290141
Find the perimeter of a square of length 25cm:
1 625cm
2 100cm
3 125cm
4 25cm
Explanation:
100cm We have the perimeter of a square = 4 × a the perimeter of a square of length 25cm is = 4 × 25 = 100cm.
09. MENSURATION
290142
Two regular Hexagons of perimeter 30cm each are joined as shown in Fig. The perimeter of the new figure is:
1 65cm
2 60cm
3 55cm
4 50cm
Explanation:
50cm Given, perimeter of hexagon = 30cm and number of sides in hexagon = 6 \(\therefore\) Length of one side \(=\frac{\text{Perimeter of hexagon}}{\text{Total number of sides}}\) \(=\frac{30}{6}\) \(=5\text{cm}\) 0 Now, two hexagons are joined then perimeter = Sum of all sides = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JA = 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 50cm
09. MENSURATION
290143
If a regular hexagon is inscribed in a circle of radius r, then its perimeter is:
1 3r
2 6r
3 9r
4 12r
Explanation:
6r Angle subtended by each side of hexagon at centre of circle is 60\(^{1}\). Thus six equilateral triangles form and each side is of length r and so perimeter = 6r.
09. MENSURATION
290144
The perimeter of a rectangle whose length (l) and breadth (b) are given, is:
1 2(l + b)
2 2l + b
3 2l + 3b
4 None of these
Explanation:
2(l + b) Perimeter of a rectangle is the sum of all its four sides. Since, two sides measure l and the other two sides measure b, Perimeter of a rectangle whose length (l) and breadth (b) are given, is l + b + l + b = 2(l + b)
290141
Find the perimeter of a square of length 25cm:
1 625cm
2 100cm
3 125cm
4 25cm
Explanation:
100cm We have the perimeter of a square = 4 × a the perimeter of a square of length 25cm is = 4 × 25 = 100cm.
09. MENSURATION
290142
Two regular Hexagons of perimeter 30cm each are joined as shown in Fig. The perimeter of the new figure is:
1 65cm
2 60cm
3 55cm
4 50cm
Explanation:
50cm Given, perimeter of hexagon = 30cm and number of sides in hexagon = 6 \(\therefore\) Length of one side \(=\frac{\text{Perimeter of hexagon}}{\text{Total number of sides}}\) \(=\frac{30}{6}\) \(=5\text{cm}\) 0 Now, two hexagons are joined then perimeter = Sum of all sides = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JA = 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 50cm
09. MENSURATION
290143
If a regular hexagon is inscribed in a circle of radius r, then its perimeter is:
1 3r
2 6r
3 9r
4 12r
Explanation:
6r Angle subtended by each side of hexagon at centre of circle is 60\(^{1}\). Thus six equilateral triangles form and each side is of length r and so perimeter = 6r.
09. MENSURATION
290144
The perimeter of a rectangle whose length (l) and breadth (b) are given, is:
1 2(l + b)
2 2l + b
3 2l + 3b
4 None of these
Explanation:
2(l + b) Perimeter of a rectangle is the sum of all its four sides. Since, two sides measure l and the other two sides measure b, Perimeter of a rectangle whose length (l) and breadth (b) are given, is l + b + l + b = 2(l + b)
290141
Find the perimeter of a square of length 25cm:
1 625cm
2 100cm
3 125cm
4 25cm
Explanation:
100cm We have the perimeter of a square = 4 × a the perimeter of a square of length 25cm is = 4 × 25 = 100cm.
09. MENSURATION
290142
Two regular Hexagons of perimeter 30cm each are joined as shown in Fig. The perimeter of the new figure is:
1 65cm
2 60cm
3 55cm
4 50cm
Explanation:
50cm Given, perimeter of hexagon = 30cm and number of sides in hexagon = 6 \(\therefore\) Length of one side \(=\frac{\text{Perimeter of hexagon}}{\text{Total number of sides}}\) \(=\frac{30}{6}\) \(=5\text{cm}\) 0 Now, two hexagons are joined then perimeter = Sum of all sides = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JA = 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 50cm
09. MENSURATION
290143
If a regular hexagon is inscribed in a circle of radius r, then its perimeter is:
1 3r
2 6r
3 9r
4 12r
Explanation:
6r Angle subtended by each side of hexagon at centre of circle is 60\(^{1}\). Thus six equilateral triangles form and each side is of length r and so perimeter = 6r.
09. MENSURATION
290144
The perimeter of a rectangle whose length (l) and breadth (b) are given, is:
1 2(l + b)
2 2l + b
3 2l + 3b
4 None of these
Explanation:
2(l + b) Perimeter of a rectangle is the sum of all its four sides. Since, two sides measure l and the other two sides measure b, Perimeter of a rectangle whose length (l) and breadth (b) are given, is l + b + l + b = 2(l + b)
290141
Find the perimeter of a square of length 25cm:
1 625cm
2 100cm
3 125cm
4 25cm
Explanation:
100cm We have the perimeter of a square = 4 × a the perimeter of a square of length 25cm is = 4 × 25 = 100cm.
09. MENSURATION
290142
Two regular Hexagons of perimeter 30cm each are joined as shown in Fig. The perimeter of the new figure is:
1 65cm
2 60cm
3 55cm
4 50cm
Explanation:
50cm Given, perimeter of hexagon = 30cm and number of sides in hexagon = 6 \(\therefore\) Length of one side \(=\frac{\text{Perimeter of hexagon}}{\text{Total number of sides}}\) \(=\frac{30}{6}\) \(=5\text{cm}\) 0 Now, two hexagons are joined then perimeter = Sum of all sides = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JA = 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 50cm
09. MENSURATION
290143
If a regular hexagon is inscribed in a circle of radius r, then its perimeter is:
1 3r
2 6r
3 9r
4 12r
Explanation:
6r Angle subtended by each side of hexagon at centre of circle is 60\(^{1}\). Thus six equilateral triangles form and each side is of length r and so perimeter = 6r.
09. MENSURATION
290144
The perimeter of a rectangle whose length (l) and breadth (b) are given, is:
1 2(l + b)
2 2l + b
3 2l + 3b
4 None of these
Explanation:
2(l + b) Perimeter of a rectangle is the sum of all its four sides. Since, two sides measure l and the other two sides measure b, Perimeter of a rectangle whose length (l) and breadth (b) are given, is l + b + l + b = 2(l + b)
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