270604
Acceleration due to gravity on moon is \(1 / 6\) of the acceleration due to gravity on earth. If the ratio of densities of earth and moon is \(5 / 3\), then radius of moon in terms of radius of earth will be
1 \(\frac{5}{18} R_{e}\)
2 \(\frac{1}{6} R_{e}\)
3 \(\frac{3}{18} R_{e}\)
4 \(\frac{1}{2 \sqrt{3}} R_{e}\)
Explanation:
\(g=\frac{4}{3} \pi G R \rho \Rightarrow g \propto R \rho\)
Gravitation
270634
If the radius of the earth is made three times, keeping the mass constant, then the weight of a body on the earth's surface will be as compared to its previous value is
1 one third
2 one ninth
3 three times
4 nine times
Explanation:
\(W=m g=\frac{G M m}{r^{2}}\)
Gravitation
270636
The angular velocity of earth's rotation about its axis is ' \(\omega\) '. An object weighed by a spring balance gives the same reading at the equator as at height ' \(h\) ' above the poles . The value of ' \(h\) ' will be
270637
The radius and acceleration due to gravity of moon are \(\frac{1}{4}\) and \(\frac{1}{5}\) that of earth, the ratio of the mass of earth to mass of moon is
1 \(1: 80\)
2 \(80: 1\)
3 \(1: 20\)
4 \(20: 1\)
Explanation:
\(g=\frac{G M}{R^{2}} \Rightarrow g \alpha \frac{M}{R^{2}}\)
Gravitation
270638
The difference in the value of ' \(g\) ' at poles and at a latitude is \(\frac{3}{4} R \omega^{2}\) then latitude angle is
1 \(60^{\circ}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(95^{\circ}\)
Explanation:
\(R \omega^{2} \cos ^{2} \lambda=\frac{3}{4} R \omega^{2}\)
270604
Acceleration due to gravity on moon is \(1 / 6\) of the acceleration due to gravity on earth. If the ratio of densities of earth and moon is \(5 / 3\), then radius of moon in terms of radius of earth will be
1 \(\frac{5}{18} R_{e}\)
2 \(\frac{1}{6} R_{e}\)
3 \(\frac{3}{18} R_{e}\)
4 \(\frac{1}{2 \sqrt{3}} R_{e}\)
Explanation:
\(g=\frac{4}{3} \pi G R \rho \Rightarrow g \propto R \rho\)
Gravitation
270634
If the radius of the earth is made three times, keeping the mass constant, then the weight of a body on the earth's surface will be as compared to its previous value is
1 one third
2 one ninth
3 three times
4 nine times
Explanation:
\(W=m g=\frac{G M m}{r^{2}}\)
Gravitation
270636
The angular velocity of earth's rotation about its axis is ' \(\omega\) '. An object weighed by a spring balance gives the same reading at the equator as at height ' \(h\) ' above the poles . The value of ' \(h\) ' will be
270637
The radius and acceleration due to gravity of moon are \(\frac{1}{4}\) and \(\frac{1}{5}\) that of earth, the ratio of the mass of earth to mass of moon is
1 \(1: 80\)
2 \(80: 1\)
3 \(1: 20\)
4 \(20: 1\)
Explanation:
\(g=\frac{G M}{R^{2}} \Rightarrow g \alpha \frac{M}{R^{2}}\)
Gravitation
270638
The difference in the value of ' \(g\) ' at poles and at a latitude is \(\frac{3}{4} R \omega^{2}\) then latitude angle is
1 \(60^{\circ}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(95^{\circ}\)
Explanation:
\(R \omega^{2} \cos ^{2} \lambda=\frac{3}{4} R \omega^{2}\)
270604
Acceleration due to gravity on moon is \(1 / 6\) of the acceleration due to gravity on earth. If the ratio of densities of earth and moon is \(5 / 3\), then radius of moon in terms of radius of earth will be
1 \(\frac{5}{18} R_{e}\)
2 \(\frac{1}{6} R_{e}\)
3 \(\frac{3}{18} R_{e}\)
4 \(\frac{1}{2 \sqrt{3}} R_{e}\)
Explanation:
\(g=\frac{4}{3} \pi G R \rho \Rightarrow g \propto R \rho\)
Gravitation
270634
If the radius of the earth is made three times, keeping the mass constant, then the weight of a body on the earth's surface will be as compared to its previous value is
1 one third
2 one ninth
3 three times
4 nine times
Explanation:
\(W=m g=\frac{G M m}{r^{2}}\)
Gravitation
270636
The angular velocity of earth's rotation about its axis is ' \(\omega\) '. An object weighed by a spring balance gives the same reading at the equator as at height ' \(h\) ' above the poles . The value of ' \(h\) ' will be
270637
The radius and acceleration due to gravity of moon are \(\frac{1}{4}\) and \(\frac{1}{5}\) that of earth, the ratio of the mass of earth to mass of moon is
1 \(1: 80\)
2 \(80: 1\)
3 \(1: 20\)
4 \(20: 1\)
Explanation:
\(g=\frac{G M}{R^{2}} \Rightarrow g \alpha \frac{M}{R^{2}}\)
Gravitation
270638
The difference in the value of ' \(g\) ' at poles and at a latitude is \(\frac{3}{4} R \omega^{2}\) then latitude angle is
1 \(60^{\circ}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(95^{\circ}\)
Explanation:
\(R \omega^{2} \cos ^{2} \lambda=\frac{3}{4} R \omega^{2}\)
270604
Acceleration due to gravity on moon is \(1 / 6\) of the acceleration due to gravity on earth. If the ratio of densities of earth and moon is \(5 / 3\), then radius of moon in terms of radius of earth will be
1 \(\frac{5}{18} R_{e}\)
2 \(\frac{1}{6} R_{e}\)
3 \(\frac{3}{18} R_{e}\)
4 \(\frac{1}{2 \sqrt{3}} R_{e}\)
Explanation:
\(g=\frac{4}{3} \pi G R \rho \Rightarrow g \propto R \rho\)
Gravitation
270634
If the radius of the earth is made three times, keeping the mass constant, then the weight of a body on the earth's surface will be as compared to its previous value is
1 one third
2 one ninth
3 three times
4 nine times
Explanation:
\(W=m g=\frac{G M m}{r^{2}}\)
Gravitation
270636
The angular velocity of earth's rotation about its axis is ' \(\omega\) '. An object weighed by a spring balance gives the same reading at the equator as at height ' \(h\) ' above the poles . The value of ' \(h\) ' will be
270637
The radius and acceleration due to gravity of moon are \(\frac{1}{4}\) and \(\frac{1}{5}\) that of earth, the ratio of the mass of earth to mass of moon is
1 \(1: 80\)
2 \(80: 1\)
3 \(1: 20\)
4 \(20: 1\)
Explanation:
\(g=\frac{G M}{R^{2}} \Rightarrow g \alpha \frac{M}{R^{2}}\)
Gravitation
270638
The difference in the value of ' \(g\) ' at poles and at a latitude is \(\frac{3}{4} R \omega^{2}\) then latitude angle is
1 \(60^{\circ}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(95^{\circ}\)
Explanation:
\(R \omega^{2} \cos ^{2} \lambda=\frac{3}{4} R \omega^{2}\)
270604
Acceleration due to gravity on moon is \(1 / 6\) of the acceleration due to gravity on earth. If the ratio of densities of earth and moon is \(5 / 3\), then radius of moon in terms of radius of earth will be
1 \(\frac{5}{18} R_{e}\)
2 \(\frac{1}{6} R_{e}\)
3 \(\frac{3}{18} R_{e}\)
4 \(\frac{1}{2 \sqrt{3}} R_{e}\)
Explanation:
\(g=\frac{4}{3} \pi G R \rho \Rightarrow g \propto R \rho\)
Gravitation
270634
If the radius of the earth is made three times, keeping the mass constant, then the weight of a body on the earth's surface will be as compared to its previous value is
1 one third
2 one ninth
3 three times
4 nine times
Explanation:
\(W=m g=\frac{G M m}{r^{2}}\)
Gravitation
270636
The angular velocity of earth's rotation about its axis is ' \(\omega\) '. An object weighed by a spring balance gives the same reading at the equator as at height ' \(h\) ' above the poles . The value of ' \(h\) ' will be
270637
The radius and acceleration due to gravity of moon are \(\frac{1}{4}\) and \(\frac{1}{5}\) that of earth, the ratio of the mass of earth to mass of moon is
1 \(1: 80\)
2 \(80: 1\)
3 \(1: 20\)
4 \(20: 1\)
Explanation:
\(g=\frac{G M}{R^{2}} \Rightarrow g \alpha \frac{M}{R^{2}}\)
Gravitation
270638
The difference in the value of ' \(g\) ' at poles and at a latitude is \(\frac{3}{4} R \omega^{2}\) then latitude angle is
1 \(60^{\circ}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(95^{\circ}\)
Explanation:
\(R \omega^{2} \cos ^{2} \lambda=\frac{3}{4} R \omega^{2}\)
