Spherical Surface and Lenses, Lens Formula, Magnification, Combination of Lens.
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Ray Optics

282388 A glass convex lens is of refractive index \(\mathbf{1 . 5 5}\) with both faces of same radius of curvature. What will be the radius of curvature if focal length is to be \(20 \mathrm{~cm}\) ?

1 \(18 \mathrm{~cm}\)
2 \(21 \mathrm{~cm}\)
3 \(20 \mathrm{~cm}\)
4 \(22 \mathrm{~cm}\)
Ray Optics

282381 A plano-convex lens fits exactly into a planoconcave lens and their plane surfaces are parallel to each other. If \(\mu_1\) and \(\mu_2\) are the refractive indices for plano-convex lens and plano-concave lens respectively and \(R\) is the radius of curvature of the curved surfaces of the lenses, then the focal-length of the combination is

1 \(\frac{\mathrm{R}}{2\left(\mu_1-\mu_2\right)}\)
2 \(\frac{2 \mathrm{R}}{\left(\mu_2-\mu_1\right)}\)
3 \(\frac{\mathrm{R}}{\mu_1-\mu_2}\)
4 \(\frac{\mathrm{R}}{2\left(\mu_1+\mu_2\right)}\)
Ray Optics

282382 You are given a thin diverging lens of \(20 \mathrm{~cm}\) focal length. Calculate the distance at which an object should be placed to obtain \(1 / 3\) lateral magnification.

1 \(10 \mathrm{~cm}\)
2 \(30 \mathrm{~cm}\)
3 \(40 \mathrm{~cm}\)
4 \(50 \mathrm{~cm}\)
Ray Optics

282383 A small object is enclosed in a transparent solid sphere of radius \(8 \mathrm{~cm}\). The object is situated at \(2 \mathbf{~ c m}\) from the centre of the sphere. If its image appears to be at \(3.2 \mathrm{~cm}\) from the nearest side, then the refractive index of the material of the sphere is

1 1.62
2 1.45
3 1.55
4 1.50
Ray Optics

282388 A glass convex lens is of refractive index \(\mathbf{1 . 5 5}\) with both faces of same radius of curvature. What will be the radius of curvature if focal length is to be \(20 \mathrm{~cm}\) ?

1 \(18 \mathrm{~cm}\)
2 \(21 \mathrm{~cm}\)
3 \(20 \mathrm{~cm}\)
4 \(22 \mathrm{~cm}\)
Ray Optics

282381 A plano-convex lens fits exactly into a planoconcave lens and their plane surfaces are parallel to each other. If \(\mu_1\) and \(\mu_2\) are the refractive indices for plano-convex lens and plano-concave lens respectively and \(R\) is the radius of curvature of the curved surfaces of the lenses, then the focal-length of the combination is

1 \(\frac{\mathrm{R}}{2\left(\mu_1-\mu_2\right)}\)
2 \(\frac{2 \mathrm{R}}{\left(\mu_2-\mu_1\right)}\)
3 \(\frac{\mathrm{R}}{\mu_1-\mu_2}\)
4 \(\frac{\mathrm{R}}{2\left(\mu_1+\mu_2\right)}\)
Ray Optics

282382 You are given a thin diverging lens of \(20 \mathrm{~cm}\) focal length. Calculate the distance at which an object should be placed to obtain \(1 / 3\) lateral magnification.

1 \(10 \mathrm{~cm}\)
2 \(30 \mathrm{~cm}\)
3 \(40 \mathrm{~cm}\)
4 \(50 \mathrm{~cm}\)
Ray Optics

282383 A small object is enclosed in a transparent solid sphere of radius \(8 \mathrm{~cm}\). The object is situated at \(2 \mathbf{~ c m}\) from the centre of the sphere. If its image appears to be at \(3.2 \mathrm{~cm}\) from the nearest side, then the refractive index of the material of the sphere is

1 1.62
2 1.45
3 1.55
4 1.50
Ray Optics

282388 A glass convex lens is of refractive index \(\mathbf{1 . 5 5}\) with both faces of same radius of curvature. What will be the radius of curvature if focal length is to be \(20 \mathrm{~cm}\) ?

1 \(18 \mathrm{~cm}\)
2 \(21 \mathrm{~cm}\)
3 \(20 \mathrm{~cm}\)
4 \(22 \mathrm{~cm}\)
Ray Optics

282381 A plano-convex lens fits exactly into a planoconcave lens and their plane surfaces are parallel to each other. If \(\mu_1\) and \(\mu_2\) are the refractive indices for plano-convex lens and plano-concave lens respectively and \(R\) is the radius of curvature of the curved surfaces of the lenses, then the focal-length of the combination is

1 \(\frac{\mathrm{R}}{2\left(\mu_1-\mu_2\right)}\)
2 \(\frac{2 \mathrm{R}}{\left(\mu_2-\mu_1\right)}\)
3 \(\frac{\mathrm{R}}{\mu_1-\mu_2}\)
4 \(\frac{\mathrm{R}}{2\left(\mu_1+\mu_2\right)}\)
Ray Optics

282382 You are given a thin diverging lens of \(20 \mathrm{~cm}\) focal length. Calculate the distance at which an object should be placed to obtain \(1 / 3\) lateral magnification.

1 \(10 \mathrm{~cm}\)
2 \(30 \mathrm{~cm}\)
3 \(40 \mathrm{~cm}\)
4 \(50 \mathrm{~cm}\)
Ray Optics

282383 A small object is enclosed in a transparent solid sphere of radius \(8 \mathrm{~cm}\). The object is situated at \(2 \mathbf{~ c m}\) from the centre of the sphere. If its image appears to be at \(3.2 \mathrm{~cm}\) from the nearest side, then the refractive index of the material of the sphere is

1 1.62
2 1.45
3 1.55
4 1.50
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Ray Optics

282388 A glass convex lens is of refractive index \(\mathbf{1 . 5 5}\) with both faces of same radius of curvature. What will be the radius of curvature if focal length is to be \(20 \mathrm{~cm}\) ?

1 \(18 \mathrm{~cm}\)
2 \(21 \mathrm{~cm}\)
3 \(20 \mathrm{~cm}\)
4 \(22 \mathrm{~cm}\)
Ray Optics

282381 A plano-convex lens fits exactly into a planoconcave lens and their plane surfaces are parallel to each other. If \(\mu_1\) and \(\mu_2\) are the refractive indices for plano-convex lens and plano-concave lens respectively and \(R\) is the radius of curvature of the curved surfaces of the lenses, then the focal-length of the combination is

1 \(\frac{\mathrm{R}}{2\left(\mu_1-\mu_2\right)}\)
2 \(\frac{2 \mathrm{R}}{\left(\mu_2-\mu_1\right)}\)
3 \(\frac{\mathrm{R}}{\mu_1-\mu_2}\)
4 \(\frac{\mathrm{R}}{2\left(\mu_1+\mu_2\right)}\)
Ray Optics

282382 You are given a thin diverging lens of \(20 \mathrm{~cm}\) focal length. Calculate the distance at which an object should be placed to obtain \(1 / 3\) lateral magnification.

1 \(10 \mathrm{~cm}\)
2 \(30 \mathrm{~cm}\)
3 \(40 \mathrm{~cm}\)
4 \(50 \mathrm{~cm}\)
Ray Optics

282383 A small object is enclosed in a transparent solid sphere of radius \(8 \mathrm{~cm}\). The object is situated at \(2 \mathbf{~ c m}\) from the centre of the sphere. If its image appears to be at \(3.2 \mathrm{~cm}\) from the nearest side, then the refractive index of the material of the sphere is

1 1.62
2 1.45
3 1.55
4 1.50