(c) A transformer is employed to obtain a Suitable A. C. voltage.
NCERT Page-260 / N-194
AC (NCERT)
274692
A transformer has an efficiency of $80\text{ }\!\!%\!\!\text{ }$. It works at $4\text{kW}$ and $100\text{V}$. If secondary voltage is $240\text{V}$, the current in primary coil is
1 $0.4\text{A}$
2 $4\text{A}$
3 $10\text{A}$
4 $40\text{A}$
Explanation:
(d) As ${{\text{E}}_{\text{p}}}{{\text{I}}_{\text{p}}}={{\text{P}}_{\text{i}}}\therefore {{\text{I}}_{\text{p}}}=\frac{{{\text{P}}_{\text{i}}}}{{{\text{E}}_{\text{p}}}}=\frac{4000}{100}=40\text{A}$.
NCERT Page-261 / N-195
AC (NCERT)
274693
The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at $1000\text{V}$ is $12\text{kW}$, what is the primary voltage?
1 $200\text{V}$
2 $300\text{V}$
3 $400\text{V}$
4 $500\text{V}$
Explanation:
(a) ${{N}_{P}}=400,{{N}_{s}}=2000$ and ${{V}_{s}}=1000\text{V}$.
$\frac{{{V}_{P}}}{{{V}_{S}}}=\frac{{{N}_{P}}}{{{N}_{S}}}$ of, ${{V}_{P}}=\frac{{{V}_{S}}\times {{N}_{P}}}{{{N}_{S}}}=\frac{1000\times 400}{2000}=200\text{V}$.
NCERT Page-261 / N-195
AC (NCERT)
274689
A transformer is used to light a $140\text{W},24\text{V}$ bulb from a $240\text{V}$ a.c. mains. The current in the main cable is $0.7\text{A}$. The efficiency of the transformer is
1 $63.8\text{ }\!\!%\!\!\text{ }$
2 $83.3\text{ }\!\!%\!\!\text{ }$
3 $16.7\text{ }\!\!%\!\!\text{ }$
4 $36.2\text{ }\!\!%\!\!\text{ }$
Explanation:
(b) Power of source $=\text{EI}=240\times 0.7=166$
$\Rightarrow $ Efficiency $=\frac{140}{166}\Rightarrow \eta =83.3\text{ }\!\!%\!\!\text{ }$
NCERT Page-261 / N-195
AC (NCERT)
274690
Eddy currents in the core of transformer can't be developed by
1 increasing the number of turns in secondary coil
(c) A transformer is employed to obtain a Suitable A. C. voltage.
NCERT Page-260 / N-194
AC (NCERT)
274692
A transformer has an efficiency of $80\text{ }\!\!%\!\!\text{ }$. It works at $4\text{kW}$ and $100\text{V}$. If secondary voltage is $240\text{V}$, the current in primary coil is
1 $0.4\text{A}$
2 $4\text{A}$
3 $10\text{A}$
4 $40\text{A}$
Explanation:
(d) As ${{\text{E}}_{\text{p}}}{{\text{I}}_{\text{p}}}={{\text{P}}_{\text{i}}}\therefore {{\text{I}}_{\text{p}}}=\frac{{{\text{P}}_{\text{i}}}}{{{\text{E}}_{\text{p}}}}=\frac{4000}{100}=40\text{A}$.
NCERT Page-261 / N-195
AC (NCERT)
274693
The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at $1000\text{V}$ is $12\text{kW}$, what is the primary voltage?
1 $200\text{V}$
2 $300\text{V}$
3 $400\text{V}$
4 $500\text{V}$
Explanation:
(a) ${{N}_{P}}=400,{{N}_{s}}=2000$ and ${{V}_{s}}=1000\text{V}$.
$\frac{{{V}_{P}}}{{{V}_{S}}}=\frac{{{N}_{P}}}{{{N}_{S}}}$ of, ${{V}_{P}}=\frac{{{V}_{S}}\times {{N}_{P}}}{{{N}_{S}}}=\frac{1000\times 400}{2000}=200\text{V}$.
NCERT Page-261 / N-195
AC (NCERT)
274689
A transformer is used to light a $140\text{W},24\text{V}$ bulb from a $240\text{V}$ a.c. mains. The current in the main cable is $0.7\text{A}$. The efficiency of the transformer is
1 $63.8\text{ }\!\!%\!\!\text{ }$
2 $83.3\text{ }\!\!%\!\!\text{ }$
3 $16.7\text{ }\!\!%\!\!\text{ }$
4 $36.2\text{ }\!\!%\!\!\text{ }$
Explanation:
(b) Power of source $=\text{EI}=240\times 0.7=166$
$\Rightarrow $ Efficiency $=\frac{140}{166}\Rightarrow \eta =83.3\text{ }\!\!%\!\!\text{ }$
NCERT Page-261 / N-195
AC (NCERT)
274690
Eddy currents in the core of transformer can't be developed by
1 increasing the number of turns in secondary coil
(c) A transformer is employed to obtain a Suitable A. C. voltage.
NCERT Page-260 / N-194
AC (NCERT)
274692
A transformer has an efficiency of $80\text{ }\!\!%\!\!\text{ }$. It works at $4\text{kW}$ and $100\text{V}$. If secondary voltage is $240\text{V}$, the current in primary coil is
1 $0.4\text{A}$
2 $4\text{A}$
3 $10\text{A}$
4 $40\text{A}$
Explanation:
(d) As ${{\text{E}}_{\text{p}}}{{\text{I}}_{\text{p}}}={{\text{P}}_{\text{i}}}\therefore {{\text{I}}_{\text{p}}}=\frac{{{\text{P}}_{\text{i}}}}{{{\text{E}}_{\text{p}}}}=\frac{4000}{100}=40\text{A}$.
NCERT Page-261 / N-195
AC (NCERT)
274693
The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at $1000\text{V}$ is $12\text{kW}$, what is the primary voltage?
1 $200\text{V}$
2 $300\text{V}$
3 $400\text{V}$
4 $500\text{V}$
Explanation:
(a) ${{N}_{P}}=400,{{N}_{s}}=2000$ and ${{V}_{s}}=1000\text{V}$.
$\frac{{{V}_{P}}}{{{V}_{S}}}=\frac{{{N}_{P}}}{{{N}_{S}}}$ of, ${{V}_{P}}=\frac{{{V}_{S}}\times {{N}_{P}}}{{{N}_{S}}}=\frac{1000\times 400}{2000}=200\text{V}$.
NCERT Page-261 / N-195
AC (NCERT)
274689
A transformer is used to light a $140\text{W},24\text{V}$ bulb from a $240\text{V}$ a.c. mains. The current in the main cable is $0.7\text{A}$. The efficiency of the transformer is
1 $63.8\text{ }\!\!%\!\!\text{ }$
2 $83.3\text{ }\!\!%\!\!\text{ }$
3 $16.7\text{ }\!\!%\!\!\text{ }$
4 $36.2\text{ }\!\!%\!\!\text{ }$
Explanation:
(b) Power of source $=\text{EI}=240\times 0.7=166$
$\Rightarrow $ Efficiency $=\frac{140}{166}\Rightarrow \eta =83.3\text{ }\!\!%\!\!\text{ }$
NCERT Page-261 / N-195
AC (NCERT)
274690
Eddy currents in the core of transformer can't be developed by
1 increasing the number of turns in secondary coil
NEET Test Series from KOTA - 10 Papers In MS WORD
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AC (NCERT)
274682
A transformer is employed to
1 convert A.C. into D.C.
2 convert D.C. into A.C.
3 obtain a suitable A.C. voltage
4 obtain a suitable D.C. voltage
Explanation:
(c) A transformer is employed to obtain a Suitable A. C. voltage.
NCERT Page-260 / N-194
AC (NCERT)
274692
A transformer has an efficiency of $80\text{ }\!\!%\!\!\text{ }$. It works at $4\text{kW}$ and $100\text{V}$. If secondary voltage is $240\text{V}$, the current in primary coil is
1 $0.4\text{A}$
2 $4\text{A}$
3 $10\text{A}$
4 $40\text{A}$
Explanation:
(d) As ${{\text{E}}_{\text{p}}}{{\text{I}}_{\text{p}}}={{\text{P}}_{\text{i}}}\therefore {{\text{I}}_{\text{p}}}=\frac{{{\text{P}}_{\text{i}}}}{{{\text{E}}_{\text{p}}}}=\frac{4000}{100}=40\text{A}$.
NCERT Page-261 / N-195
AC (NCERT)
274693
The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at $1000\text{V}$ is $12\text{kW}$, what is the primary voltage?
1 $200\text{V}$
2 $300\text{V}$
3 $400\text{V}$
4 $500\text{V}$
Explanation:
(a) ${{N}_{P}}=400,{{N}_{s}}=2000$ and ${{V}_{s}}=1000\text{V}$.
$\frac{{{V}_{P}}}{{{V}_{S}}}=\frac{{{N}_{P}}}{{{N}_{S}}}$ of, ${{V}_{P}}=\frac{{{V}_{S}}\times {{N}_{P}}}{{{N}_{S}}}=\frac{1000\times 400}{2000}=200\text{V}$.
NCERT Page-261 / N-195
AC (NCERT)
274689
A transformer is used to light a $140\text{W},24\text{V}$ bulb from a $240\text{V}$ a.c. mains. The current in the main cable is $0.7\text{A}$. The efficiency of the transformer is
1 $63.8\text{ }\!\!%\!\!\text{ }$
2 $83.3\text{ }\!\!%\!\!\text{ }$
3 $16.7\text{ }\!\!%\!\!\text{ }$
4 $36.2\text{ }\!\!%\!\!\text{ }$
Explanation:
(b) Power of source $=\text{EI}=240\times 0.7=166$
$\Rightarrow $ Efficiency $=\frac{140}{166}\Rightarrow \eta =83.3\text{ }\!\!%\!\!\text{ }$
NCERT Page-261 / N-195
AC (NCERT)
274690
Eddy currents in the core of transformer can't be developed by
1 increasing the number of turns in secondary coil
(c) A transformer is employed to obtain a Suitable A. C. voltage.
NCERT Page-260 / N-194
AC (NCERT)
274692
A transformer has an efficiency of $80\text{ }\!\!%\!\!\text{ }$. It works at $4\text{kW}$ and $100\text{V}$. If secondary voltage is $240\text{V}$, the current in primary coil is
1 $0.4\text{A}$
2 $4\text{A}$
3 $10\text{A}$
4 $40\text{A}$
Explanation:
(d) As ${{\text{E}}_{\text{p}}}{{\text{I}}_{\text{p}}}={{\text{P}}_{\text{i}}}\therefore {{\text{I}}_{\text{p}}}=\frac{{{\text{P}}_{\text{i}}}}{{{\text{E}}_{\text{p}}}}=\frac{4000}{100}=40\text{A}$.
NCERT Page-261 / N-195
AC (NCERT)
274693
The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at $1000\text{V}$ is $12\text{kW}$, what is the primary voltage?
1 $200\text{V}$
2 $300\text{V}$
3 $400\text{V}$
4 $500\text{V}$
Explanation:
(a) ${{N}_{P}}=400,{{N}_{s}}=2000$ and ${{V}_{s}}=1000\text{V}$.
$\frac{{{V}_{P}}}{{{V}_{S}}}=\frac{{{N}_{P}}}{{{N}_{S}}}$ of, ${{V}_{P}}=\frac{{{V}_{S}}\times {{N}_{P}}}{{{N}_{S}}}=\frac{1000\times 400}{2000}=200\text{V}$.
NCERT Page-261 / N-195
AC (NCERT)
274689
A transformer is used to light a $140\text{W},24\text{V}$ bulb from a $240\text{V}$ a.c. mains. The current in the main cable is $0.7\text{A}$. The efficiency of the transformer is
1 $63.8\text{ }\!\!%\!\!\text{ }$
2 $83.3\text{ }\!\!%\!\!\text{ }$
3 $16.7\text{ }\!\!%\!\!\text{ }$
4 $36.2\text{ }\!\!%\!\!\text{ }$
Explanation:
(b) Power of source $=\text{EI}=240\times 0.7=166$
$\Rightarrow $ Efficiency $=\frac{140}{166}\Rightarrow \eta =83.3\text{ }\!\!%\!\!\text{ }$
NCERT Page-261 / N-195
AC (NCERT)
274690
Eddy currents in the core of transformer can't be developed by
1 increasing the number of turns in secondary coil