281989
A girl is standing $7 \mathrm{~m}$ from a plane mirror. The distance of the girl from her image in the mirror is
1 $3.5 \mathrm{~m}$
2 $7 \mathrm{~m}$
3 $10.5 \mathrm{~m}$
4 $14 \mathrm{~m}$
Explanation:
D:
Hence, Distance of image of girl
$=7+7=14 \mathrm{~m} \text {. }$
SRMJEEE - 2015
Ray Optics
281945
Light appears to travel in a straight line, because
1 its wavelength is very small
2 its velocity is large
3 it is not absorbed by surroundings
4 it is reflected by surroundings
Explanation:
ALight appears to travel in a straight line because its wavelength is too small (i.e. in the order of nanometer) and obstacles of this size cannot be determined by our naked eyes.
Hence, we feel that light travel along a straight line.
AMU-2017
Ray Optics
281946
Assertion: Plane mirror may form real image.
Reason: Plane mirror forms virtual image, if object is real .
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
BPlane mirror may form real image, if object is virtual for real object, plane mirror form virtual image.
AIIMS-2017
Ray Optics
281990
A ray deviates at $90^{\circ}$ after suffering reflection from a mirror. The angle of incidence is
281947
A $1 \mathrm{~cm}$ height needle is placed at a distance of $0.1 \mathrm{~m}$ from a convex mirror of focal length 0.05 , then size of the image is
1 $1 \mathrm{~cm}$
2 $0.66 \mathrm{~cm}$
3 $0.33 \mathrm{~cm}$
4 $0.5 \mathrm{~cm}$
Explanation:
C: Given,
Height of object $\left(\mathrm{h}_0\right)=1 \mathrm{~cm}=1 \times 10^{-2} \mathrm{~m}$
Distance of object from convex mirror $(\mathrm{u})=-0.1 \mathrm{~m}$
Focal length of convex mirror $(\mathrm{f})=0.05 \mathrm{~m}$
From the mirror formula
$\begin{aligned}
\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}} \\
\frac{1}{0.05}=\frac{1}{-0.1}+\frac{1}{\mathrm{v}} \\
\frac{1}{\mathrm{v}}=\frac{1}{0.05}+\frac{1}{0.1}
\end{aligned}$
$\frac{1}{\mathrm{v}}=20+10=30$
$\mathrm{v}=\frac{1}{30}$
$\mathrm{v}=0.033 \mathrm{~m}$
Magnification $(\mathrm{m})=\frac{\mathrm{h}_{\mathrm{i}}}{\mathrm{h}_{\mathrm{o}}}=\frac{-\mathrm{v}}{\mathrm{u}}$
$\frac{\mathrm{h}_{\mathrm{i}}}{1 \times 10^{-2}}=\frac{0.033}{(-0.1)}$
$\mathrm{h}_{\mathrm{i}}=0.33 \times 10^{-2} \mathrm{~m}=0.33 \mathrm{~cm}$
281989
A girl is standing $7 \mathrm{~m}$ from a plane mirror. The distance of the girl from her image in the mirror is
1 $3.5 \mathrm{~m}$
2 $7 \mathrm{~m}$
3 $10.5 \mathrm{~m}$
4 $14 \mathrm{~m}$
Explanation:
D:
Hence, Distance of image of girl
$=7+7=14 \mathrm{~m} \text {. }$
SRMJEEE - 2015
Ray Optics
281945
Light appears to travel in a straight line, because
1 its wavelength is very small
2 its velocity is large
3 it is not absorbed by surroundings
4 it is reflected by surroundings
Explanation:
ALight appears to travel in a straight line because its wavelength is too small (i.e. in the order of nanometer) and obstacles of this size cannot be determined by our naked eyes.
Hence, we feel that light travel along a straight line.
AMU-2017
Ray Optics
281946
Assertion: Plane mirror may form real image.
Reason: Plane mirror forms virtual image, if object is real .
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
BPlane mirror may form real image, if object is virtual for real object, plane mirror form virtual image.
AIIMS-2017
Ray Optics
281990
A ray deviates at $90^{\circ}$ after suffering reflection from a mirror. The angle of incidence is
281947
A $1 \mathrm{~cm}$ height needle is placed at a distance of $0.1 \mathrm{~m}$ from a convex mirror of focal length 0.05 , then size of the image is
1 $1 \mathrm{~cm}$
2 $0.66 \mathrm{~cm}$
3 $0.33 \mathrm{~cm}$
4 $0.5 \mathrm{~cm}$
Explanation:
C: Given,
Height of object $\left(\mathrm{h}_0\right)=1 \mathrm{~cm}=1 \times 10^{-2} \mathrm{~m}$
Distance of object from convex mirror $(\mathrm{u})=-0.1 \mathrm{~m}$
Focal length of convex mirror $(\mathrm{f})=0.05 \mathrm{~m}$
From the mirror formula
$\begin{aligned}
\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}} \\
\frac{1}{0.05}=\frac{1}{-0.1}+\frac{1}{\mathrm{v}} \\
\frac{1}{\mathrm{v}}=\frac{1}{0.05}+\frac{1}{0.1}
\end{aligned}$
$\frac{1}{\mathrm{v}}=20+10=30$
$\mathrm{v}=\frac{1}{30}$
$\mathrm{v}=0.033 \mathrm{~m}$
Magnification $(\mathrm{m})=\frac{\mathrm{h}_{\mathrm{i}}}{\mathrm{h}_{\mathrm{o}}}=\frac{-\mathrm{v}}{\mathrm{u}}$
$\frac{\mathrm{h}_{\mathrm{i}}}{1 \times 10^{-2}}=\frac{0.033}{(-0.1)}$
$\mathrm{h}_{\mathrm{i}}=0.33 \times 10^{-2} \mathrm{~m}=0.33 \mathrm{~cm}$
281989
A girl is standing $7 \mathrm{~m}$ from a plane mirror. The distance of the girl from her image in the mirror is
1 $3.5 \mathrm{~m}$
2 $7 \mathrm{~m}$
3 $10.5 \mathrm{~m}$
4 $14 \mathrm{~m}$
Explanation:
D:
Hence, Distance of image of girl
$=7+7=14 \mathrm{~m} \text {. }$
SRMJEEE - 2015
Ray Optics
281945
Light appears to travel in a straight line, because
1 its wavelength is very small
2 its velocity is large
3 it is not absorbed by surroundings
4 it is reflected by surroundings
Explanation:
ALight appears to travel in a straight line because its wavelength is too small (i.e. in the order of nanometer) and obstacles of this size cannot be determined by our naked eyes.
Hence, we feel that light travel along a straight line.
AMU-2017
Ray Optics
281946
Assertion: Plane mirror may form real image.
Reason: Plane mirror forms virtual image, if object is real .
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
BPlane mirror may form real image, if object is virtual for real object, plane mirror form virtual image.
AIIMS-2017
Ray Optics
281990
A ray deviates at $90^{\circ}$ after suffering reflection from a mirror. The angle of incidence is
281947
A $1 \mathrm{~cm}$ height needle is placed at a distance of $0.1 \mathrm{~m}$ from a convex mirror of focal length 0.05 , then size of the image is
1 $1 \mathrm{~cm}$
2 $0.66 \mathrm{~cm}$
3 $0.33 \mathrm{~cm}$
4 $0.5 \mathrm{~cm}$
Explanation:
C: Given,
Height of object $\left(\mathrm{h}_0\right)=1 \mathrm{~cm}=1 \times 10^{-2} \mathrm{~m}$
Distance of object from convex mirror $(\mathrm{u})=-0.1 \mathrm{~m}$
Focal length of convex mirror $(\mathrm{f})=0.05 \mathrm{~m}$
From the mirror formula
$\begin{aligned}
\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}} \\
\frac{1}{0.05}=\frac{1}{-0.1}+\frac{1}{\mathrm{v}} \\
\frac{1}{\mathrm{v}}=\frac{1}{0.05}+\frac{1}{0.1}
\end{aligned}$
$\frac{1}{\mathrm{v}}=20+10=30$
$\mathrm{v}=\frac{1}{30}$
$\mathrm{v}=0.033 \mathrm{~m}$
Magnification $(\mathrm{m})=\frac{\mathrm{h}_{\mathrm{i}}}{\mathrm{h}_{\mathrm{o}}}=\frac{-\mathrm{v}}{\mathrm{u}}$
$\frac{\mathrm{h}_{\mathrm{i}}}{1 \times 10^{-2}}=\frac{0.033}{(-0.1)}$
$\mathrm{h}_{\mathrm{i}}=0.33 \times 10^{-2} \mathrm{~m}=0.33 \mathrm{~cm}$
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Ray Optics
281989
A girl is standing $7 \mathrm{~m}$ from a plane mirror. The distance of the girl from her image in the mirror is
1 $3.5 \mathrm{~m}$
2 $7 \mathrm{~m}$
3 $10.5 \mathrm{~m}$
4 $14 \mathrm{~m}$
Explanation:
D:
Hence, Distance of image of girl
$=7+7=14 \mathrm{~m} \text {. }$
SRMJEEE - 2015
Ray Optics
281945
Light appears to travel in a straight line, because
1 its wavelength is very small
2 its velocity is large
3 it is not absorbed by surroundings
4 it is reflected by surroundings
Explanation:
ALight appears to travel in a straight line because its wavelength is too small (i.e. in the order of nanometer) and obstacles of this size cannot be determined by our naked eyes.
Hence, we feel that light travel along a straight line.
AMU-2017
Ray Optics
281946
Assertion: Plane mirror may form real image.
Reason: Plane mirror forms virtual image, if object is real .
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
BPlane mirror may form real image, if object is virtual for real object, plane mirror form virtual image.
AIIMS-2017
Ray Optics
281990
A ray deviates at $90^{\circ}$ after suffering reflection from a mirror. The angle of incidence is
281947
A $1 \mathrm{~cm}$ height needle is placed at a distance of $0.1 \mathrm{~m}$ from a convex mirror of focal length 0.05 , then size of the image is
1 $1 \mathrm{~cm}$
2 $0.66 \mathrm{~cm}$
3 $0.33 \mathrm{~cm}$
4 $0.5 \mathrm{~cm}$
Explanation:
C: Given,
Height of object $\left(\mathrm{h}_0\right)=1 \mathrm{~cm}=1 \times 10^{-2} \mathrm{~m}$
Distance of object from convex mirror $(\mathrm{u})=-0.1 \mathrm{~m}$
Focal length of convex mirror $(\mathrm{f})=0.05 \mathrm{~m}$
From the mirror formula
$\begin{aligned}
\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}} \\
\frac{1}{0.05}=\frac{1}{-0.1}+\frac{1}{\mathrm{v}} \\
\frac{1}{\mathrm{v}}=\frac{1}{0.05}+\frac{1}{0.1}
\end{aligned}$
$\frac{1}{\mathrm{v}}=20+10=30$
$\mathrm{v}=\frac{1}{30}$
$\mathrm{v}=0.033 \mathrm{~m}$
Magnification $(\mathrm{m})=\frac{\mathrm{h}_{\mathrm{i}}}{\mathrm{h}_{\mathrm{o}}}=\frac{-\mathrm{v}}{\mathrm{u}}$
$\frac{\mathrm{h}_{\mathrm{i}}}{1 \times 10^{-2}}=\frac{0.033}{(-0.1)}$
$\mathrm{h}_{\mathrm{i}}=0.33 \times 10^{-2} \mathrm{~m}=0.33 \mathrm{~cm}$
281989
A girl is standing $7 \mathrm{~m}$ from a plane mirror. The distance of the girl from her image in the mirror is
1 $3.5 \mathrm{~m}$
2 $7 \mathrm{~m}$
3 $10.5 \mathrm{~m}$
4 $14 \mathrm{~m}$
Explanation:
D:
Hence, Distance of image of girl
$=7+7=14 \mathrm{~m} \text {. }$
SRMJEEE - 2015
Ray Optics
281945
Light appears to travel in a straight line, because
1 its wavelength is very small
2 its velocity is large
3 it is not absorbed by surroundings
4 it is reflected by surroundings
Explanation:
ALight appears to travel in a straight line because its wavelength is too small (i.e. in the order of nanometer) and obstacles of this size cannot be determined by our naked eyes.
Hence, we feel that light travel along a straight line.
AMU-2017
Ray Optics
281946
Assertion: Plane mirror may form real image.
Reason: Plane mirror forms virtual image, if object is real .
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
BPlane mirror may form real image, if object is virtual for real object, plane mirror form virtual image.
AIIMS-2017
Ray Optics
281990
A ray deviates at $90^{\circ}$ after suffering reflection from a mirror. The angle of incidence is
281947
A $1 \mathrm{~cm}$ height needle is placed at a distance of $0.1 \mathrm{~m}$ from a convex mirror of focal length 0.05 , then size of the image is
1 $1 \mathrm{~cm}$
2 $0.66 \mathrm{~cm}$
3 $0.33 \mathrm{~cm}$
4 $0.5 \mathrm{~cm}$
Explanation:
C: Given,
Height of object $\left(\mathrm{h}_0\right)=1 \mathrm{~cm}=1 \times 10^{-2} \mathrm{~m}$
Distance of object from convex mirror $(\mathrm{u})=-0.1 \mathrm{~m}$
Focal length of convex mirror $(\mathrm{f})=0.05 \mathrm{~m}$
From the mirror formula
$\begin{aligned}
\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}} \\
\frac{1}{0.05}=\frac{1}{-0.1}+\frac{1}{\mathrm{v}} \\
\frac{1}{\mathrm{v}}=\frac{1}{0.05}+\frac{1}{0.1}
\end{aligned}$
$\frac{1}{\mathrm{v}}=20+10=30$
$\mathrm{v}=\frac{1}{30}$
$\mathrm{v}=0.033 \mathrm{~m}$
Magnification $(\mathrm{m})=\frac{\mathrm{h}_{\mathrm{i}}}{\mathrm{h}_{\mathrm{o}}}=\frac{-\mathrm{v}}{\mathrm{u}}$
$\frac{\mathrm{h}_{\mathrm{i}}}{1 \times 10^{-2}}=\frac{0.033}{(-0.1)}$
$\mathrm{h}_{\mathrm{i}}=0.33 \times 10^{-2} \mathrm{~m}=0.33 \mathrm{~cm}$