2 the escape velocity being greater than the mean speed of the molecules of the atmospheric gases.
3 the escape velocity being smaller than the mean speed of the molecules of the atmospheric gases.
4 the sun's gravitational effect.
Explanation:
Gravitation
270432
Ratio of the radius of a planet \(A\) to that of planet \(B\) is ' \(r\) '. The ratio of accelerations due to gravity for the two planets is \(x\). The ratio of the escape velocities from the two planets is
1 \(\sqrt{r x}\)
2 \(\sqrt{r / x}\)
3 \(\sqrt{r}\)
4 \(\sqrt{x / r}\)
Explanation:
Gravitation
270433
The ratio of the escape velocity and the orbital velocity is
1 \(\sqrt{2}\)
2 \(\frac{1}{\sqrt{2}}\)
3 2
4 \(1 / 2\)
Explanation:
Gravitation
270434
The escape velocity from the earth for a rocket is \(11.2 \mathrm{~km} / \mathrm{sec}\). Ignoring the air resistance, the escape velocity of \(10 \mathrm{mg}\) grain of sand from the earth will be (in \(\mathrm{km} / \mathrm{sec}\) )
1 0.112
2 11.2
3 1.12
4 None
Explanation:
Gravitation
270435
The escape velocity for a body projected vertically upwards from the surface of earth is \(11 \mathrm{~km} / \mathrm{s}\). If the body is projected at an angle of \(45^{\circ}\) with the vertical, the escape velocity will be
2 the escape velocity being greater than the mean speed of the molecules of the atmospheric gases.
3 the escape velocity being smaller than the mean speed of the molecules of the atmospheric gases.
4 the sun's gravitational effect.
Explanation:
Gravitation
270432
Ratio of the radius of a planet \(A\) to that of planet \(B\) is ' \(r\) '. The ratio of accelerations due to gravity for the two planets is \(x\). The ratio of the escape velocities from the two planets is
1 \(\sqrt{r x}\)
2 \(\sqrt{r / x}\)
3 \(\sqrt{r}\)
4 \(\sqrt{x / r}\)
Explanation:
Gravitation
270433
The ratio of the escape velocity and the orbital velocity is
1 \(\sqrt{2}\)
2 \(\frac{1}{\sqrt{2}}\)
3 2
4 \(1 / 2\)
Explanation:
Gravitation
270434
The escape velocity from the earth for a rocket is \(11.2 \mathrm{~km} / \mathrm{sec}\). Ignoring the air resistance, the escape velocity of \(10 \mathrm{mg}\) grain of sand from the earth will be (in \(\mathrm{km} / \mathrm{sec}\) )
1 0.112
2 11.2
3 1.12
4 None
Explanation:
Gravitation
270435
The escape velocity for a body projected vertically upwards from the surface of earth is \(11 \mathrm{~km} / \mathrm{s}\). If the body is projected at an angle of \(45^{\circ}\) with the vertical, the escape velocity will be
2 the escape velocity being greater than the mean speed of the molecules of the atmospheric gases.
3 the escape velocity being smaller than the mean speed of the molecules of the atmospheric gases.
4 the sun's gravitational effect.
Explanation:
Gravitation
270432
Ratio of the radius of a planet \(A\) to that of planet \(B\) is ' \(r\) '. The ratio of accelerations due to gravity for the two planets is \(x\). The ratio of the escape velocities from the two planets is
1 \(\sqrt{r x}\)
2 \(\sqrt{r / x}\)
3 \(\sqrt{r}\)
4 \(\sqrt{x / r}\)
Explanation:
Gravitation
270433
The ratio of the escape velocity and the orbital velocity is
1 \(\sqrt{2}\)
2 \(\frac{1}{\sqrt{2}}\)
3 2
4 \(1 / 2\)
Explanation:
Gravitation
270434
The escape velocity from the earth for a rocket is \(11.2 \mathrm{~km} / \mathrm{sec}\). Ignoring the air resistance, the escape velocity of \(10 \mathrm{mg}\) grain of sand from the earth will be (in \(\mathrm{km} / \mathrm{sec}\) )
1 0.112
2 11.2
3 1.12
4 None
Explanation:
Gravitation
270435
The escape velocity for a body projected vertically upwards from the surface of earth is \(11 \mathrm{~km} / \mathrm{s}\). If the body is projected at an angle of \(45^{\circ}\) with the vertical, the escape velocity will be
2 the escape velocity being greater than the mean speed of the molecules of the atmospheric gases.
3 the escape velocity being smaller than the mean speed of the molecules of the atmospheric gases.
4 the sun's gravitational effect.
Explanation:
Gravitation
270432
Ratio of the radius of a planet \(A\) to that of planet \(B\) is ' \(r\) '. The ratio of accelerations due to gravity for the two planets is \(x\). The ratio of the escape velocities from the two planets is
1 \(\sqrt{r x}\)
2 \(\sqrt{r / x}\)
3 \(\sqrt{r}\)
4 \(\sqrt{x / r}\)
Explanation:
Gravitation
270433
The ratio of the escape velocity and the orbital velocity is
1 \(\sqrt{2}\)
2 \(\frac{1}{\sqrt{2}}\)
3 2
4 \(1 / 2\)
Explanation:
Gravitation
270434
The escape velocity from the earth for a rocket is \(11.2 \mathrm{~km} / \mathrm{sec}\). Ignoring the air resistance, the escape velocity of \(10 \mathrm{mg}\) grain of sand from the earth will be (in \(\mathrm{km} / \mathrm{sec}\) )
1 0.112
2 11.2
3 1.12
4 None
Explanation:
Gravitation
270435
The escape velocity for a body projected vertically upwards from the surface of earth is \(11 \mathrm{~km} / \mathrm{s}\). If the body is projected at an angle of \(45^{\circ}\) with the vertical, the escape velocity will be
2 the escape velocity being greater than the mean speed of the molecules of the atmospheric gases.
3 the escape velocity being smaller than the mean speed of the molecules of the atmospheric gases.
4 the sun's gravitational effect.
Explanation:
Gravitation
270432
Ratio of the radius of a planet \(A\) to that of planet \(B\) is ' \(r\) '. The ratio of accelerations due to gravity for the two planets is \(x\). The ratio of the escape velocities from the two planets is
1 \(\sqrt{r x}\)
2 \(\sqrt{r / x}\)
3 \(\sqrt{r}\)
4 \(\sqrt{x / r}\)
Explanation:
Gravitation
270433
The ratio of the escape velocity and the orbital velocity is
1 \(\sqrt{2}\)
2 \(\frac{1}{\sqrt{2}}\)
3 2
4 \(1 / 2\)
Explanation:
Gravitation
270434
The escape velocity from the earth for a rocket is \(11.2 \mathrm{~km} / \mathrm{sec}\). Ignoring the air resistance, the escape velocity of \(10 \mathrm{mg}\) grain of sand from the earth will be (in \(\mathrm{km} / \mathrm{sec}\) )
1 0.112
2 11.2
3 1.12
4 None
Explanation:
Gravitation
270435
The escape velocity for a body projected vertically upwards from the surface of earth is \(11 \mathrm{~km} / \mathrm{s}\). If the body is projected at an angle of \(45^{\circ}\) with the vertical, the escape velocity will be