283615
The angle' of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\tan ^{-1}(\mathrm{n})\)
2 \(\operatorname{Sin}^{-1}(\mathrm{n})\)
3 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
4 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan _{-1} \mathrm{i}_{\mathrm{p}}\) Then, \(\mathrm{I}_{\mathrm{p}}=\tan ^{-1} \mathrm{n}\) Where, \(i_p\) is the angle of incidence when reflected light is totally polarized \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
AP EMCET(Medical)-2011
WAVE OPTICS
283619
Critical angle for certain medium is \(\sin ^{-1}(0.6)\). The polarizing angle of that medium is
283620
The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\sin ^{-1}(\mathrm{n})\)
2 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
3 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
4 \(\tan ^{-1}(\mathrm{n})\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}}\) \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}} \quad\left\{\begin{array}{c}\text { where, } \mathrm{i}_{\mathrm{p}}=\text { polarization angle } \\ \mathrm{n}=\text { refractive index }\end{array}\right\}\) \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
UPSEE -2005
WAVE OPTICS
283568
An unpolarized light wave is incident from air on a glass surface at the Brewster angle. The angle between the reflected and the refracted wave is
1 \(0^{\circ}\)
2 \(45^{\circ}\)
3 \(90^{\circ}\)
4 \(120^{\circ}\)
Explanation:
: When an unpolarized light is incident on a glass plate at Brewster's angle the reflected ray and refracted ray are mutually perpendicular. i.e. \(\theta_{\mathrm{R}}+\theta_{\mathrm{T}}=\) \(90^{\circ}\)
UPSEE 2020
WAVE OPTICS
283570
The phenomenon of polarization shows that light has nature :
1 dual
2 particle
3 transverse
4 longitudinal
Explanation:
: Polarisation is a process through which unpolarised light is transformed into polarised light. Its tells about the transverse wave nature light as the light wave is polarised in particular plane. The longitudinal waves cannot be polarised.
283615
The angle' of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\tan ^{-1}(\mathrm{n})\)
2 \(\operatorname{Sin}^{-1}(\mathrm{n})\)
3 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
4 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan _{-1} \mathrm{i}_{\mathrm{p}}\) Then, \(\mathrm{I}_{\mathrm{p}}=\tan ^{-1} \mathrm{n}\) Where, \(i_p\) is the angle of incidence when reflected light is totally polarized \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
AP EMCET(Medical)-2011
WAVE OPTICS
283619
Critical angle for certain medium is \(\sin ^{-1}(0.6)\). The polarizing angle of that medium is
283620
The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\sin ^{-1}(\mathrm{n})\)
2 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
3 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
4 \(\tan ^{-1}(\mathrm{n})\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}}\) \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}} \quad\left\{\begin{array}{c}\text { where, } \mathrm{i}_{\mathrm{p}}=\text { polarization angle } \\ \mathrm{n}=\text { refractive index }\end{array}\right\}\) \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
UPSEE -2005
WAVE OPTICS
283568
An unpolarized light wave is incident from air on a glass surface at the Brewster angle. The angle between the reflected and the refracted wave is
1 \(0^{\circ}\)
2 \(45^{\circ}\)
3 \(90^{\circ}\)
4 \(120^{\circ}\)
Explanation:
: When an unpolarized light is incident on a glass plate at Brewster's angle the reflected ray and refracted ray are mutually perpendicular. i.e. \(\theta_{\mathrm{R}}+\theta_{\mathrm{T}}=\) \(90^{\circ}\)
UPSEE 2020
WAVE OPTICS
283570
The phenomenon of polarization shows that light has nature :
1 dual
2 particle
3 transverse
4 longitudinal
Explanation:
: Polarisation is a process through which unpolarised light is transformed into polarised light. Its tells about the transverse wave nature light as the light wave is polarised in particular plane. The longitudinal waves cannot be polarised.
283615
The angle' of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\tan ^{-1}(\mathrm{n})\)
2 \(\operatorname{Sin}^{-1}(\mathrm{n})\)
3 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
4 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan _{-1} \mathrm{i}_{\mathrm{p}}\) Then, \(\mathrm{I}_{\mathrm{p}}=\tan ^{-1} \mathrm{n}\) Where, \(i_p\) is the angle of incidence when reflected light is totally polarized \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
AP EMCET(Medical)-2011
WAVE OPTICS
283619
Critical angle for certain medium is \(\sin ^{-1}(0.6)\). The polarizing angle of that medium is
283620
The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\sin ^{-1}(\mathrm{n})\)
2 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
3 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
4 \(\tan ^{-1}(\mathrm{n})\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}}\) \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}} \quad\left\{\begin{array}{c}\text { where, } \mathrm{i}_{\mathrm{p}}=\text { polarization angle } \\ \mathrm{n}=\text { refractive index }\end{array}\right\}\) \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
UPSEE -2005
WAVE OPTICS
283568
An unpolarized light wave is incident from air on a glass surface at the Brewster angle. The angle between the reflected and the refracted wave is
1 \(0^{\circ}\)
2 \(45^{\circ}\)
3 \(90^{\circ}\)
4 \(120^{\circ}\)
Explanation:
: When an unpolarized light is incident on a glass plate at Brewster's angle the reflected ray and refracted ray are mutually perpendicular. i.e. \(\theta_{\mathrm{R}}+\theta_{\mathrm{T}}=\) \(90^{\circ}\)
UPSEE 2020
WAVE OPTICS
283570
The phenomenon of polarization shows that light has nature :
1 dual
2 particle
3 transverse
4 longitudinal
Explanation:
: Polarisation is a process through which unpolarised light is transformed into polarised light. Its tells about the transverse wave nature light as the light wave is polarised in particular plane. The longitudinal waves cannot be polarised.
283615
The angle' of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\tan ^{-1}(\mathrm{n})\)
2 \(\operatorname{Sin}^{-1}(\mathrm{n})\)
3 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
4 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan _{-1} \mathrm{i}_{\mathrm{p}}\) Then, \(\mathrm{I}_{\mathrm{p}}=\tan ^{-1} \mathrm{n}\) Where, \(i_p\) is the angle of incidence when reflected light is totally polarized \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
AP EMCET(Medical)-2011
WAVE OPTICS
283619
Critical angle for certain medium is \(\sin ^{-1}(0.6)\). The polarizing angle of that medium is
283620
The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\sin ^{-1}(\mathrm{n})\)
2 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
3 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
4 \(\tan ^{-1}(\mathrm{n})\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}}\) \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}} \quad\left\{\begin{array}{c}\text { where, } \mathrm{i}_{\mathrm{p}}=\text { polarization angle } \\ \mathrm{n}=\text { refractive index }\end{array}\right\}\) \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
UPSEE -2005
WAVE OPTICS
283568
An unpolarized light wave is incident from air on a glass surface at the Brewster angle. The angle between the reflected and the refracted wave is
1 \(0^{\circ}\)
2 \(45^{\circ}\)
3 \(90^{\circ}\)
4 \(120^{\circ}\)
Explanation:
: When an unpolarized light is incident on a glass plate at Brewster's angle the reflected ray and refracted ray are mutually perpendicular. i.e. \(\theta_{\mathrm{R}}+\theta_{\mathrm{T}}=\) \(90^{\circ}\)
UPSEE 2020
WAVE OPTICS
283570
The phenomenon of polarization shows that light has nature :
1 dual
2 particle
3 transverse
4 longitudinal
Explanation:
: Polarisation is a process through which unpolarised light is transformed into polarised light. Its tells about the transverse wave nature light as the light wave is polarised in particular plane. The longitudinal waves cannot be polarised.
283615
The angle' of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\tan ^{-1}(\mathrm{n})\)
2 \(\operatorname{Sin}^{-1}(\mathrm{n})\)
3 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
4 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan _{-1} \mathrm{i}_{\mathrm{p}}\) Then, \(\mathrm{I}_{\mathrm{p}}=\tan ^{-1} \mathrm{n}\) Where, \(i_p\) is the angle of incidence when reflected light is totally polarized \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
AP EMCET(Medical)-2011
WAVE OPTICS
283619
Critical angle for certain medium is \(\sin ^{-1}(0.6)\). The polarizing angle of that medium is
283620
The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index \(n\) ) is
1 \(\sin ^{-1}(\mathrm{n})\)
2 \(\sin ^{-1}\left(\frac{1}{n}\right)\)
3 \(\tan ^{-1}\left(\frac{1}{\mathrm{n}}\right)\)
4 \(\tan ^{-1}(\mathrm{n})\)
Explanation:
: According to Brewster's law - \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}}\) \(\mathrm{n}=\tan \mathrm{i}_{\mathrm{p}} \quad\left\{\begin{array}{c}\text { where, } \mathrm{i}_{\mathrm{p}}=\text { polarization angle } \\ \mathrm{n}=\text { refractive index }\end{array}\right\}\) \(\mathrm{i}_{\mathrm{p}}=\tan ^{-1}(\mathrm{n})\)
UPSEE -2005
WAVE OPTICS
283568
An unpolarized light wave is incident from air on a glass surface at the Brewster angle. The angle between the reflected and the refracted wave is
1 \(0^{\circ}\)
2 \(45^{\circ}\)
3 \(90^{\circ}\)
4 \(120^{\circ}\)
Explanation:
: When an unpolarized light is incident on a glass plate at Brewster's angle the reflected ray and refracted ray are mutually perpendicular. i.e. \(\theta_{\mathrm{R}}+\theta_{\mathrm{T}}=\) \(90^{\circ}\)
UPSEE 2020
WAVE OPTICS
283570
The phenomenon of polarization shows that light has nature :
1 dual
2 particle
3 transverse
4 longitudinal
Explanation:
: Polarisation is a process through which unpolarised light is transformed into polarised light. Its tells about the transverse wave nature light as the light wave is polarised in particular plane. The longitudinal waves cannot be polarised.
