282241
Light travelling from a transparent medium to air undergoes total internal reflection at an angle of incident of \(45^{\circ}\). Then refractive index of the medium may be
282242
In the formation of a rainbow, light from the sun on water droplets undergoes
1 dispersion only
2 only total internal reflection
3 dispersion and total internal reflection
4 None of the above
Explanation:
C: In the Rainbow formation dispersion and total internal reflection both takes place inside the water droplets.
- Dispersion of light - The phenomenon of splitting of a beam of light into its seven constituent colours when passed through a transparent medium called dispersion of white light.
- Total internal Reflection - Complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium called total internal reflection.
Manipal UGET-2019
Ray Optics
282243
In a spherical glass marble of radius \(6 \mathrm{~cm}\), a centre of the marble. The apparent position of the air bubble from the nearest point on the surface of the marble is about, (refractive index of glass is 1.5 )
1 \(3.3 \mathrm{~cm}\)
2 \(4.6 \mathrm{~cm}\)
3 \(5.4 \mathrm{~cm}\)
4 \(7.0 \mathrm{~cm}\)
Explanation:
A: Given, Real distance \(=(6-1)=5 \mathrm{~cm}, \mu=\) 1.5
Apparent distance \(=\) ?
Refractive index \(=\frac{\text { Real Distance }}{\text { Apparant Distance }}\)
Apparent Distance \(=\frac{5}{1.5}=3.3 \mathrm{~cm}\)
AP EAMCET (22.04.2019) Shift-II
Ray Optics
282244
A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to three times the square of the depth of the lake refractive index of water in the lake is
1 \(\sqrt{\pi+1}\)
2 \(\sqrt{\frac{\pi}{3}+1}\)
3 \(\frac{\pi}{3}+1\)
4 \(\frac{\pi}{4}+1\)
Explanation:
B:
Depth of lake \(=\mathrm{H}\)
Radius of illuminated circle \(=\mathrm{R}\)
Given, \(\pi \mathrm{R}^2=3 \mathrm{H}^2\)
Critical angle, \(\quad \sin \theta_{\mathrm{c}}=\frac{\mathrm{R}}{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}\)
Also, \(\quad \sin \theta_{\mathrm{c}}=\frac{1}{\mu}\)
So, \(\quad \begin{aligned} \mu & =\frac{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}{\mathrm{R}}=\frac{\mathrm{R} \sqrt{1+\frac{\pi}{3}}}{R} \\ \mu & =\sqrt{\frac{\pi}{3}+1}\end{aligned} \quad\) [from (i)]
AP EAMCET (Medical)-24.04.2019
Ray Optics
282245
In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be angle of refraction?
1 \(0^{\circ}\)
2 Equal to angle of incidence
3 \(90^{\circ}\)
4 \(180^{\circ}\)
Explanation:
C: According to question,
In total internal reflection,
If \(\quad i=\) critical angle \(\left(\theta_c\right)\)
Then, angle of refraction is \(90^{\circ}\).
282241
Light travelling from a transparent medium to air undergoes total internal reflection at an angle of incident of \(45^{\circ}\). Then refractive index of the medium may be
282242
In the formation of a rainbow, light from the sun on water droplets undergoes
1 dispersion only
2 only total internal reflection
3 dispersion and total internal reflection
4 None of the above
Explanation:
C: In the Rainbow formation dispersion and total internal reflection both takes place inside the water droplets.
- Dispersion of light - The phenomenon of splitting of a beam of light into its seven constituent colours when passed through a transparent medium called dispersion of white light.
- Total internal Reflection - Complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium called total internal reflection.
Manipal UGET-2019
Ray Optics
282243
In a spherical glass marble of radius \(6 \mathrm{~cm}\), a centre of the marble. The apparent position of the air bubble from the nearest point on the surface of the marble is about, (refractive index of glass is 1.5 )
1 \(3.3 \mathrm{~cm}\)
2 \(4.6 \mathrm{~cm}\)
3 \(5.4 \mathrm{~cm}\)
4 \(7.0 \mathrm{~cm}\)
Explanation:
A: Given, Real distance \(=(6-1)=5 \mathrm{~cm}, \mu=\) 1.5
Apparent distance \(=\) ?
Refractive index \(=\frac{\text { Real Distance }}{\text { Apparant Distance }}\)
Apparent Distance \(=\frac{5}{1.5}=3.3 \mathrm{~cm}\)
AP EAMCET (22.04.2019) Shift-II
Ray Optics
282244
A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to three times the square of the depth of the lake refractive index of water in the lake is
1 \(\sqrt{\pi+1}\)
2 \(\sqrt{\frac{\pi}{3}+1}\)
3 \(\frac{\pi}{3}+1\)
4 \(\frac{\pi}{4}+1\)
Explanation:
B:
Depth of lake \(=\mathrm{H}\)
Radius of illuminated circle \(=\mathrm{R}\)
Given, \(\pi \mathrm{R}^2=3 \mathrm{H}^2\)
Critical angle, \(\quad \sin \theta_{\mathrm{c}}=\frac{\mathrm{R}}{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}\)
Also, \(\quad \sin \theta_{\mathrm{c}}=\frac{1}{\mu}\)
So, \(\quad \begin{aligned} \mu & =\frac{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}{\mathrm{R}}=\frac{\mathrm{R} \sqrt{1+\frac{\pi}{3}}}{R} \\ \mu & =\sqrt{\frac{\pi}{3}+1}\end{aligned} \quad\) [from (i)]
AP EAMCET (Medical)-24.04.2019
Ray Optics
282245
In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be angle of refraction?
1 \(0^{\circ}\)
2 Equal to angle of incidence
3 \(90^{\circ}\)
4 \(180^{\circ}\)
Explanation:
C: According to question,
In total internal reflection,
If \(\quad i=\) critical angle \(\left(\theta_c\right)\)
Then, angle of refraction is \(90^{\circ}\).
NEET Test Series from KOTA - 10 Papers In MS WORD
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Ray Optics
282241
Light travelling from a transparent medium to air undergoes total internal reflection at an angle of incident of \(45^{\circ}\). Then refractive index of the medium may be
282242
In the formation of a rainbow, light from the sun on water droplets undergoes
1 dispersion only
2 only total internal reflection
3 dispersion and total internal reflection
4 None of the above
Explanation:
C: In the Rainbow formation dispersion and total internal reflection both takes place inside the water droplets.
- Dispersion of light - The phenomenon of splitting of a beam of light into its seven constituent colours when passed through a transparent medium called dispersion of white light.
- Total internal Reflection - Complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium called total internal reflection.
Manipal UGET-2019
Ray Optics
282243
In a spherical glass marble of radius \(6 \mathrm{~cm}\), a centre of the marble. The apparent position of the air bubble from the nearest point on the surface of the marble is about, (refractive index of glass is 1.5 )
1 \(3.3 \mathrm{~cm}\)
2 \(4.6 \mathrm{~cm}\)
3 \(5.4 \mathrm{~cm}\)
4 \(7.0 \mathrm{~cm}\)
Explanation:
A: Given, Real distance \(=(6-1)=5 \mathrm{~cm}, \mu=\) 1.5
Apparent distance \(=\) ?
Refractive index \(=\frac{\text { Real Distance }}{\text { Apparant Distance }}\)
Apparent Distance \(=\frac{5}{1.5}=3.3 \mathrm{~cm}\)
AP EAMCET (22.04.2019) Shift-II
Ray Optics
282244
A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to three times the square of the depth of the lake refractive index of water in the lake is
1 \(\sqrt{\pi+1}\)
2 \(\sqrt{\frac{\pi}{3}+1}\)
3 \(\frac{\pi}{3}+1\)
4 \(\frac{\pi}{4}+1\)
Explanation:
B:
Depth of lake \(=\mathrm{H}\)
Radius of illuminated circle \(=\mathrm{R}\)
Given, \(\pi \mathrm{R}^2=3 \mathrm{H}^2\)
Critical angle, \(\quad \sin \theta_{\mathrm{c}}=\frac{\mathrm{R}}{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}\)
Also, \(\quad \sin \theta_{\mathrm{c}}=\frac{1}{\mu}\)
So, \(\quad \begin{aligned} \mu & =\frac{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}{\mathrm{R}}=\frac{\mathrm{R} \sqrt{1+\frac{\pi}{3}}}{R} \\ \mu & =\sqrt{\frac{\pi}{3}+1}\end{aligned} \quad\) [from (i)]
AP EAMCET (Medical)-24.04.2019
Ray Optics
282245
In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be angle of refraction?
1 \(0^{\circ}\)
2 Equal to angle of incidence
3 \(90^{\circ}\)
4 \(180^{\circ}\)
Explanation:
C: According to question,
In total internal reflection,
If \(\quad i=\) critical angle \(\left(\theta_c\right)\)
Then, angle of refraction is \(90^{\circ}\).
282241
Light travelling from a transparent medium to air undergoes total internal reflection at an angle of incident of \(45^{\circ}\). Then refractive index of the medium may be
282242
In the formation of a rainbow, light from the sun on water droplets undergoes
1 dispersion only
2 only total internal reflection
3 dispersion and total internal reflection
4 None of the above
Explanation:
C: In the Rainbow formation dispersion and total internal reflection both takes place inside the water droplets.
- Dispersion of light - The phenomenon of splitting of a beam of light into its seven constituent colours when passed through a transparent medium called dispersion of white light.
- Total internal Reflection - Complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium called total internal reflection.
Manipal UGET-2019
Ray Optics
282243
In a spherical glass marble of radius \(6 \mathrm{~cm}\), a centre of the marble. The apparent position of the air bubble from the nearest point on the surface of the marble is about, (refractive index of glass is 1.5 )
1 \(3.3 \mathrm{~cm}\)
2 \(4.6 \mathrm{~cm}\)
3 \(5.4 \mathrm{~cm}\)
4 \(7.0 \mathrm{~cm}\)
Explanation:
A: Given, Real distance \(=(6-1)=5 \mathrm{~cm}, \mu=\) 1.5
Apparent distance \(=\) ?
Refractive index \(=\frac{\text { Real Distance }}{\text { Apparant Distance }}\)
Apparent Distance \(=\frac{5}{1.5}=3.3 \mathrm{~cm}\)
AP EAMCET (22.04.2019) Shift-II
Ray Optics
282244
A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to three times the square of the depth of the lake refractive index of water in the lake is
1 \(\sqrt{\pi+1}\)
2 \(\sqrt{\frac{\pi}{3}+1}\)
3 \(\frac{\pi}{3}+1\)
4 \(\frac{\pi}{4}+1\)
Explanation:
B:
Depth of lake \(=\mathrm{H}\)
Radius of illuminated circle \(=\mathrm{R}\)
Given, \(\pi \mathrm{R}^2=3 \mathrm{H}^2\)
Critical angle, \(\quad \sin \theta_{\mathrm{c}}=\frac{\mathrm{R}}{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}\)
Also, \(\quad \sin \theta_{\mathrm{c}}=\frac{1}{\mu}\)
So, \(\quad \begin{aligned} \mu & =\frac{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}{\mathrm{R}}=\frac{\mathrm{R} \sqrt{1+\frac{\pi}{3}}}{R} \\ \mu & =\sqrt{\frac{\pi}{3}+1}\end{aligned} \quad\) [from (i)]
AP EAMCET (Medical)-24.04.2019
Ray Optics
282245
In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be angle of refraction?
1 \(0^{\circ}\)
2 Equal to angle of incidence
3 \(90^{\circ}\)
4 \(180^{\circ}\)
Explanation:
C: According to question,
In total internal reflection,
If \(\quad i=\) critical angle \(\left(\theta_c\right)\)
Then, angle of refraction is \(90^{\circ}\).
282241
Light travelling from a transparent medium to air undergoes total internal reflection at an angle of incident of \(45^{\circ}\). Then refractive index of the medium may be
282242
In the formation of a rainbow, light from the sun on water droplets undergoes
1 dispersion only
2 only total internal reflection
3 dispersion and total internal reflection
4 None of the above
Explanation:
C: In the Rainbow formation dispersion and total internal reflection both takes place inside the water droplets.
- Dispersion of light - The phenomenon of splitting of a beam of light into its seven constituent colours when passed through a transparent medium called dispersion of white light.
- Total internal Reflection - Complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium called total internal reflection.
Manipal UGET-2019
Ray Optics
282243
In a spherical glass marble of radius \(6 \mathrm{~cm}\), a centre of the marble. The apparent position of the air bubble from the nearest point on the surface of the marble is about, (refractive index of glass is 1.5 )
1 \(3.3 \mathrm{~cm}\)
2 \(4.6 \mathrm{~cm}\)
3 \(5.4 \mathrm{~cm}\)
4 \(7.0 \mathrm{~cm}\)
Explanation:
A: Given, Real distance \(=(6-1)=5 \mathrm{~cm}, \mu=\) 1.5
Apparent distance \(=\) ?
Refractive index \(=\frac{\text { Real Distance }}{\text { Apparant Distance }}\)
Apparent Distance \(=\frac{5}{1.5}=3.3 \mathrm{~cm}\)
AP EAMCET (22.04.2019) Shift-II
Ray Optics
282244
A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to three times the square of the depth of the lake refractive index of water in the lake is
1 \(\sqrt{\pi+1}\)
2 \(\sqrt{\frac{\pi}{3}+1}\)
3 \(\frac{\pi}{3}+1\)
4 \(\frac{\pi}{4}+1\)
Explanation:
B:
Depth of lake \(=\mathrm{H}\)
Radius of illuminated circle \(=\mathrm{R}\)
Given, \(\pi \mathrm{R}^2=3 \mathrm{H}^2\)
Critical angle, \(\quad \sin \theta_{\mathrm{c}}=\frac{\mathrm{R}}{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}\)
Also, \(\quad \sin \theta_{\mathrm{c}}=\frac{1}{\mu}\)
So, \(\quad \begin{aligned} \mu & =\frac{\sqrt{\mathrm{R}^2+\mathrm{H}^2}}{\mathrm{R}}=\frac{\mathrm{R} \sqrt{1+\frac{\pi}{3}}}{R} \\ \mu & =\sqrt{\frac{\pi}{3}+1}\end{aligned} \quad\) [from (i)]
AP EAMCET (Medical)-24.04.2019
Ray Optics
282245
In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be angle of refraction?
1 \(0^{\circ}\)
2 Equal to angle of incidence
3 \(90^{\circ}\)
4 \(180^{\circ}\)
Explanation:
C: According to question,
In total internal reflection,
If \(\quad i=\) critical angle \(\left(\theta_c\right)\)
Then, angle of refraction is \(90^{\circ}\).
