Spherical Surface and Lenses, Lens Formula, Magnification, Combination of Lens.
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Ray Optics

282471 The correct formula used to decide the focal length of a lens is ( \(F\) is focal length, \(\mu\) is refractive index of the material of lens, \(R_1\) and \(R_2\) are radii of curvature of curved surfaces, \(u\) and \(v\) are respectively object distance and image distance

1 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{~V}}-\frac{1}{\mathrm{u}}\)
2 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)\)
3 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}\)
4 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)\)
Ray Optics

282472 In experiment of finding the focal length of a convex lens by two- pin method, the \(u-v\) graph obtained by the student will be as

(a)
(b)
(c)
(d)
Ans: c
Exp: C: When, \(\mathrm{u}=\mathrm{f}\) then \(\mathrm{v} \rightarrow \infty\) and \(\mathrm{u}=\infty, \mathrm{v}=\mathrm{f}\)

Ray Optics

282473 A person cannot see objects clearly beyond 50 \(\mathrm{cm}\). The power of the lens to correct the vision is

1 \(+5 \mathrm{D}\)
2 \(-0.5 \mathrm{D}\)
3 \(-2 \mathrm{D}\)
4 \(+2 \mathrm{D}\)
Ray Optics

282474 The focal length of a simple convex lens used as a magnifier is \(10 \mathrm{~cm}\). For the image to be formed at a distance of distinct vision \((D=25\) \(\mathrm{cm}\) ), the object must be placed away from the lens at a distance of

1 \(0.5 \mathrm{~cm}\)
2 \(7.14 \mathrm{~cm}\)
3 \(7.20 \mathrm{~cm}\)
4 \(16.16 \mathrm{~cm}\)
Ray Optics

282471 The correct formula used to decide the focal length of a lens is ( \(F\) is focal length, \(\mu\) is refractive index of the material of lens, \(R_1\) and \(R_2\) are radii of curvature of curved surfaces, \(u\) and \(v\) are respectively object distance and image distance

1 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{~V}}-\frac{1}{\mathrm{u}}\)
2 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)\)
3 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}\)
4 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)\)
Ray Optics

282472 In experiment of finding the focal length of a convex lens by two- pin method, the \(u-v\) graph obtained by the student will be as

(a)
(b)
(c)
(d)
Ans: c
Exp: C: When, \(\mathrm{u}=\mathrm{f}\) then \(\mathrm{v} \rightarrow \infty\) and \(\mathrm{u}=\infty, \mathrm{v}=\mathrm{f}\)

Ray Optics

282473 A person cannot see objects clearly beyond 50 \(\mathrm{cm}\). The power of the lens to correct the vision is

1 \(+5 \mathrm{D}\)
2 \(-0.5 \mathrm{D}\)
3 \(-2 \mathrm{D}\)
4 \(+2 \mathrm{D}\)
Ray Optics

282474 The focal length of a simple convex lens used as a magnifier is \(10 \mathrm{~cm}\). For the image to be formed at a distance of distinct vision \((D=25\) \(\mathrm{cm}\) ), the object must be placed away from the lens at a distance of

1 \(0.5 \mathrm{~cm}\)
2 \(7.14 \mathrm{~cm}\)
3 \(7.20 \mathrm{~cm}\)
4 \(16.16 \mathrm{~cm}\)
Ray Optics

282471 The correct formula used to decide the focal length of a lens is ( \(F\) is focal length, \(\mu\) is refractive index of the material of lens, \(R_1\) and \(R_2\) are radii of curvature of curved surfaces, \(u\) and \(v\) are respectively object distance and image distance

1 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{~V}}-\frac{1}{\mathrm{u}}\)
2 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)\)
3 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}\)
4 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)\)
Ray Optics

282472 In experiment of finding the focal length of a convex lens by two- pin method, the \(u-v\) graph obtained by the student will be as

(a)
(b)
(c)
(d)
Ans: c
Exp: C: When, \(\mathrm{u}=\mathrm{f}\) then \(\mathrm{v} \rightarrow \infty\) and \(\mathrm{u}=\infty, \mathrm{v}=\mathrm{f}\)

Ray Optics

282473 A person cannot see objects clearly beyond 50 \(\mathrm{cm}\). The power of the lens to correct the vision is

1 \(+5 \mathrm{D}\)
2 \(-0.5 \mathrm{D}\)
3 \(-2 \mathrm{D}\)
4 \(+2 \mathrm{D}\)
Ray Optics

282474 The focal length of a simple convex lens used as a magnifier is \(10 \mathrm{~cm}\). For the image to be formed at a distance of distinct vision \((D=25\) \(\mathrm{cm}\) ), the object must be placed away from the lens at a distance of

1 \(0.5 \mathrm{~cm}\)
2 \(7.14 \mathrm{~cm}\)
3 \(7.20 \mathrm{~cm}\)
4 \(16.16 \mathrm{~cm}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Ray Optics

282471 The correct formula used to decide the focal length of a lens is ( \(F\) is focal length, \(\mu\) is refractive index of the material of lens, \(R_1\) and \(R_2\) are radii of curvature of curved surfaces, \(u\) and \(v\) are respectively object distance and image distance

1 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{~V}}-\frac{1}{\mathrm{u}}\)
2 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right)\)
3 \(\frac{1}{\mathrm{~F}}=\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}\)
4 \(\frac{1}{\mathrm{~F}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}\right)\)
Ray Optics

282472 In experiment of finding the focal length of a convex lens by two- pin method, the \(u-v\) graph obtained by the student will be as

(a)
(b)
(c)
(d)
Ans: c
Exp: C: When, \(\mathrm{u}=\mathrm{f}\) then \(\mathrm{v} \rightarrow \infty\) and \(\mathrm{u}=\infty, \mathrm{v}=\mathrm{f}\)

Ray Optics

282473 A person cannot see objects clearly beyond 50 \(\mathrm{cm}\). The power of the lens to correct the vision is

1 \(+5 \mathrm{D}\)
2 \(-0.5 \mathrm{D}\)
3 \(-2 \mathrm{D}\)
4 \(+2 \mathrm{D}\)
Ray Optics

282474 The focal length of a simple convex lens used as a magnifier is \(10 \mathrm{~cm}\). For the image to be formed at a distance of distinct vision \((D=25\) \(\mathrm{cm}\) ), the object must be placed away from the lens at a distance of

1 \(0.5 \mathrm{~cm}\)
2 \(7.14 \mathrm{~cm}\)
3 \(7.20 \mathrm{~cm}\)
4 \(16.16 \mathrm{~cm}\)