287353
The product of a whole number (other than zero) and its successor is:
1 An even number.
2 An odd number.
3 Divisible by 4
4 Divisible by 3
Explanation:
An even number. Solution: We have: Whole number = 1 Successor of 1 = 1 + 1 = 2 Their product = 1 × 2 = 2 Thus, 2 is an even number.
01. WHOLE NUMBERS
287354
The product of the predecessor and successor of an odd natural number is always divisible by:
1 2
2 4
3 6
4 8
Explanation:
8 Solution: The predecessor of an odd number is an even number. The successor of an odd number is also an even number. These two even numbers are two consecutive even numbers, and the product of two consecutive even numbers is always divisible by 8.
01. WHOLE NUMBERS
287355
In a division sum, we have dividend = 199, quotient = 16 and remainder = 7. The divisor is:
287353
The product of a whole number (other than zero) and its successor is:
1 An even number.
2 An odd number.
3 Divisible by 4
4 Divisible by 3
Explanation:
An even number. Solution: We have: Whole number = 1 Successor of 1 = 1 + 1 = 2 Their product = 1 × 2 = 2 Thus, 2 is an even number.
01. WHOLE NUMBERS
287354
The product of the predecessor and successor of an odd natural number is always divisible by:
1 2
2 4
3 6
4 8
Explanation:
8 Solution: The predecessor of an odd number is an even number. The successor of an odd number is also an even number. These two even numbers are two consecutive even numbers, and the product of two consecutive even numbers is always divisible by 8.
01. WHOLE NUMBERS
287355
In a division sum, we have dividend = 199, quotient = 16 and remainder = 7. The divisor is:
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
01. WHOLE NUMBERS
287353
The product of a whole number (other than zero) and its successor is:
1 An even number.
2 An odd number.
3 Divisible by 4
4 Divisible by 3
Explanation:
An even number. Solution: We have: Whole number = 1 Successor of 1 = 1 + 1 = 2 Their product = 1 × 2 = 2 Thus, 2 is an even number.
01. WHOLE NUMBERS
287354
The product of the predecessor and successor of an odd natural number is always divisible by:
1 2
2 4
3 6
4 8
Explanation:
8 Solution: The predecessor of an odd number is an even number. The successor of an odd number is also an even number. These two even numbers are two consecutive even numbers, and the product of two consecutive even numbers is always divisible by 8.
01. WHOLE NUMBERS
287355
In a division sum, we have dividend = 199, quotient = 16 and remainder = 7. The divisor is:
287353
The product of a whole number (other than zero) and its successor is:
1 An even number.
2 An odd number.
3 Divisible by 4
4 Divisible by 3
Explanation:
An even number. Solution: We have: Whole number = 1 Successor of 1 = 1 + 1 = 2 Their product = 1 × 2 = 2 Thus, 2 is an even number.
01. WHOLE NUMBERS
287354
The product of the predecessor and successor of an odd natural number is always divisible by:
1 2
2 4
3 6
4 8
Explanation:
8 Solution: The predecessor of an odd number is an even number. The successor of an odd number is also an even number. These two even numbers are two consecutive even numbers, and the product of two consecutive even numbers is always divisible by 8.
01. WHOLE NUMBERS
287355
In a division sum, we have dividend = 199, quotient = 16 and remainder = 7. The divisor is:
287353
The product of a whole number (other than zero) and its successor is:
1 An even number.
2 An odd number.
3 Divisible by 4
4 Divisible by 3
Explanation:
An even number. Solution: We have: Whole number = 1 Successor of 1 = 1 + 1 = 2 Their product = 1 × 2 = 2 Thus, 2 is an even number.
01. WHOLE NUMBERS
287354
The product of the predecessor and successor of an odd natural number is always divisible by:
1 2
2 4
3 6
4 8
Explanation:
8 Solution: The predecessor of an odd number is an even number. The successor of an odd number is also an even number. These two even numbers are two consecutive even numbers, and the product of two consecutive even numbers is always divisible by 8.
01. WHOLE NUMBERS
287355
In a division sum, we have dividend = 199, quotient = 16 and remainder = 7. The divisor is: