 4a Area of square is a\(^{1}\) According to question 4a = a\(^{1}\) a\(^{1}\)- 4a = 0 a(a - 4) = 0 either a = 0 or a =4 \(\therefore\) 0 cant be taken as a measure length
09. MENSURATION
290220
Im going to place a rope around the perimeter of our school playground that is in the shape of an octagon. The sides are 10m, 10m, 8m, 8m, 5m, 5m, 9m, and 9m, How many metres of rope will be needed for the perimeter?
1 164m
2 38m
3 64m
4 138m
Explanation:
64m Length of Rope required = Perimeter of the School Playground Perimeter is the sum of all sides of the polygon. Here, the school playground is in the form of an octagon with sides. as 10m,10m, 8m, 8m, 5m, 5m, 9m, 9 mPerimeter = 10 + 10 + 8 + 8 + 5 + 5 + 9 + 9 = 64 Length of rope required = 64 m
290216
Length of a rectangle is 8 cm longer than its width. A square of side x centimeters is cut out of it. If x centimeters is half the width of the rectangle, then the remaining area in square centimeters is
1 3x\(^{1}\) + 16x
2 2x\(^{1}\) + 8x
3 3x\(^{1}\) + 8x
4 2x\(^{1}\) + 16x
Explanation:
3x\(^{1}\) + 16x If\ width=W,length=8+W\\ W=\dfrac x 2........ given\\\\ Total\ area\ of\ rectangle=W(8+W)\\ =2x(8+2x)\\\\ =16x+{ 4x }^{ 2 }-{ x }^{ 2 }\\\\ ={ 3x }^{ 2 }+16x\\\\If width=W,length=8+WW=2x?........givenTotal area of rectangle=W(8+W)=2x(8+2x)=16x+4x2-x2=3x2+16x
09. MENSURATION
290217
If the side of a square park is 5m then its perimeter is:
1 10m
2 25m
3 20m
4 15m
Explanation:
20m We know, Perimeter = 4 × side = 4 × 5 = 20m
09. MENSURATION
290218
If the perimeter of a square is (4y + 12)m, then the length of its diagonal is:
1 \(\frac{\text{y+3}}{\sqrt{2}}\text{m}\)
2 \(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\)
3 \(\sqrt{2} \big(\text{4y} + {12}\big)\text{m}\)
4 \(\frac{4\text{y}+12}{\sqrt2}\text{m}\)
Explanation:
\(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\) Consider the given perimeter of the square is = ( 4y + 12 )m We know, perimeter of the square = 4 × side (4y + 12) = 4 × side. \(\text{ side } \frac{4\text{y}+12}{4} = \text{y} + {3}\) Now, length of diagonal of the square \( = \sqrt{(\text{side})^{2} + (\text{side}^{2})}\) \(= \sqrt{(\text{y+3}^{2} + (\text{y + 3})^{2}}\) \( = \sqrt{2}.(\text{y} + {3})\text{m}\)
09. MENSURATION
290219
The perimeter and area of square is same. find its side:
1 4
2 8
3 16
4 64
Explanation:
4 Let the side of square be a Perimeter is 4a Area of square is a\(^{1}\) According to question 4a = a\(^{1}\) a\(^{1}\)- 4a = 0 a(a - 4) = 0 either a = 0 or a =4 \(\therefore\) 0 cant be taken as a measure length
09. MENSURATION
290220
Im going to place a rope around the perimeter of our school playground that is in the shape of an octagon. The sides are 10m, 10m, 8m, 8m, 5m, 5m, 9m, and 9m, How many metres of rope will be needed for the perimeter?
1 164m
2 38m
3 64m
4 138m
Explanation:
64m Length of Rope required = Perimeter of the School Playground Perimeter is the sum of all sides of the polygon. Here, the school playground is in the form of an octagon with sides. as 10m,10m, 8m, 8m, 5m, 5m, 9m, 9 mPerimeter = 10 + 10 + 8 + 8 + 5 + 5 + 9 + 9 = 64 Length of rope required = 64 m
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09. MENSURATION
290216
Length of a rectangle is 8 cm longer than its width. A square of side x centimeters is cut out of it. If x centimeters is half the width of the rectangle, then the remaining area in square centimeters is
1 3x\(^{1}\) + 16x
2 2x\(^{1}\) + 8x
3 3x\(^{1}\) + 8x
4 2x\(^{1}\) + 16x
Explanation:
3x\(^{1}\) + 16x If\ width=W,length=8+W\\ W=\dfrac x 2........ given\\\\ Total\ area\ of\ rectangle=W(8+W)\\ =2x(8+2x)\\\\ =16x+{ 4x }^{ 2 }-{ x }^{ 2 }\\\\ ={ 3x }^{ 2 }+16x\\\\If width=W,length=8+WW=2x?........givenTotal area of rectangle=W(8+W)=2x(8+2x)=16x+4x2-x2=3x2+16x
09. MENSURATION
290217
If the side of a square park is 5m then its perimeter is:
1 10m
2 25m
3 20m
4 15m
Explanation:
20m We know, Perimeter = 4 × side = 4 × 5 = 20m
09. MENSURATION
290218
If the perimeter of a square is (4y + 12)m, then the length of its diagonal is:
1 \(\frac{\text{y+3}}{\sqrt{2}}\text{m}\)
2 \(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\)
3 \(\sqrt{2} \big(\text{4y} + {12}\big)\text{m}\)
4 \(\frac{4\text{y}+12}{\sqrt2}\text{m}\)
Explanation:
\(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\) Consider the given perimeter of the square is = ( 4y + 12 )m We know, perimeter of the square = 4 × side (4y + 12) = 4 × side. \(\text{ side } \frac{4\text{y}+12}{4} = \text{y} + {3}\) Now, length of diagonal of the square \( = \sqrt{(\text{side})^{2} + (\text{side}^{2})}\) \(= \sqrt{(\text{y+3}^{2} + (\text{y + 3})^{2}}\) \( = \sqrt{2}.(\text{y} + {3})\text{m}\)
09. MENSURATION
290219
The perimeter and area of square is same. find its side:
1 4
2 8
3 16
4 64
Explanation:
4 Let the side of square be a Perimeter is 4a Area of square is a\(^{1}\) According to question 4a = a\(^{1}\) a\(^{1}\)- 4a = 0 a(a - 4) = 0 either a = 0 or a =4 \(\therefore\) 0 cant be taken as a measure length
09. MENSURATION
290220
Im going to place a rope around the perimeter of our school playground that is in the shape of an octagon. The sides are 10m, 10m, 8m, 8m, 5m, 5m, 9m, and 9m, How many metres of rope will be needed for the perimeter?
1 164m
2 38m
3 64m
4 138m
Explanation:
64m Length of Rope required = Perimeter of the School Playground Perimeter is the sum of all sides of the polygon. Here, the school playground is in the form of an octagon with sides. as 10m,10m, 8m, 8m, 5m, 5m, 9m, 9 mPerimeter = 10 + 10 + 8 + 8 + 5 + 5 + 9 + 9 = 64 Length of rope required = 64 m
290216
Length of a rectangle is 8 cm longer than its width. A square of side x centimeters is cut out of it. If x centimeters is half the width of the rectangle, then the remaining area in square centimeters is
1 3x\(^{1}\) + 16x
2 2x\(^{1}\) + 8x
3 3x\(^{1}\) + 8x
4 2x\(^{1}\) + 16x
Explanation:
3x\(^{1}\) + 16x If\ width=W,length=8+W\\ W=\dfrac x 2........ given\\\\ Total\ area\ of\ rectangle=W(8+W)\\ =2x(8+2x)\\\\ =16x+{ 4x }^{ 2 }-{ x }^{ 2 }\\\\ ={ 3x }^{ 2 }+16x\\\\If width=W,length=8+WW=2x?........givenTotal area of rectangle=W(8+W)=2x(8+2x)=16x+4x2-x2=3x2+16x
09. MENSURATION
290217
If the side of a square park is 5m then its perimeter is:
1 10m
2 25m
3 20m
4 15m
Explanation:
20m We know, Perimeter = 4 × side = 4 × 5 = 20m
09. MENSURATION
290218
If the perimeter of a square is (4y + 12)m, then the length of its diagonal is:
1 \(\frac{\text{y+3}}{\sqrt{2}}\text{m}\)
2 \(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\)
3 \(\sqrt{2} \big(\text{4y} + {12}\big)\text{m}\)
4 \(\frac{4\text{y}+12}{\sqrt2}\text{m}\)
Explanation:
\(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\) Consider the given perimeter of the square is = ( 4y + 12 )m We know, perimeter of the square = 4 × side (4y + 12) = 4 × side. \(\text{ side } \frac{4\text{y}+12}{4} = \text{y} + {3}\) Now, length of diagonal of the square \( = \sqrt{(\text{side})^{2} + (\text{side}^{2})}\) \(= \sqrt{(\text{y+3}^{2} + (\text{y + 3})^{2}}\) \( = \sqrt{2}.(\text{y} + {3})\text{m}\)
09. MENSURATION
290219
The perimeter and area of square is same. find its side:
1 4
2 8
3 16
4 64
Explanation:
4 Let the side of square be a Perimeter is 4a Area of square is a\(^{1}\) According to question 4a = a\(^{1}\) a\(^{1}\)- 4a = 0 a(a - 4) = 0 either a = 0 or a =4 \(\therefore\) 0 cant be taken as a measure length
09. MENSURATION
290220
Im going to place a rope around the perimeter of our school playground that is in the shape of an octagon. The sides are 10m, 10m, 8m, 8m, 5m, 5m, 9m, and 9m, How many metres of rope will be needed for the perimeter?
1 164m
2 38m
3 64m
4 138m
Explanation:
64m Length of Rope required = Perimeter of the School Playground Perimeter is the sum of all sides of the polygon. Here, the school playground is in the form of an octagon with sides. as 10m,10m, 8m, 8m, 5m, 5m, 9m, 9 mPerimeter = 10 + 10 + 8 + 8 + 5 + 5 + 9 + 9 = 64 Length of rope required = 64 m
290216
Length of a rectangle is 8 cm longer than its width. A square of side x centimeters is cut out of it. If x centimeters is half the width of the rectangle, then the remaining area in square centimeters is
1 3x\(^{1}\) + 16x
2 2x\(^{1}\) + 8x
3 3x\(^{1}\) + 8x
4 2x\(^{1}\) + 16x
Explanation:
3x\(^{1}\) + 16x If\ width=W,length=8+W\\ W=\dfrac x 2........ given\\\\ Total\ area\ of\ rectangle=W(8+W)\\ =2x(8+2x)\\\\ =16x+{ 4x }^{ 2 }-{ x }^{ 2 }\\\\ ={ 3x }^{ 2 }+16x\\\\If width=W,length=8+WW=2x?........givenTotal area of rectangle=W(8+W)=2x(8+2x)=16x+4x2-x2=3x2+16x
09. MENSURATION
290217
If the side of a square park is 5m then its perimeter is:
1 10m
2 25m
3 20m
4 15m
Explanation:
20m We know, Perimeter = 4 × side = 4 × 5 = 20m
09. MENSURATION
290218
If the perimeter of a square is (4y + 12)m, then the length of its diagonal is:
1 \(\frac{\text{y+3}}{\sqrt{2}}\text{m}\)
2 \(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\)
3 \(\sqrt{2} \big(\text{4y} + {12}\big)\text{m}\)
4 \(\frac{4\text{y}+12}{\sqrt2}\text{m}\)
Explanation:
\(\sqrt{2} \big(\text{y} + {3}\big)\text{m}\) Consider the given perimeter of the square is = ( 4y + 12 )m We know, perimeter of the square = 4 × side (4y + 12) = 4 × side. \(\text{ side } \frac{4\text{y}+12}{4} = \text{y} + {3}\) Now, length of diagonal of the square \( = \sqrt{(\text{side})^{2} + (\text{side}^{2})}\) \(= \sqrt{(\text{y+3}^{2} + (\text{y + 3})^{2}}\) \( = \sqrt{2}.(\text{y} + {3})\text{m}\)
09. MENSURATION
290219
The perimeter and area of square is same. find its side:
1 4
2 8
3 16
4 64
Explanation:
4 Let the side of square be a Perimeter is 4a Area of square is a\(^{1}\) According to question 4a = a\(^{1}\) a\(^{1}\)- 4a = 0 a(a - 4) = 0 either a = 0 or a =4 \(\therefore\) 0 cant be taken as a measure length
09. MENSURATION
290220
Im going to place a rope around the perimeter of our school playground that is in the shape of an octagon. The sides are 10m, 10m, 8m, 8m, 5m, 5m, 9m, and 9m, How many metres of rope will be needed for the perimeter?
1 164m
2 38m
3 64m
4 138m
Explanation:
64m Length of Rope required = Perimeter of the School Playground Perimeter is the sum of all sides of the polygon. Here, the school playground is in the form of an octagon with sides. as 10m,10m, 8m, 8m, 5m, 5m, 9m, 9 mPerimeter = 10 + 10 + 8 + 8 + 5 + 5 + 9 + 9 = 64 Length of rope required = 64 m