282217
The apparent depth of a needle lying in a water beaker is found to be \(9 \mathrm{~cm}\). If water is replaced by a liquid of refractive index 1.5 , then the apparent depth of needle will be ( \(\mu\) of water is 4/3)
1 \(10 \mathrm{~cm}\)
2 \(9 \mathrm{~cm}\)
3 \(12 \mathrm{~cm}\)
4 \(7 \mathrm{~cm}\)
(e) \(8 \mathrm{~cm}\)
Explanation:
E : Given that, \(x\) is the real depth
Apparent depth, \(y=9 \mathrm{~cm}\)
Refractive index of liquid \(\left(\mu_l\right)=1.5\)
Refractive index of water \(\left(\mu_w\right)=4 / 3\)
We know,
\(\mu_w=\frac{\text { Realdepth }(x)}{\text { Apparent depth }(y)}\)
\(\begin{aligned}
\frac{4}{3}=\frac{\mathrm{x}}{9} \\
\mathrm{x}=12 \mathrm{~cm} \\
\mu_l=\frac{\text { Real depth }(\mathrm{x})}{\text { Apparent depth }\left(\mathrm{y}^{\prime}\right)} \\
\mathrm{y}^{\prime}=12 \times \frac{1}{1.5}=8 \mathrm{~cm}
\end{aligned}\)
Kerala CEE 2021
Ray Optics
282218
If refractive index of water is \(\frac{4}{3}\) and that of a given slab immersed in it is \(\frac{5}{3}\). The value of critical angle for a ray of light tending to go from glass to water is :
C: A well-cut diamond appears bright because of its total internal reflection.
Total internal reflection of light is the process in which light after refraction from one medium to another medium return to its original or previous medium from which it started travelling. It occurs only when light reaches a critical angle of light.
AP EAMCET-23.08.2021
Ray Optics
282220
Conditions for total internal reflection to occur are
1 \((\mathrm{b}, \mathrm{c})\)
2 \((\mathrm{a}, \mathrm{c})\)
3 \((\mathrm{a}, \mathrm{d})\)
4 \((\mathrm{b}, \mathrm{d})\)
Explanation:
A: Following are condition for total internal reflection.
(i) Light is travelling more slowly in the denser medium than rarer medium.
(ii) The angle of incidence should be greater than critical angle.
(iii) Denser medium has higher index of refraction than that of rarer.
282217
The apparent depth of a needle lying in a water beaker is found to be \(9 \mathrm{~cm}\). If water is replaced by a liquid of refractive index 1.5 , then the apparent depth of needle will be ( \(\mu\) of water is 4/3)
1 \(10 \mathrm{~cm}\)
2 \(9 \mathrm{~cm}\)
3 \(12 \mathrm{~cm}\)
4 \(7 \mathrm{~cm}\)
(e) \(8 \mathrm{~cm}\)
Explanation:
E : Given that, \(x\) is the real depth
Apparent depth, \(y=9 \mathrm{~cm}\)
Refractive index of liquid \(\left(\mu_l\right)=1.5\)
Refractive index of water \(\left(\mu_w\right)=4 / 3\)
We know,
\(\mu_w=\frac{\text { Realdepth }(x)}{\text { Apparent depth }(y)}\)
\(\begin{aligned}
\frac{4}{3}=\frac{\mathrm{x}}{9} \\
\mathrm{x}=12 \mathrm{~cm} \\
\mu_l=\frac{\text { Real depth }(\mathrm{x})}{\text { Apparent depth }\left(\mathrm{y}^{\prime}\right)} \\
\mathrm{y}^{\prime}=12 \times \frac{1}{1.5}=8 \mathrm{~cm}
\end{aligned}\)
Kerala CEE 2021
Ray Optics
282218
If refractive index of water is \(\frac{4}{3}\) and that of a given slab immersed in it is \(\frac{5}{3}\). The value of critical angle for a ray of light tending to go from glass to water is :
C: A well-cut diamond appears bright because of its total internal reflection.
Total internal reflection of light is the process in which light after refraction from one medium to another medium return to its original or previous medium from which it started travelling. It occurs only when light reaches a critical angle of light.
AP EAMCET-23.08.2021
Ray Optics
282220
Conditions for total internal reflection to occur are
1 \((\mathrm{b}, \mathrm{c})\)
2 \((\mathrm{a}, \mathrm{c})\)
3 \((\mathrm{a}, \mathrm{d})\)
4 \((\mathrm{b}, \mathrm{d})\)
Explanation:
A: Following are condition for total internal reflection.
(i) Light is travelling more slowly in the denser medium than rarer medium.
(ii) The angle of incidence should be greater than critical angle.
(iii) Denser medium has higher index of refraction than that of rarer.
282217
The apparent depth of a needle lying in a water beaker is found to be \(9 \mathrm{~cm}\). If water is replaced by a liquid of refractive index 1.5 , then the apparent depth of needle will be ( \(\mu\) of water is 4/3)
1 \(10 \mathrm{~cm}\)
2 \(9 \mathrm{~cm}\)
3 \(12 \mathrm{~cm}\)
4 \(7 \mathrm{~cm}\)
(e) \(8 \mathrm{~cm}\)
Explanation:
E : Given that, \(x\) is the real depth
Apparent depth, \(y=9 \mathrm{~cm}\)
Refractive index of liquid \(\left(\mu_l\right)=1.5\)
Refractive index of water \(\left(\mu_w\right)=4 / 3\)
We know,
\(\mu_w=\frac{\text { Realdepth }(x)}{\text { Apparent depth }(y)}\)
\(\begin{aligned}
\frac{4}{3}=\frac{\mathrm{x}}{9} \\
\mathrm{x}=12 \mathrm{~cm} \\
\mu_l=\frac{\text { Real depth }(\mathrm{x})}{\text { Apparent depth }\left(\mathrm{y}^{\prime}\right)} \\
\mathrm{y}^{\prime}=12 \times \frac{1}{1.5}=8 \mathrm{~cm}
\end{aligned}\)
Kerala CEE 2021
Ray Optics
282218
If refractive index of water is \(\frac{4}{3}\) and that of a given slab immersed in it is \(\frac{5}{3}\). The value of critical angle for a ray of light tending to go from glass to water is :
C: A well-cut diamond appears bright because of its total internal reflection.
Total internal reflection of light is the process in which light after refraction from one medium to another medium return to its original or previous medium from which it started travelling. It occurs only when light reaches a critical angle of light.
AP EAMCET-23.08.2021
Ray Optics
282220
Conditions for total internal reflection to occur are
1 \((\mathrm{b}, \mathrm{c})\)
2 \((\mathrm{a}, \mathrm{c})\)
3 \((\mathrm{a}, \mathrm{d})\)
4 \((\mathrm{b}, \mathrm{d})\)
Explanation:
A: Following are condition for total internal reflection.
(i) Light is travelling more slowly in the denser medium than rarer medium.
(ii) The angle of incidence should be greater than critical angle.
(iii) Denser medium has higher index of refraction than that of rarer.
282217
The apparent depth of a needle lying in a water beaker is found to be \(9 \mathrm{~cm}\). If water is replaced by a liquid of refractive index 1.5 , then the apparent depth of needle will be ( \(\mu\) of water is 4/3)
1 \(10 \mathrm{~cm}\)
2 \(9 \mathrm{~cm}\)
3 \(12 \mathrm{~cm}\)
4 \(7 \mathrm{~cm}\)
(e) \(8 \mathrm{~cm}\)
Explanation:
E : Given that, \(x\) is the real depth
Apparent depth, \(y=9 \mathrm{~cm}\)
Refractive index of liquid \(\left(\mu_l\right)=1.5\)
Refractive index of water \(\left(\mu_w\right)=4 / 3\)
We know,
\(\mu_w=\frac{\text { Realdepth }(x)}{\text { Apparent depth }(y)}\)
\(\begin{aligned}
\frac{4}{3}=\frac{\mathrm{x}}{9} \\
\mathrm{x}=12 \mathrm{~cm} \\
\mu_l=\frac{\text { Real depth }(\mathrm{x})}{\text { Apparent depth }\left(\mathrm{y}^{\prime}\right)} \\
\mathrm{y}^{\prime}=12 \times \frac{1}{1.5}=8 \mathrm{~cm}
\end{aligned}\)
Kerala CEE 2021
Ray Optics
282218
If refractive index of water is \(\frac{4}{3}\) and that of a given slab immersed in it is \(\frac{5}{3}\). The value of critical angle for a ray of light tending to go from glass to water is :
C: A well-cut diamond appears bright because of its total internal reflection.
Total internal reflection of light is the process in which light after refraction from one medium to another medium return to its original or previous medium from which it started travelling. It occurs only when light reaches a critical angle of light.
AP EAMCET-23.08.2021
Ray Optics
282220
Conditions for total internal reflection to occur are
1 \((\mathrm{b}, \mathrm{c})\)
2 \((\mathrm{a}, \mathrm{c})\)
3 \((\mathrm{a}, \mathrm{d})\)
4 \((\mathrm{b}, \mathrm{d})\)
Explanation:
A: Following are condition for total internal reflection.
(i) Light is travelling more slowly in the denser medium than rarer medium.
(ii) The angle of incidence should be greater than critical angle.
(iii) Denser medium has higher index of refraction than that of rarer.
