283207
In Young's double slit experiment interference fringes will be observed on the screen when, the initial phase difference between lights originating from the two coherent sources separated vertically by distance \(d\), is equal to
1 Zero
2 \(\pi\)
3 \(\mathrm{kd}\)
4 \(\omega t+2 \pi\)
Explanation:
: We know that, in Young's double slit experiment constructive interference occurs when the phase difference between the waves is an even multiple of \(\pi\), where as destructive interference occurs when the difference is an odd multiple of \(\pi\).
UPSEE - 2011
WAVE OPTICS
283209
In an interference experiment, the spacing between successive maxima or minima is
1 \(\lambda \mathrm{d} / \mathrm{D}\)
2 \(\lambda \mathrm{D} / \mathrm{d}\)
3 \(\mathrm{dD} / \lambda\)
4 \(\lambda \mathrm{d} / 4 \mathrm{D}\)
Explanation:
: Young's double slit experiment used diffracted light of a single source from two slits to produce two coherent sources. The interference pattern produced by the double-slit experiment is made up of alternate light and dark fringes that run parallel to the slits. Hence, the spacing between successive maxima or minima is \(\lambda \mathrm{D} / \mathrm{d}\).
UPSEE - 2008
WAVE OPTICS
283210
In which of the following is the interference due to the division of wavefront?
1 Young's double slit experiment
2 Fresnel's biprism experiment
3 Llyod's mirror experiment
4 Demonstration colours of thin film
Explanation:
: In Fresnel's Biprism experiment, two prism which are connected through their bases are used. When a light source having particular wavelength allowed to fall on this setup then an interference pattern observed on a screen kept on the other side of the Biprism.
UPSEE - 2005
WAVE OPTICS
283218
The width of the diffraction band varies
1 inversely as the wavelength
2 directly as the width of the slit
3 directly as the distance between the slit and the screen
4 inversely as the size of the source from which the slit is illuminated
Explanation:
: \(\beta=\frac{\mathrm{D} \lambda}{\mathrm{d}}\) From above equation, it is clear that the width of the diffraction band varies directly as the distance between the slit and the screen.
NEET Test Series from KOTA - 10 Papers In MS WORD
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WAVE OPTICS
283207
In Young's double slit experiment interference fringes will be observed on the screen when, the initial phase difference between lights originating from the two coherent sources separated vertically by distance \(d\), is equal to
1 Zero
2 \(\pi\)
3 \(\mathrm{kd}\)
4 \(\omega t+2 \pi\)
Explanation:
: We know that, in Young's double slit experiment constructive interference occurs when the phase difference between the waves is an even multiple of \(\pi\), where as destructive interference occurs when the difference is an odd multiple of \(\pi\).
UPSEE - 2011
WAVE OPTICS
283209
In an interference experiment, the spacing between successive maxima or minima is
1 \(\lambda \mathrm{d} / \mathrm{D}\)
2 \(\lambda \mathrm{D} / \mathrm{d}\)
3 \(\mathrm{dD} / \lambda\)
4 \(\lambda \mathrm{d} / 4 \mathrm{D}\)
Explanation:
: Young's double slit experiment used diffracted light of a single source from two slits to produce two coherent sources. The interference pattern produced by the double-slit experiment is made up of alternate light and dark fringes that run parallel to the slits. Hence, the spacing between successive maxima or minima is \(\lambda \mathrm{D} / \mathrm{d}\).
UPSEE - 2008
WAVE OPTICS
283210
In which of the following is the interference due to the division of wavefront?
1 Young's double slit experiment
2 Fresnel's biprism experiment
3 Llyod's mirror experiment
4 Demonstration colours of thin film
Explanation:
: In Fresnel's Biprism experiment, two prism which are connected through their bases are used. When a light source having particular wavelength allowed to fall on this setup then an interference pattern observed on a screen kept on the other side of the Biprism.
UPSEE - 2005
WAVE OPTICS
283218
The width of the diffraction band varies
1 inversely as the wavelength
2 directly as the width of the slit
3 directly as the distance between the slit and the screen
4 inversely as the size of the source from which the slit is illuminated
Explanation:
: \(\beta=\frac{\mathrm{D} \lambda}{\mathrm{d}}\) From above equation, it is clear that the width of the diffraction band varies directly as the distance between the slit and the screen.
283207
In Young's double slit experiment interference fringes will be observed on the screen when, the initial phase difference between lights originating from the two coherent sources separated vertically by distance \(d\), is equal to
1 Zero
2 \(\pi\)
3 \(\mathrm{kd}\)
4 \(\omega t+2 \pi\)
Explanation:
: We know that, in Young's double slit experiment constructive interference occurs when the phase difference between the waves is an even multiple of \(\pi\), where as destructive interference occurs when the difference is an odd multiple of \(\pi\).
UPSEE - 2011
WAVE OPTICS
283209
In an interference experiment, the spacing between successive maxima or minima is
1 \(\lambda \mathrm{d} / \mathrm{D}\)
2 \(\lambda \mathrm{D} / \mathrm{d}\)
3 \(\mathrm{dD} / \lambda\)
4 \(\lambda \mathrm{d} / 4 \mathrm{D}\)
Explanation:
: Young's double slit experiment used diffracted light of a single source from two slits to produce two coherent sources. The interference pattern produced by the double-slit experiment is made up of alternate light and dark fringes that run parallel to the slits. Hence, the spacing between successive maxima or minima is \(\lambda \mathrm{D} / \mathrm{d}\).
UPSEE - 2008
WAVE OPTICS
283210
In which of the following is the interference due to the division of wavefront?
1 Young's double slit experiment
2 Fresnel's biprism experiment
3 Llyod's mirror experiment
4 Demonstration colours of thin film
Explanation:
: In Fresnel's Biprism experiment, two prism which are connected through their bases are used. When a light source having particular wavelength allowed to fall on this setup then an interference pattern observed on a screen kept on the other side of the Biprism.
UPSEE - 2005
WAVE OPTICS
283218
The width of the diffraction band varies
1 inversely as the wavelength
2 directly as the width of the slit
3 directly as the distance between the slit and the screen
4 inversely as the size of the source from which the slit is illuminated
Explanation:
: \(\beta=\frac{\mathrm{D} \lambda}{\mathrm{d}}\) From above equation, it is clear that the width of the diffraction band varies directly as the distance between the slit and the screen.
283207
In Young's double slit experiment interference fringes will be observed on the screen when, the initial phase difference between lights originating from the two coherent sources separated vertically by distance \(d\), is equal to
1 Zero
2 \(\pi\)
3 \(\mathrm{kd}\)
4 \(\omega t+2 \pi\)
Explanation:
: We know that, in Young's double slit experiment constructive interference occurs when the phase difference between the waves is an even multiple of \(\pi\), where as destructive interference occurs when the difference is an odd multiple of \(\pi\).
UPSEE - 2011
WAVE OPTICS
283209
In an interference experiment, the spacing between successive maxima or minima is
1 \(\lambda \mathrm{d} / \mathrm{D}\)
2 \(\lambda \mathrm{D} / \mathrm{d}\)
3 \(\mathrm{dD} / \lambda\)
4 \(\lambda \mathrm{d} / 4 \mathrm{D}\)
Explanation:
: Young's double slit experiment used diffracted light of a single source from two slits to produce two coherent sources. The interference pattern produced by the double-slit experiment is made up of alternate light and dark fringes that run parallel to the slits. Hence, the spacing between successive maxima or minima is \(\lambda \mathrm{D} / \mathrm{d}\).
UPSEE - 2008
WAVE OPTICS
283210
In which of the following is the interference due to the division of wavefront?
1 Young's double slit experiment
2 Fresnel's biprism experiment
3 Llyod's mirror experiment
4 Demonstration colours of thin film
Explanation:
: In Fresnel's Biprism experiment, two prism which are connected through their bases are used. When a light source having particular wavelength allowed to fall on this setup then an interference pattern observed on a screen kept on the other side of the Biprism.
UPSEE - 2005
WAVE OPTICS
283218
The width of the diffraction band varies
1 inversely as the wavelength
2 directly as the width of the slit
3 directly as the distance between the slit and the screen
4 inversely as the size of the source from which the slit is illuminated
Explanation:
: \(\beta=\frac{\mathrm{D} \lambda}{\mathrm{d}}\) From above equation, it is clear that the width of the diffraction band varies directly as the distance between the slit and the screen.