285473
\(\mathrm{MSO}_4 \xrightarrow{\mathrm{NH}_4 \mathrm{OH}} \mathrm{x} \downarrow \xrightarrow[\substack{\text { excess } \\ \text { white }}]{\mathrm{NH}_4 \mathrm{OH}} \mathrm{Y} \xrightarrow{\mathrm{H}_2 \mathrm{~S}} \mathrm{Z} \downarrow\)
Here M and Z are
1 \(\mathrm{Zn}, \mathrm{ZnS}\)
2 \(\mathrm{Al}, \mathrm{Al}_2 \mathrm{~S}_3\)
3 \(\mathrm{Cu}, \mathrm{ZnS}\)
4 \(\mathrm{Fe}, \mathrm{FeS}\)
Explanation:
(a)
M is Zn .
Karnataka CET 2015
CHEMISTRY(KCET)
285471
When a brown compound of\(\mathrm{Mn}(A)\) is treated with HCl , it gives a gas \((B)\). The gas \((B)\) taken in excess reacts with \(\mathrm{NH}_3\) to give an explosive compound \((C)\).
The compounds \(A, B\) and \(C\) are
285446
The transition element (\(5 \%\) ) present with lanthanoid metal in Misch metal is:
1 Mg
2 Fe
3 Zn
4 Co
Explanation:
(b) Mischmetal is an alloy of rare earth elements. It is also called cerium mischmetal. A typical composition includes approximately\(55 \%\) cerium, \(25 \%\) lanthanum and \(15 \sim 18 \%\) neodymium. It contains 95\% lanthanides and \(5 \%\) iron.
Karnataka CET 2024
CHEMISTRY(KCET)
285447
Which of the following statements related to lanthanoids is incorrect?
1 Lanthanoids are silvery white soft metals
2 Samarium shows +2 oxidation state
3 \(\mathrm{Ce}^{+4}\) solutions are widely used as oxidising agents in titrimetric analysis
4 Colour of Lanthanoid ion in solution is due to d-d transition
Explanation:
(d) All the lanthanoids are silvery white soft metals and tarnish rapidly in air.
Samarium show +2 as well as +3 oxidation state. \(\mathrm{Ce}^{4+}\) is a oxidising agent in titrimetric analysis. The colors in lanthanoid is due to f - f transitions.
285473
\(\mathrm{MSO}_4 \xrightarrow{\mathrm{NH}_4 \mathrm{OH}} \mathrm{x} \downarrow \xrightarrow[\substack{\text { excess } \\ \text { white }}]{\mathrm{NH}_4 \mathrm{OH}} \mathrm{Y} \xrightarrow{\mathrm{H}_2 \mathrm{~S}} \mathrm{Z} \downarrow\)
Here M and Z are
1 \(\mathrm{Zn}, \mathrm{ZnS}\)
2 \(\mathrm{Al}, \mathrm{Al}_2 \mathrm{~S}_3\)
3 \(\mathrm{Cu}, \mathrm{ZnS}\)
4 \(\mathrm{Fe}, \mathrm{FeS}\)
Explanation:
(a)
M is Zn .
Karnataka CET 2015
CHEMISTRY(KCET)
285471
When a brown compound of\(\mathrm{Mn}(A)\) is treated with HCl , it gives a gas \((B)\). The gas \((B)\) taken in excess reacts with \(\mathrm{NH}_3\) to give an explosive compound \((C)\).
The compounds \(A, B\) and \(C\) are
285446
The transition element (\(5 \%\) ) present with lanthanoid metal in Misch metal is:
1 Mg
2 Fe
3 Zn
4 Co
Explanation:
(b) Mischmetal is an alloy of rare earth elements. It is also called cerium mischmetal. A typical composition includes approximately\(55 \%\) cerium, \(25 \%\) lanthanum and \(15 \sim 18 \%\) neodymium. It contains 95\% lanthanides and \(5 \%\) iron.
Karnataka CET 2024
CHEMISTRY(KCET)
285447
Which of the following statements related to lanthanoids is incorrect?
1 Lanthanoids are silvery white soft metals
2 Samarium shows +2 oxidation state
3 \(\mathrm{Ce}^{+4}\) solutions are widely used as oxidising agents in titrimetric analysis
4 Colour of Lanthanoid ion in solution is due to d-d transition
Explanation:
(d) All the lanthanoids are silvery white soft metals and tarnish rapidly in air.
Samarium show +2 as well as +3 oxidation state. \(\mathrm{Ce}^{4+}\) is a oxidising agent in titrimetric analysis. The colors in lanthanoid is due to f - f transitions.
285473
\(\mathrm{MSO}_4 \xrightarrow{\mathrm{NH}_4 \mathrm{OH}} \mathrm{x} \downarrow \xrightarrow[\substack{\text { excess } \\ \text { white }}]{\mathrm{NH}_4 \mathrm{OH}} \mathrm{Y} \xrightarrow{\mathrm{H}_2 \mathrm{~S}} \mathrm{Z} \downarrow\)
Here M and Z are
1 \(\mathrm{Zn}, \mathrm{ZnS}\)
2 \(\mathrm{Al}, \mathrm{Al}_2 \mathrm{~S}_3\)
3 \(\mathrm{Cu}, \mathrm{ZnS}\)
4 \(\mathrm{Fe}, \mathrm{FeS}\)
Explanation:
(a)
M is Zn .
Karnataka CET 2015
CHEMISTRY(KCET)
285471
When a brown compound of\(\mathrm{Mn}(A)\) is treated with HCl , it gives a gas \((B)\). The gas \((B)\) taken in excess reacts with \(\mathrm{NH}_3\) to give an explosive compound \((C)\).
The compounds \(A, B\) and \(C\) are
285446
The transition element (\(5 \%\) ) present with lanthanoid metal in Misch metal is:
1 Mg
2 Fe
3 Zn
4 Co
Explanation:
(b) Mischmetal is an alloy of rare earth elements. It is also called cerium mischmetal. A typical composition includes approximately\(55 \%\) cerium, \(25 \%\) lanthanum and \(15 \sim 18 \%\) neodymium. It contains 95\% lanthanides and \(5 \%\) iron.
Karnataka CET 2024
CHEMISTRY(KCET)
285447
Which of the following statements related to lanthanoids is incorrect?
1 Lanthanoids are silvery white soft metals
2 Samarium shows +2 oxidation state
3 \(\mathrm{Ce}^{+4}\) solutions are widely used as oxidising agents in titrimetric analysis
4 Colour of Lanthanoid ion in solution is due to d-d transition
Explanation:
(d) All the lanthanoids are silvery white soft metals and tarnish rapidly in air.
Samarium show +2 as well as +3 oxidation state. \(\mathrm{Ce}^{4+}\) is a oxidising agent in titrimetric analysis. The colors in lanthanoid is due to f - f transitions.
285473
\(\mathrm{MSO}_4 \xrightarrow{\mathrm{NH}_4 \mathrm{OH}} \mathrm{x} \downarrow \xrightarrow[\substack{\text { excess } \\ \text { white }}]{\mathrm{NH}_4 \mathrm{OH}} \mathrm{Y} \xrightarrow{\mathrm{H}_2 \mathrm{~S}} \mathrm{Z} \downarrow\)
Here M and Z are
1 \(\mathrm{Zn}, \mathrm{ZnS}\)
2 \(\mathrm{Al}, \mathrm{Al}_2 \mathrm{~S}_3\)
3 \(\mathrm{Cu}, \mathrm{ZnS}\)
4 \(\mathrm{Fe}, \mathrm{FeS}\)
Explanation:
(a)
M is Zn .
Karnataka CET 2015
CHEMISTRY(KCET)
285471
When a brown compound of\(\mathrm{Mn}(A)\) is treated with HCl , it gives a gas \((B)\). The gas \((B)\) taken in excess reacts with \(\mathrm{NH}_3\) to give an explosive compound \((C)\).
The compounds \(A, B\) and \(C\) are
285446
The transition element (\(5 \%\) ) present with lanthanoid metal in Misch metal is:
1 Mg
2 Fe
3 Zn
4 Co
Explanation:
(b) Mischmetal is an alloy of rare earth elements. It is also called cerium mischmetal. A typical composition includes approximately\(55 \%\) cerium, \(25 \%\) lanthanum and \(15 \sim 18 \%\) neodymium. It contains 95\% lanthanides and \(5 \%\) iron.
Karnataka CET 2024
CHEMISTRY(KCET)
285447
Which of the following statements related to lanthanoids is incorrect?
1 Lanthanoids are silvery white soft metals
2 Samarium shows +2 oxidation state
3 \(\mathrm{Ce}^{+4}\) solutions are widely used as oxidising agents in titrimetric analysis
4 Colour of Lanthanoid ion in solution is due to d-d transition
Explanation:
(d) All the lanthanoids are silvery white soft metals and tarnish rapidly in air.
Samarium show +2 as well as +3 oxidation state. \(\mathrm{Ce}^{4+}\) is a oxidising agent in titrimetric analysis. The colors in lanthanoid is due to f - f transitions.
285473
\(\mathrm{MSO}_4 \xrightarrow{\mathrm{NH}_4 \mathrm{OH}} \mathrm{x} \downarrow \xrightarrow[\substack{\text { excess } \\ \text { white }}]{\mathrm{NH}_4 \mathrm{OH}} \mathrm{Y} \xrightarrow{\mathrm{H}_2 \mathrm{~S}} \mathrm{Z} \downarrow\)
Here M and Z are
1 \(\mathrm{Zn}, \mathrm{ZnS}\)
2 \(\mathrm{Al}, \mathrm{Al}_2 \mathrm{~S}_3\)
3 \(\mathrm{Cu}, \mathrm{ZnS}\)
4 \(\mathrm{Fe}, \mathrm{FeS}\)
Explanation:
(a)
M is Zn .
Karnataka CET 2015
CHEMISTRY(KCET)
285471
When a brown compound of\(\mathrm{Mn}(A)\) is treated with HCl , it gives a gas \((B)\). The gas \((B)\) taken in excess reacts with \(\mathrm{NH}_3\) to give an explosive compound \((C)\).
The compounds \(A, B\) and \(C\) are
285446
The transition element (\(5 \%\) ) present with lanthanoid metal in Misch metal is:
1 Mg
2 Fe
3 Zn
4 Co
Explanation:
(b) Mischmetal is an alloy of rare earth elements. It is also called cerium mischmetal. A typical composition includes approximately\(55 \%\) cerium, \(25 \%\) lanthanum and \(15 \sim 18 \%\) neodymium. It contains 95\% lanthanides and \(5 \%\) iron.
Karnataka CET 2024
CHEMISTRY(KCET)
285447
Which of the following statements related to lanthanoids is incorrect?
1 Lanthanoids are silvery white soft metals
2 Samarium shows +2 oxidation state
3 \(\mathrm{Ce}^{+4}\) solutions are widely used as oxidising agents in titrimetric analysis
4 Colour of Lanthanoid ion in solution is due to d-d transition
Explanation:
(d) All the lanthanoids are silvery white soft metals and tarnish rapidly in air.
Samarium show +2 as well as +3 oxidation state. \(\mathrm{Ce}^{4+}\) is a oxidising agent in titrimetric analysis. The colors in lanthanoid is due to f - f transitions.