290149
In a square shaped park whose side measures 28m a rectangular pond is located at the centre with dimension 3m and 2m the area of the park excluding the pond is:
1 784sq m
2 6sq m
3 778sq m
4 708sq m
Explanation:
778sq m Area of pond = 3m × 2m = 6sq m area of park = 28 × 28 = 784sq m area of the park excluding the pond = 784 - 6 = 778sq m
09. MENSURATION
290150
The area of a rectangle is 650cm\(^{1}\) and its breadth is 13cm. the perimeter of the rectangle is:
1 63cm
2 130cm
3 100cm
4 126cm
Explanation:
126cm Area of the rectangle = 650cm2 Breadth = 13cm Length = Area breadth \( = \frac{650}{13}\) = 50cm Perimeter = 2(length + breadth) = 2(50 + 13)cm = 2(63) = 126cm
09. MENSURATION
290151
Mark \((\checkmark)\) against the correct answer in the following: The cost of fencing a rectangular field at Rs. 30 per meter is Rs. 2400. If the length of the field is 24m, then its breadth is:
1 8m
2 16m
3 18m
4 24m
Explanation:
16m Total cost of fencing = Rs. 2400 Rate = Rs. 30 per m Perimeter of the rectangular field \(=\frac{2400}{30}\) = 80m \(\therefore\) Length + breadth \(=\frac{80}{2}\) = 40m Length of field = 24m \(\therefore\) Breadth = 40 - 24 = 16m
09. MENSURATION
290152
Mark the correct alternative in the following question: If the diagonal of a square is \(\sqrt{18}\) metre, then its area is:
1 8m\(^{1}\)
2 4m\(^{1}\)
3 16m\(^{1}\)
4 6m\(^{1}\)
Explanation:
4m\(^{1}\) We have, length of the diagonal of the square \(=\sqrt{8}\text{cm}\) Now, the area of the square \(=\frac{1}{2}\times\text{diagonal}\times\text{diagonal}\) \(=\frac{1}{2}\times\sqrt{8}\times\sqrt{8}\) \(=\frac{8}{2}\) \(=4\text{m}^{2}\)
290149
In a square shaped park whose side measures 28m a rectangular pond is located at the centre with dimension 3m and 2m the area of the park excluding the pond is:
1 784sq m
2 6sq m
3 778sq m
4 708sq m
Explanation:
778sq m Area of pond = 3m × 2m = 6sq m area of park = 28 × 28 = 784sq m area of the park excluding the pond = 784 - 6 = 778sq m
09. MENSURATION
290150
The area of a rectangle is 650cm\(^{1}\) and its breadth is 13cm. the perimeter of the rectangle is:
1 63cm
2 130cm
3 100cm
4 126cm
Explanation:
126cm Area of the rectangle = 650cm2 Breadth = 13cm Length = Area breadth \( = \frac{650}{13}\) = 50cm Perimeter = 2(length + breadth) = 2(50 + 13)cm = 2(63) = 126cm
09. MENSURATION
290151
Mark \((\checkmark)\) against the correct answer in the following: The cost of fencing a rectangular field at Rs. 30 per meter is Rs. 2400. If the length of the field is 24m, then its breadth is:
1 8m
2 16m
3 18m
4 24m
Explanation:
16m Total cost of fencing = Rs. 2400 Rate = Rs. 30 per m Perimeter of the rectangular field \(=\frac{2400}{30}\) = 80m \(\therefore\) Length + breadth \(=\frac{80}{2}\) = 40m Length of field = 24m \(\therefore\) Breadth = 40 - 24 = 16m
09. MENSURATION
290152
Mark the correct alternative in the following question: If the diagonal of a square is \(\sqrt{18}\) metre, then its area is:
1 8m\(^{1}\)
2 4m\(^{1}\)
3 16m\(^{1}\)
4 6m\(^{1}\)
Explanation:
4m\(^{1}\) We have, length of the diagonal of the square \(=\sqrt{8}\text{cm}\) Now, the area of the square \(=\frac{1}{2}\times\text{diagonal}\times\text{diagonal}\) \(=\frac{1}{2}\times\sqrt{8}\times\sqrt{8}\) \(=\frac{8}{2}\) \(=4\text{m}^{2}\)
290149
In a square shaped park whose side measures 28m a rectangular pond is located at the centre with dimension 3m and 2m the area of the park excluding the pond is:
1 784sq m
2 6sq m
3 778sq m
4 708sq m
Explanation:
778sq m Area of pond = 3m × 2m = 6sq m area of park = 28 × 28 = 784sq m area of the park excluding the pond = 784 - 6 = 778sq m
09. MENSURATION
290150
The area of a rectangle is 650cm\(^{1}\) and its breadth is 13cm. the perimeter of the rectangle is:
1 63cm
2 130cm
3 100cm
4 126cm
Explanation:
126cm Area of the rectangle = 650cm2 Breadth = 13cm Length = Area breadth \( = \frac{650}{13}\) = 50cm Perimeter = 2(length + breadth) = 2(50 + 13)cm = 2(63) = 126cm
09. MENSURATION
290151
Mark \((\checkmark)\) against the correct answer in the following: The cost of fencing a rectangular field at Rs. 30 per meter is Rs. 2400. If the length of the field is 24m, then its breadth is:
1 8m
2 16m
3 18m
4 24m
Explanation:
16m Total cost of fencing = Rs. 2400 Rate = Rs. 30 per m Perimeter of the rectangular field \(=\frac{2400}{30}\) = 80m \(\therefore\) Length + breadth \(=\frac{80}{2}\) = 40m Length of field = 24m \(\therefore\) Breadth = 40 - 24 = 16m
09. MENSURATION
290152
Mark the correct alternative in the following question: If the diagonal of a square is \(\sqrt{18}\) metre, then its area is:
1 8m\(^{1}\)
2 4m\(^{1}\)
3 16m\(^{1}\)
4 6m\(^{1}\)
Explanation:
4m\(^{1}\) We have, length of the diagonal of the square \(=\sqrt{8}\text{cm}\) Now, the area of the square \(=\frac{1}{2}\times\text{diagonal}\times\text{diagonal}\) \(=\frac{1}{2}\times\sqrt{8}\times\sqrt{8}\) \(=\frac{8}{2}\) \(=4\text{m}^{2}\)
290149
In a square shaped park whose side measures 28m a rectangular pond is located at the centre with dimension 3m and 2m the area of the park excluding the pond is:
1 784sq m
2 6sq m
3 778sq m
4 708sq m
Explanation:
778sq m Area of pond = 3m × 2m = 6sq m area of park = 28 × 28 = 784sq m area of the park excluding the pond = 784 - 6 = 778sq m
09. MENSURATION
290150
The area of a rectangle is 650cm\(^{1}\) and its breadth is 13cm. the perimeter of the rectangle is:
1 63cm
2 130cm
3 100cm
4 126cm
Explanation:
126cm Area of the rectangle = 650cm2 Breadth = 13cm Length = Area breadth \( = \frac{650}{13}\) = 50cm Perimeter = 2(length + breadth) = 2(50 + 13)cm = 2(63) = 126cm
09. MENSURATION
290151
Mark \((\checkmark)\) against the correct answer in the following: The cost of fencing a rectangular field at Rs. 30 per meter is Rs. 2400. If the length of the field is 24m, then its breadth is:
1 8m
2 16m
3 18m
4 24m
Explanation:
16m Total cost of fencing = Rs. 2400 Rate = Rs. 30 per m Perimeter of the rectangular field \(=\frac{2400}{30}\) = 80m \(\therefore\) Length + breadth \(=\frac{80}{2}\) = 40m Length of field = 24m \(\therefore\) Breadth = 40 - 24 = 16m
09. MENSURATION
290152
Mark the correct alternative in the following question: If the diagonal of a square is \(\sqrt{18}\) metre, then its area is:
1 8m\(^{1}\)
2 4m\(^{1}\)
3 16m\(^{1}\)
4 6m\(^{1}\)
Explanation:
4m\(^{1}\) We have, length of the diagonal of the square \(=\sqrt{8}\text{cm}\) Now, the area of the square \(=\frac{1}{2}\times\text{diagonal}\times\text{diagonal}\) \(=\frac{1}{2}\times\sqrt{8}\times\sqrt{8}\) \(=\frac{8}{2}\) \(=4\text{m}^{2}\)
