272223
The electric potential inside a conducting sphere
1 increases from centre to surface
2 decreases from centre to surface
3 remains constant from centre to surface
4 is zero at every point inside
Explanation:
(c) Electric potential inside a conductor is constant and it is equal to that on the surface of the conductor.
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272224
It becomes possible to define potential at a point in an electric field because electric field
1 is a conservative field
2 is a non-conservative field
3 is a vector field
4 : obeys principle of superposition
Explanation:
(a) Potential energy is defined only in case of conservative forces like electrostatic force \{and due to which electrostatic field is a conservative field). It is not defined for non-conservative forces like friction
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272225
Which of the following about potential at a point due to a given point charge is true?
The potential at a point \(P\) due to a given point charge
1 is a function of distance from the point charge.
2 varies inversely as the square of distance from the point charge.
3 is a vector quantity
4 is directly proportional to the square of distance from the point charge.
Explanation:
(a) Since \(V=\frac{1}{4 \pi \varepsilon_0} \frac{q}{T}\), for a given point charge, \(q\) is constant, therefore \(V\) depends only on \(r\). Hence \(V\) is a function of distance.
NCERT Pige-53/N-47
Electrostatic Potentials and Capacitance
272227
The figure shows the electric dipole placed along \(x\)-axis. As we move from point \(A\) to point \(B\) potential changes from
1 positive to negative
2 negative to positive
3 positive to zero
4 does not change
Explanation:
(b)
NCERT Page - 53 /N-47
Electrostatic Potentials and Capacitance
272228
\(A\) and \(B\) are two points in an electric field. If the work done in carrying 4.0 C of electric charge from \(A\) to \(B\) is 16.0 J , the potential difference between \(A\) and \(B\) is
1 zero
2 2.0 V
3 4.0 V
4 16.0 V
Explanation:
(c) Since \(W_{A \rightarrow B}=q\left(V_B-V_A\right) \Rightarrow V_B-V_A=\frac{16}{4}=4 V\)
272223
The electric potential inside a conducting sphere
1 increases from centre to surface
2 decreases from centre to surface
3 remains constant from centre to surface
4 is zero at every point inside
Explanation:
(c) Electric potential inside a conductor is constant and it is equal to that on the surface of the conductor.
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272224
It becomes possible to define potential at a point in an electric field because electric field
1 is a conservative field
2 is a non-conservative field
3 is a vector field
4 : obeys principle of superposition
Explanation:
(a) Potential energy is defined only in case of conservative forces like electrostatic force \{and due to which electrostatic field is a conservative field). It is not defined for non-conservative forces like friction
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272225
Which of the following about potential at a point due to a given point charge is true?
The potential at a point \(P\) due to a given point charge
1 is a function of distance from the point charge.
2 varies inversely as the square of distance from the point charge.
3 is a vector quantity
4 is directly proportional to the square of distance from the point charge.
Explanation:
(a) Since \(V=\frac{1}{4 \pi \varepsilon_0} \frac{q}{T}\), for a given point charge, \(q\) is constant, therefore \(V\) depends only on \(r\). Hence \(V\) is a function of distance.
NCERT Pige-53/N-47
Electrostatic Potentials and Capacitance
272227
The figure shows the electric dipole placed along \(x\)-axis. As we move from point \(A\) to point \(B\) potential changes from
1 positive to negative
2 negative to positive
3 positive to zero
4 does not change
Explanation:
(b)
NCERT Page - 53 /N-47
Electrostatic Potentials and Capacitance
272228
\(A\) and \(B\) are two points in an electric field. If the work done in carrying 4.0 C of electric charge from \(A\) to \(B\) is 16.0 J , the potential difference between \(A\) and \(B\) is
1 zero
2 2.0 V
3 4.0 V
4 16.0 V
Explanation:
(c) Since \(W_{A \rightarrow B}=q\left(V_B-V_A\right) \Rightarrow V_B-V_A=\frac{16}{4}=4 V\)
272223
The electric potential inside a conducting sphere
1 increases from centre to surface
2 decreases from centre to surface
3 remains constant from centre to surface
4 is zero at every point inside
Explanation:
(c) Electric potential inside a conductor is constant and it is equal to that on the surface of the conductor.
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272224
It becomes possible to define potential at a point in an electric field because electric field
1 is a conservative field
2 is a non-conservative field
3 is a vector field
4 : obeys principle of superposition
Explanation:
(a) Potential energy is defined only in case of conservative forces like electrostatic force \{and due to which electrostatic field is a conservative field). It is not defined for non-conservative forces like friction
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272225
Which of the following about potential at a point due to a given point charge is true?
The potential at a point \(P\) due to a given point charge
1 is a function of distance from the point charge.
2 varies inversely as the square of distance from the point charge.
3 is a vector quantity
4 is directly proportional to the square of distance from the point charge.
Explanation:
(a) Since \(V=\frac{1}{4 \pi \varepsilon_0} \frac{q}{T}\), for a given point charge, \(q\) is constant, therefore \(V\) depends only on \(r\). Hence \(V\) is a function of distance.
NCERT Pige-53/N-47
Electrostatic Potentials and Capacitance
272227
The figure shows the electric dipole placed along \(x\)-axis. As we move from point \(A\) to point \(B\) potential changes from
1 positive to negative
2 negative to positive
3 positive to zero
4 does not change
Explanation:
(b)
NCERT Page - 53 /N-47
Electrostatic Potentials and Capacitance
272228
\(A\) and \(B\) are two points in an electric field. If the work done in carrying 4.0 C of electric charge from \(A\) to \(B\) is 16.0 J , the potential difference between \(A\) and \(B\) is
1 zero
2 2.0 V
3 4.0 V
4 16.0 V
Explanation:
(c) Since \(W_{A \rightarrow B}=q\left(V_B-V_A\right) \Rightarrow V_B-V_A=\frac{16}{4}=4 V\)
272223
The electric potential inside a conducting sphere
1 increases from centre to surface
2 decreases from centre to surface
3 remains constant from centre to surface
4 is zero at every point inside
Explanation:
(c) Electric potential inside a conductor is constant and it is equal to that on the surface of the conductor.
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272224
It becomes possible to define potential at a point in an electric field because electric field
1 is a conservative field
2 is a non-conservative field
3 is a vector field
4 : obeys principle of superposition
Explanation:
(a) Potential energy is defined only in case of conservative forces like electrostatic force \{and due to which electrostatic field is a conservative field). It is not defined for non-conservative forces like friction
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272225
Which of the following about potential at a point due to a given point charge is true?
The potential at a point \(P\) due to a given point charge
1 is a function of distance from the point charge.
2 varies inversely as the square of distance from the point charge.
3 is a vector quantity
4 is directly proportional to the square of distance from the point charge.
Explanation:
(a) Since \(V=\frac{1}{4 \pi \varepsilon_0} \frac{q}{T}\), for a given point charge, \(q\) is constant, therefore \(V\) depends only on \(r\). Hence \(V\) is a function of distance.
NCERT Pige-53/N-47
Electrostatic Potentials and Capacitance
272227
The figure shows the electric dipole placed along \(x\)-axis. As we move from point \(A\) to point \(B\) potential changes from
1 positive to negative
2 negative to positive
3 positive to zero
4 does not change
Explanation:
(b)
NCERT Page - 53 /N-47
Electrostatic Potentials and Capacitance
272228
\(A\) and \(B\) are two points in an electric field. If the work done in carrying 4.0 C of electric charge from \(A\) to \(B\) is 16.0 J , the potential difference between \(A\) and \(B\) is
1 zero
2 2.0 V
3 4.0 V
4 16.0 V
Explanation:
(c) Since \(W_{A \rightarrow B}=q\left(V_B-V_A\right) \Rightarrow V_B-V_A=\frac{16}{4}=4 V\)
272223
The electric potential inside a conducting sphere
1 increases from centre to surface
2 decreases from centre to surface
3 remains constant from centre to surface
4 is zero at every point inside
Explanation:
(c) Electric potential inside a conductor is constant and it is equal to that on the surface of the conductor.
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272224
It becomes possible to define potential at a point in an electric field because electric field
1 is a conservative field
2 is a non-conservative field
3 is a vector field
4 : obeys principle of superposition
Explanation:
(a) Potential energy is defined only in case of conservative forces like electrostatic force \{and due to which electrostatic field is a conservative field). It is not defined for non-conservative forces like friction
NCERT Page-53/N-47
Electrostatic Potentials and Capacitance
272225
Which of the following about potential at a point due to a given point charge is true?
The potential at a point \(P\) due to a given point charge
1 is a function of distance from the point charge.
2 varies inversely as the square of distance from the point charge.
3 is a vector quantity
4 is directly proportional to the square of distance from the point charge.
Explanation:
(a) Since \(V=\frac{1}{4 \pi \varepsilon_0} \frac{q}{T}\), for a given point charge, \(q\) is constant, therefore \(V\) depends only on \(r\). Hence \(V\) is a function of distance.
NCERT Pige-53/N-47
Electrostatic Potentials and Capacitance
272227
The figure shows the electric dipole placed along \(x\)-axis. As we move from point \(A\) to point \(B\) potential changes from
1 positive to negative
2 negative to positive
3 positive to zero
4 does not change
Explanation:
(b)
NCERT Page - 53 /N-47
Electrostatic Potentials and Capacitance
272228
\(A\) and \(B\) are two points in an electric field. If the work done in carrying 4.0 C of electric charge from \(A\) to \(B\) is 16.0 J , the potential difference between \(A\) and \(B\) is
1 zero
2 2.0 V
3 4.0 V
4 16.0 V
Explanation:
(c) Since \(W_{A \rightarrow B}=q\left(V_B-V_A\right) \Rightarrow V_B-V_A=\frac{16}{4}=4 V\)
