285582
Which is the most suitable reagent for the following conversion?
1 Tollens' reagent
2 Benzoyl peroxide
3 \(\mathrm{I}_2\) and NaOH solution with subsequent acidification
4 Sn andNaOH solution
Explanation:
(c)
This reaction is known as iodoform reaction.
Karnataka CET 2021
CHEMISTRY(KCET)
285583
The product '\(A\) ' gives white precipitate when treated with bromine water. The product ' \(B\) ' is treated with barium hydroxide to give the product ' \(C\) '. The compound ' \(C\) is heated strongly to form prduct ' \(D\) '.
The product ' \(D\) ' is
1 4-methylpent-3-en-2-one
2 but-2-enal
3 3-methylpent-3-en-2-one
4 2-methylbut-2-enal.
Explanation:
(a)
-
Phenol
(A)
(B)
4-Methylpent-3-en-2-one
(D)
Karnataka CET 2021
CHEMISTRY(KCET)
285585
The carbonyl compound that does not undergo aldol condensation is
1 dichloroacetaldehyde
2 trichloroacetaldehyde
3 acetaldehyde
4 acetone.
Explanation:
(b) Due to absence of \(\alpha\)-hydrogen atom, trichloroacetaldehyde does not undergo aldol condensation.
Trichloroacetaldehyde,
Karnataka CET 2020
CHEMISTRY(KCET)
285587
The reagents\(A, B\) and \(C\) respectively are
(c)
\(\therefore A=\mathrm{NaBH}_4, B=P C C\) and \(C=\mathrm{H}_2 / \mathrm{Pd} . \mathrm{NaBH}_4\) does not reduce double bond. However, catalytic hydrogenolysis \(\left(\mathrm{H}_2 / \mathrm{Pd}\right)\) reduces both double bond and the carbonyl group.
Karnataka CET 2019
CHEMISTRY(KCET)
285588
Propanoic acid undergoes HVZ reaction to give chloropropanoic acid. The product obtained is
1 stronger acid than propanoic acid
2 as stronger as propanoic acid
3 weaker acid than propanoic acid
4 stronger than dichloropropanoic acid.
Explanation:
(a) Electron withdrawing group ( -Cl group) stabilizes the carboxylate ion by dispersing the negative charge and hence increases the acidity of carboxylic acid. Therefore, chloropropanoic acid is stronger acid than propanoic acid.
285582
Which is the most suitable reagent for the following conversion?
1 Tollens' reagent
2 Benzoyl peroxide
3 \(\mathrm{I}_2\) and NaOH solution with subsequent acidification
4 Sn andNaOH solution
Explanation:
(c)
This reaction is known as iodoform reaction.
Karnataka CET 2021
CHEMISTRY(KCET)
285583
The product '\(A\) ' gives white precipitate when treated with bromine water. The product ' \(B\) ' is treated with barium hydroxide to give the product ' \(C\) '. The compound ' \(C\) is heated strongly to form prduct ' \(D\) '.
The product ' \(D\) ' is
1 4-methylpent-3-en-2-one
2 but-2-enal
3 3-methylpent-3-en-2-one
4 2-methylbut-2-enal.
Explanation:
(a)
-
Phenol
(A)
(B)
4-Methylpent-3-en-2-one
(D)
Karnataka CET 2021
CHEMISTRY(KCET)
285585
The carbonyl compound that does not undergo aldol condensation is
1 dichloroacetaldehyde
2 trichloroacetaldehyde
3 acetaldehyde
4 acetone.
Explanation:
(b) Due to absence of \(\alpha\)-hydrogen atom, trichloroacetaldehyde does not undergo aldol condensation.
Trichloroacetaldehyde,
Karnataka CET 2020
CHEMISTRY(KCET)
285587
The reagents\(A, B\) and \(C\) respectively are
(c)
\(\therefore A=\mathrm{NaBH}_4, B=P C C\) and \(C=\mathrm{H}_2 / \mathrm{Pd} . \mathrm{NaBH}_4\) does not reduce double bond. However, catalytic hydrogenolysis \(\left(\mathrm{H}_2 / \mathrm{Pd}\right)\) reduces both double bond and the carbonyl group.
Karnataka CET 2019
CHEMISTRY(KCET)
285588
Propanoic acid undergoes HVZ reaction to give chloropropanoic acid. The product obtained is
1 stronger acid than propanoic acid
2 as stronger as propanoic acid
3 weaker acid than propanoic acid
4 stronger than dichloropropanoic acid.
Explanation:
(a) Electron withdrawing group ( -Cl group) stabilizes the carboxylate ion by dispersing the negative charge and hence increases the acidity of carboxylic acid. Therefore, chloropropanoic acid is stronger acid than propanoic acid.
285582
Which is the most suitable reagent for the following conversion?
1 Tollens' reagent
2 Benzoyl peroxide
3 \(\mathrm{I}_2\) and NaOH solution with subsequent acidification
4 Sn andNaOH solution
Explanation:
(c)
This reaction is known as iodoform reaction.
Karnataka CET 2021
CHEMISTRY(KCET)
285583
The product '\(A\) ' gives white precipitate when treated with bromine water. The product ' \(B\) ' is treated with barium hydroxide to give the product ' \(C\) '. The compound ' \(C\) is heated strongly to form prduct ' \(D\) '.
The product ' \(D\) ' is
1 4-methylpent-3-en-2-one
2 but-2-enal
3 3-methylpent-3-en-2-one
4 2-methylbut-2-enal.
Explanation:
(a)
-
Phenol
(A)
(B)
4-Methylpent-3-en-2-one
(D)
Karnataka CET 2021
CHEMISTRY(KCET)
285585
The carbonyl compound that does not undergo aldol condensation is
1 dichloroacetaldehyde
2 trichloroacetaldehyde
3 acetaldehyde
4 acetone.
Explanation:
(b) Due to absence of \(\alpha\)-hydrogen atom, trichloroacetaldehyde does not undergo aldol condensation.
Trichloroacetaldehyde,
Karnataka CET 2020
CHEMISTRY(KCET)
285587
The reagents\(A, B\) and \(C\) respectively are
(c)
\(\therefore A=\mathrm{NaBH}_4, B=P C C\) and \(C=\mathrm{H}_2 / \mathrm{Pd} . \mathrm{NaBH}_4\) does not reduce double bond. However, catalytic hydrogenolysis \(\left(\mathrm{H}_2 / \mathrm{Pd}\right)\) reduces both double bond and the carbonyl group.
Karnataka CET 2019
CHEMISTRY(KCET)
285588
Propanoic acid undergoes HVZ reaction to give chloropropanoic acid. The product obtained is
1 stronger acid than propanoic acid
2 as stronger as propanoic acid
3 weaker acid than propanoic acid
4 stronger than dichloropropanoic acid.
Explanation:
(a) Electron withdrawing group ( -Cl group) stabilizes the carboxylate ion by dispersing the negative charge and hence increases the acidity of carboxylic acid. Therefore, chloropropanoic acid is stronger acid than propanoic acid.
285582
Which is the most suitable reagent for the following conversion?
1 Tollens' reagent
2 Benzoyl peroxide
3 \(\mathrm{I}_2\) and NaOH solution with subsequent acidification
4 Sn andNaOH solution
Explanation:
(c)
This reaction is known as iodoform reaction.
Karnataka CET 2021
CHEMISTRY(KCET)
285583
The product '\(A\) ' gives white precipitate when treated with bromine water. The product ' \(B\) ' is treated with barium hydroxide to give the product ' \(C\) '. The compound ' \(C\) is heated strongly to form prduct ' \(D\) '.
The product ' \(D\) ' is
1 4-methylpent-3-en-2-one
2 but-2-enal
3 3-methylpent-3-en-2-one
4 2-methylbut-2-enal.
Explanation:
(a)
-
Phenol
(A)
(B)
4-Methylpent-3-en-2-one
(D)
Karnataka CET 2021
CHEMISTRY(KCET)
285585
The carbonyl compound that does not undergo aldol condensation is
1 dichloroacetaldehyde
2 trichloroacetaldehyde
3 acetaldehyde
4 acetone.
Explanation:
(b) Due to absence of \(\alpha\)-hydrogen atom, trichloroacetaldehyde does not undergo aldol condensation.
Trichloroacetaldehyde,
Karnataka CET 2020
CHEMISTRY(KCET)
285587
The reagents\(A, B\) and \(C\) respectively are
(c)
\(\therefore A=\mathrm{NaBH}_4, B=P C C\) and \(C=\mathrm{H}_2 / \mathrm{Pd} . \mathrm{NaBH}_4\) does not reduce double bond. However, catalytic hydrogenolysis \(\left(\mathrm{H}_2 / \mathrm{Pd}\right)\) reduces both double bond and the carbonyl group.
Karnataka CET 2019
CHEMISTRY(KCET)
285588
Propanoic acid undergoes HVZ reaction to give chloropropanoic acid. The product obtained is
1 stronger acid than propanoic acid
2 as stronger as propanoic acid
3 weaker acid than propanoic acid
4 stronger than dichloropropanoic acid.
Explanation:
(a) Electron withdrawing group ( -Cl group) stabilizes the carboxylate ion by dispersing the negative charge and hence increases the acidity of carboxylic acid. Therefore, chloropropanoic acid is stronger acid than propanoic acid.
285582
Which is the most suitable reagent for the following conversion?
1 Tollens' reagent
2 Benzoyl peroxide
3 \(\mathrm{I}_2\) and NaOH solution with subsequent acidification
4 Sn andNaOH solution
Explanation:
(c)
This reaction is known as iodoform reaction.
Karnataka CET 2021
CHEMISTRY(KCET)
285583
The product '\(A\) ' gives white precipitate when treated with bromine water. The product ' \(B\) ' is treated with barium hydroxide to give the product ' \(C\) '. The compound ' \(C\) is heated strongly to form prduct ' \(D\) '.
The product ' \(D\) ' is
1 4-methylpent-3-en-2-one
2 but-2-enal
3 3-methylpent-3-en-2-one
4 2-methylbut-2-enal.
Explanation:
(a)
-
Phenol
(A)
(B)
4-Methylpent-3-en-2-one
(D)
Karnataka CET 2021
CHEMISTRY(KCET)
285585
The carbonyl compound that does not undergo aldol condensation is
1 dichloroacetaldehyde
2 trichloroacetaldehyde
3 acetaldehyde
4 acetone.
Explanation:
(b) Due to absence of \(\alpha\)-hydrogen atom, trichloroacetaldehyde does not undergo aldol condensation.
Trichloroacetaldehyde,
Karnataka CET 2020
CHEMISTRY(KCET)
285587
The reagents\(A, B\) and \(C\) respectively are
(c)
\(\therefore A=\mathrm{NaBH}_4, B=P C C\) and \(C=\mathrm{H}_2 / \mathrm{Pd} . \mathrm{NaBH}_4\) does not reduce double bond. However, catalytic hydrogenolysis \(\left(\mathrm{H}_2 / \mathrm{Pd}\right)\) reduces both double bond and the carbonyl group.
Karnataka CET 2019
CHEMISTRY(KCET)
285588
Propanoic acid undergoes HVZ reaction to give chloropropanoic acid. The product obtained is
1 stronger acid than propanoic acid
2 as stronger as propanoic acid
3 weaker acid than propanoic acid
4 stronger than dichloropropanoic acid.
Explanation:
(a) Electron withdrawing group ( -Cl group) stabilizes the carboxylate ion by dispersing the negative charge and hence increases the acidity of carboxylic acid. Therefore, chloropropanoic acid is stronger acid than propanoic acid.
