282703
The light ray is incident at angle of \(60^{\circ}\) on a prism of angle \(45^{\circ}\). When the light rays falls on the other surface at \(90^{\circ}\), the refractive index of the material of prism \(\mu\) and the angle of deviation \(\delta\) are given by
282704
A prism of crown glass with refracting angle of \(5^{\circ}\) and mean refractive inde \(x=1.51\) is combined with a flint glass prism of refractive index \(=\) 1.65 to produce no deviation. Find the angle of flint glass.
1 \(3.92^{\circ}\)
2 \(4.68^{\circ}\)
3 \(5.32^{\circ}\)
4 \(7.28^{\circ}\)
Explanation:
A: Given, Angle of prism, \(A_1=5^{\circ}\)
Refractive index of prism, \(\mu_1=1.51\)
Angle of flint glass, \(\mathrm{A}_2=\) ?
Refractive index of flint glass, \(\mu_2=1.65\)
We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
5^{\circ}(1.51-1)=\mathrm{A}_2(1.65-1) \\
\mathrm{A}_2=\frac{5^{\circ} \times 0.51}{0.65} \\
\mathrm{~A}_2=3.92^{\circ}
\end{aligned}\)
JIPMER-2018
Ray Optics
282705
An air gap in the form of a prism as shown in the figure is present inside a glass slab of refractive index 1.8 A ray enters from left side of the slab through face \(A\). Then
1 The ray passes through the slab undeviated
2 The ray exits from the slab bending upwards
3 The ray exits from the slab bending downwards
4 The ray exits from the slab after total internal reflection
Explanation:
B: - When the ray enters glass slab it does not bends because angle of incident is zero \(\left(0^{\circ}\right)\).
- When ray enters air prism then it bends away from the normal.
- Again when ray touches glass slab it moves with bending, it emerged out from slab but in upwards direction.
TS EAMCET 03.05.2018
Ray Optics
282706
A thin prism of angle \(15^0\) made of glass of refractive index \(\mu_1=1.5\) is combined with another prism of glass of refractive index \(\mu_2=\) 1.75. The combination of prism produces dispersion without deviation. The angle of the second prism should be
1 \(7^0\)
2 \(10^0\)
3 \(12^0\)
4 \(5^0\)
Explanation:
BGiven, \(\mathrm{A}_1=15^{\circ}, \mu_1=1.5, \mathrm{~A}_2=\) ?, \(\mu_2=1.75\) We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
15(1.5-1)=\mathrm{A}_2(1.75-1) \\
\mathrm{A}_2=\frac{15 \times 0.5}{0.75}
\end{aligned}\)
So, the angle of the second prism-
\(\mathrm{A}_2=10^{\circ}\)
282703
The light ray is incident at angle of \(60^{\circ}\) on a prism of angle \(45^{\circ}\). When the light rays falls on the other surface at \(90^{\circ}\), the refractive index of the material of prism \(\mu\) and the angle of deviation \(\delta\) are given by
282704
A prism of crown glass with refracting angle of \(5^{\circ}\) and mean refractive inde \(x=1.51\) is combined with a flint glass prism of refractive index \(=\) 1.65 to produce no deviation. Find the angle of flint glass.
1 \(3.92^{\circ}\)
2 \(4.68^{\circ}\)
3 \(5.32^{\circ}\)
4 \(7.28^{\circ}\)
Explanation:
A: Given, Angle of prism, \(A_1=5^{\circ}\)
Refractive index of prism, \(\mu_1=1.51\)
Angle of flint glass, \(\mathrm{A}_2=\) ?
Refractive index of flint glass, \(\mu_2=1.65\)
We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
5^{\circ}(1.51-1)=\mathrm{A}_2(1.65-1) \\
\mathrm{A}_2=\frac{5^{\circ} \times 0.51}{0.65} \\
\mathrm{~A}_2=3.92^{\circ}
\end{aligned}\)
JIPMER-2018
Ray Optics
282705
An air gap in the form of a prism as shown in the figure is present inside a glass slab of refractive index 1.8 A ray enters from left side of the slab through face \(A\). Then
1 The ray passes through the slab undeviated
2 The ray exits from the slab bending upwards
3 The ray exits from the slab bending downwards
4 The ray exits from the slab after total internal reflection
Explanation:
B: - When the ray enters glass slab it does not bends because angle of incident is zero \(\left(0^{\circ}\right)\).
- When ray enters air prism then it bends away from the normal.
- Again when ray touches glass slab it moves with bending, it emerged out from slab but in upwards direction.
TS EAMCET 03.05.2018
Ray Optics
282706
A thin prism of angle \(15^0\) made of glass of refractive index \(\mu_1=1.5\) is combined with another prism of glass of refractive index \(\mu_2=\) 1.75. The combination of prism produces dispersion without deviation. The angle of the second prism should be
1 \(7^0\)
2 \(10^0\)
3 \(12^0\)
4 \(5^0\)
Explanation:
BGiven, \(\mathrm{A}_1=15^{\circ}, \mu_1=1.5, \mathrm{~A}_2=\) ?, \(\mu_2=1.75\) We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
15(1.5-1)=\mathrm{A}_2(1.75-1) \\
\mathrm{A}_2=\frac{15 \times 0.5}{0.75}
\end{aligned}\)
So, the angle of the second prism-
\(\mathrm{A}_2=10^{\circ}\)
282703
The light ray is incident at angle of \(60^{\circ}\) on a prism of angle \(45^{\circ}\). When the light rays falls on the other surface at \(90^{\circ}\), the refractive index of the material of prism \(\mu\) and the angle of deviation \(\delta\) are given by
282704
A prism of crown glass with refracting angle of \(5^{\circ}\) and mean refractive inde \(x=1.51\) is combined with a flint glass prism of refractive index \(=\) 1.65 to produce no deviation. Find the angle of flint glass.
1 \(3.92^{\circ}\)
2 \(4.68^{\circ}\)
3 \(5.32^{\circ}\)
4 \(7.28^{\circ}\)
Explanation:
A: Given, Angle of prism, \(A_1=5^{\circ}\)
Refractive index of prism, \(\mu_1=1.51\)
Angle of flint glass, \(\mathrm{A}_2=\) ?
Refractive index of flint glass, \(\mu_2=1.65\)
We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
5^{\circ}(1.51-1)=\mathrm{A}_2(1.65-1) \\
\mathrm{A}_2=\frac{5^{\circ} \times 0.51}{0.65} \\
\mathrm{~A}_2=3.92^{\circ}
\end{aligned}\)
JIPMER-2018
Ray Optics
282705
An air gap in the form of a prism as shown in the figure is present inside a glass slab of refractive index 1.8 A ray enters from left side of the slab through face \(A\). Then
1 The ray passes through the slab undeviated
2 The ray exits from the slab bending upwards
3 The ray exits from the slab bending downwards
4 The ray exits from the slab after total internal reflection
Explanation:
B: - When the ray enters glass slab it does not bends because angle of incident is zero \(\left(0^{\circ}\right)\).
- When ray enters air prism then it bends away from the normal.
- Again when ray touches glass slab it moves with bending, it emerged out from slab but in upwards direction.
TS EAMCET 03.05.2018
Ray Optics
282706
A thin prism of angle \(15^0\) made of glass of refractive index \(\mu_1=1.5\) is combined with another prism of glass of refractive index \(\mu_2=\) 1.75. The combination of prism produces dispersion without deviation. The angle of the second prism should be
1 \(7^0\)
2 \(10^0\)
3 \(12^0\)
4 \(5^0\)
Explanation:
BGiven, \(\mathrm{A}_1=15^{\circ}, \mu_1=1.5, \mathrm{~A}_2=\) ?, \(\mu_2=1.75\) We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
15(1.5-1)=\mathrm{A}_2(1.75-1) \\
\mathrm{A}_2=\frac{15 \times 0.5}{0.75}
\end{aligned}\)
So, the angle of the second prism-
\(\mathrm{A}_2=10^{\circ}\)
282703
The light ray is incident at angle of \(60^{\circ}\) on a prism of angle \(45^{\circ}\). When the light rays falls on the other surface at \(90^{\circ}\), the refractive index of the material of prism \(\mu\) and the angle of deviation \(\delta\) are given by
282704
A prism of crown glass with refracting angle of \(5^{\circ}\) and mean refractive inde \(x=1.51\) is combined with a flint glass prism of refractive index \(=\) 1.65 to produce no deviation. Find the angle of flint glass.
1 \(3.92^{\circ}\)
2 \(4.68^{\circ}\)
3 \(5.32^{\circ}\)
4 \(7.28^{\circ}\)
Explanation:
A: Given, Angle of prism, \(A_1=5^{\circ}\)
Refractive index of prism, \(\mu_1=1.51\)
Angle of flint glass, \(\mathrm{A}_2=\) ?
Refractive index of flint glass, \(\mu_2=1.65\)
We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
5^{\circ}(1.51-1)=\mathrm{A}_2(1.65-1) \\
\mathrm{A}_2=\frac{5^{\circ} \times 0.51}{0.65} \\
\mathrm{~A}_2=3.92^{\circ}
\end{aligned}\)
JIPMER-2018
Ray Optics
282705
An air gap in the form of a prism as shown in the figure is present inside a glass slab of refractive index 1.8 A ray enters from left side of the slab through face \(A\). Then
1 The ray passes through the slab undeviated
2 The ray exits from the slab bending upwards
3 The ray exits from the slab bending downwards
4 The ray exits from the slab after total internal reflection
Explanation:
B: - When the ray enters glass slab it does not bends because angle of incident is zero \(\left(0^{\circ}\right)\).
- When ray enters air prism then it bends away from the normal.
- Again when ray touches glass slab it moves with bending, it emerged out from slab but in upwards direction.
TS EAMCET 03.05.2018
Ray Optics
282706
A thin prism of angle \(15^0\) made of glass of refractive index \(\mu_1=1.5\) is combined with another prism of glass of refractive index \(\mu_2=\) 1.75. The combination of prism produces dispersion without deviation. The angle of the second prism should be
1 \(7^0\)
2 \(10^0\)
3 \(12^0\)
4 \(5^0\)
Explanation:
BGiven, \(\mathrm{A}_1=15^{\circ}, \mu_1=1.5, \mathrm{~A}_2=\) ?, \(\mu_2=1.75\) We know that-
\(\begin{aligned}
\mathrm{A}_1\left(\mu_1-1\right)=\mathrm{A}_2\left(\mu_2-1\right) \\
15(1.5-1)=\mathrm{A}_2(1.75-1) \\
\mathrm{A}_2=\frac{15 \times 0.5}{0.75}
\end{aligned}\)
So, the angle of the second prism-
\(\mathrm{A}_2=10^{\circ}\)
