282670
A thin prism \(P_1\) with an angle \(6^{\circ}\) and made of glass of refractive index 1.54 is combined with another primes \(P_2\) made from glass of refractive index 1.72 to produce dispersion without average deviation. The angle of prism \(\mathbf{P}_2\) is
282671
The refracting angle of prism is \(A\) and refractive index of material of prism is \(\cot \frac{A}{2}\). The angle of minimum deviation is \(\mathbf{A}\).
282672
A ray is incident at an angle of incidence \(i\) on one surface of a small angle prism (with angle of prism A) and emerges normally from the opposite surface. If the refractive index of the material of the prism is \(\mu\), then the angle of incidence is nearly equal to
1 \(\frac{2 \mathrm{~A}}{\mu}\)
2 \(\mu \mathrm{A}\)
3 \(\frac{\mu \mathrm{A}}{2}\)
4 \(\frac{\mathrm{A}}{2 \mu}\)
Explanation:
B: We know that,
Angle of deviation \(\delta=(\mu-1)\) A
Sum of angle
\(\delta+\mathrm{A}=\mathrm{i}+\mathrm{e}\)
Ray emerges normally e \(=0\)
Solving equation (i) \& (ii), we get
\(\begin{aligned}
(\mu-1) \mathrm{A}+\mathrm{A}=\mathrm{i}+0 \\
\mu \mathrm{A}-\mathrm{A}+\mathrm{A}=\mathrm{i} \\
\mu \mathrm{A}=\mathrm{i}
\end{aligned}\)
NEET(Sep.)- 2020
Ray Optics
282673
A light ray through a glass prism of angle \(60^{\circ}\) under goes a minimum deviation of \(30^{\circ}\). What is the speed of light in the prism?
(Assume \(c=\) speed of light in air)
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Ray Optics
282670
A thin prism \(P_1\) with an angle \(6^{\circ}\) and made of glass of refractive index 1.54 is combined with another primes \(P_2\) made from glass of refractive index 1.72 to produce dispersion without average deviation. The angle of prism \(\mathbf{P}_2\) is
282671
The refracting angle of prism is \(A\) and refractive index of material of prism is \(\cot \frac{A}{2}\). The angle of minimum deviation is \(\mathbf{A}\).
282672
A ray is incident at an angle of incidence \(i\) on one surface of a small angle prism (with angle of prism A) and emerges normally from the opposite surface. If the refractive index of the material of the prism is \(\mu\), then the angle of incidence is nearly equal to
1 \(\frac{2 \mathrm{~A}}{\mu}\)
2 \(\mu \mathrm{A}\)
3 \(\frac{\mu \mathrm{A}}{2}\)
4 \(\frac{\mathrm{A}}{2 \mu}\)
Explanation:
B: We know that,
Angle of deviation \(\delta=(\mu-1)\) A
Sum of angle
\(\delta+\mathrm{A}=\mathrm{i}+\mathrm{e}\)
Ray emerges normally e \(=0\)
Solving equation (i) \& (ii), we get
\(\begin{aligned}
(\mu-1) \mathrm{A}+\mathrm{A}=\mathrm{i}+0 \\
\mu \mathrm{A}-\mathrm{A}+\mathrm{A}=\mathrm{i} \\
\mu \mathrm{A}=\mathrm{i}
\end{aligned}\)
NEET(Sep.)- 2020
Ray Optics
282673
A light ray through a glass prism of angle \(60^{\circ}\) under goes a minimum deviation of \(30^{\circ}\). What is the speed of light in the prism?
(Assume \(c=\) speed of light in air)
282670
A thin prism \(P_1\) with an angle \(6^{\circ}\) and made of glass of refractive index 1.54 is combined with another primes \(P_2\) made from glass of refractive index 1.72 to produce dispersion without average deviation. The angle of prism \(\mathbf{P}_2\) is
282671
The refracting angle of prism is \(A\) and refractive index of material of prism is \(\cot \frac{A}{2}\). The angle of minimum deviation is \(\mathbf{A}\).
282672
A ray is incident at an angle of incidence \(i\) on one surface of a small angle prism (with angle of prism A) and emerges normally from the opposite surface. If the refractive index of the material of the prism is \(\mu\), then the angle of incidence is nearly equal to
1 \(\frac{2 \mathrm{~A}}{\mu}\)
2 \(\mu \mathrm{A}\)
3 \(\frac{\mu \mathrm{A}}{2}\)
4 \(\frac{\mathrm{A}}{2 \mu}\)
Explanation:
B: We know that,
Angle of deviation \(\delta=(\mu-1)\) A
Sum of angle
\(\delta+\mathrm{A}=\mathrm{i}+\mathrm{e}\)
Ray emerges normally e \(=0\)
Solving equation (i) \& (ii), we get
\(\begin{aligned}
(\mu-1) \mathrm{A}+\mathrm{A}=\mathrm{i}+0 \\
\mu \mathrm{A}-\mathrm{A}+\mathrm{A}=\mathrm{i} \\
\mu \mathrm{A}=\mathrm{i}
\end{aligned}\)
NEET(Sep.)- 2020
Ray Optics
282673
A light ray through a glass prism of angle \(60^{\circ}\) under goes a minimum deviation of \(30^{\circ}\). What is the speed of light in the prism?
(Assume \(c=\) speed of light in air)
282670
A thin prism \(P_1\) with an angle \(6^{\circ}\) and made of glass of refractive index 1.54 is combined with another primes \(P_2\) made from glass of refractive index 1.72 to produce dispersion without average deviation. The angle of prism \(\mathbf{P}_2\) is
282671
The refracting angle of prism is \(A\) and refractive index of material of prism is \(\cot \frac{A}{2}\). The angle of minimum deviation is \(\mathbf{A}\).
282672
A ray is incident at an angle of incidence \(i\) on one surface of a small angle prism (with angle of prism A) and emerges normally from the opposite surface. If the refractive index of the material of the prism is \(\mu\), then the angle of incidence is nearly equal to
1 \(\frac{2 \mathrm{~A}}{\mu}\)
2 \(\mu \mathrm{A}\)
3 \(\frac{\mu \mathrm{A}}{2}\)
4 \(\frac{\mathrm{A}}{2 \mu}\)
Explanation:
B: We know that,
Angle of deviation \(\delta=(\mu-1)\) A
Sum of angle
\(\delta+\mathrm{A}=\mathrm{i}+\mathrm{e}\)
Ray emerges normally e \(=0\)
Solving equation (i) \& (ii), we get
\(\begin{aligned}
(\mu-1) \mathrm{A}+\mathrm{A}=\mathrm{i}+0 \\
\mu \mathrm{A}-\mathrm{A}+\mathrm{A}=\mathrm{i} \\
\mu \mathrm{A}=\mathrm{i}
\end{aligned}\)
NEET(Sep.)- 2020
Ray Optics
282673
A light ray through a glass prism of angle \(60^{\circ}\) under goes a minimum deviation of \(30^{\circ}\). What is the speed of light in the prism?
(Assume \(c=\) speed of light in air)