EQUILIBRIUM OF A PARTICLE
Laws of Motion

270270 The coefficient of friction between a hemispherical bowl and an insect is\(\sqrt{0.44}\) and the radius of the bowl is \(0.6 \mathrm{~m}\). The maximum height to which an insect can crawl in the bowl will be

1 \(0.4 \mathrm{~m}\)
2 \(0.2 \mathrm{~m}\)
3 \(0.3 \mathrm{~m}\)
4 \(0.1 \mathrm{~m}\)
Laws of Motion

270271 A\(500 \mathrm{~kg}\) horse pulls a cart of mass \(1500 \mathrm{~kg}\) along a level road with an acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). If coefficient of sliding friction is 0.2 , then force exerted by the earth on horse is

1 \(3000 \mathrm{~N}\)
2 \(4000 \mathrm{~N}\)
3 \(5000 \mathrm{~N}\)
4 \(6000 \mathrm{~N}\)
Laws of Motion

270272 Anaeroplane requires for take off a speed of \(108 \mathrm{kmph}\) the run on the ground being \(100 \mathrm{~m}\). Mass of the plane is \(10^{4} \mathrm{~kg}\) and the coefficient of friction between the plane and the ground is 0.2. Assuming the plane accelerates uniformly the minimum force required is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(2 \times 10^{4} \mathrm{~N}\)
2 \(2.43 \times 10^{4} \mathrm{~N}\)
3 \(6.5 \times 10^{4} \mathrm{~N}\)
4 \(8.86 \times 10^{4} \mathrm{~N}\)
Laws of Motion

270273 A duster weighs\(0.5 \mathrm{~N}\). It is pressed against a vertical board with a horizontal force of \(11 \mathrm{~N}\). If the co-efficient of friction is 0.5 the minimum force that must be applied on the duster parallel to the board to move it upwards is

1 \(0.4 \mathrm{~N}\)
2 \(0.7 \mathrm{~N}\)
3 \(6 \mathrm{~N}\)
4 \(7 \mathrm{~N}\)
Laws of Motion

270270 The coefficient of friction between a hemispherical bowl and an insect is\(\sqrt{0.44}\) and the radius of the bowl is \(0.6 \mathrm{~m}\). The maximum height to which an insect can crawl in the bowl will be

1 \(0.4 \mathrm{~m}\)
2 \(0.2 \mathrm{~m}\)
3 \(0.3 \mathrm{~m}\)
4 \(0.1 \mathrm{~m}\)
Laws of Motion

270271 A\(500 \mathrm{~kg}\) horse pulls a cart of mass \(1500 \mathrm{~kg}\) along a level road with an acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). If coefficient of sliding friction is 0.2 , then force exerted by the earth on horse is

1 \(3000 \mathrm{~N}\)
2 \(4000 \mathrm{~N}\)
3 \(5000 \mathrm{~N}\)
4 \(6000 \mathrm{~N}\)
Laws of Motion

270272 Anaeroplane requires for take off a speed of \(108 \mathrm{kmph}\) the run on the ground being \(100 \mathrm{~m}\). Mass of the plane is \(10^{4} \mathrm{~kg}\) and the coefficient of friction between the plane and the ground is 0.2. Assuming the plane accelerates uniformly the minimum force required is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(2 \times 10^{4} \mathrm{~N}\)
2 \(2.43 \times 10^{4} \mathrm{~N}\)
3 \(6.5 \times 10^{4} \mathrm{~N}\)
4 \(8.86 \times 10^{4} \mathrm{~N}\)
Laws of Motion

270273 A duster weighs\(0.5 \mathrm{~N}\). It is pressed against a vertical board with a horizontal force of \(11 \mathrm{~N}\). If the co-efficient of friction is 0.5 the minimum force that must be applied on the duster parallel to the board to move it upwards is

1 \(0.4 \mathrm{~N}\)
2 \(0.7 \mathrm{~N}\)
3 \(6 \mathrm{~N}\)
4 \(7 \mathrm{~N}\)
Laws of Motion

270270 The coefficient of friction between a hemispherical bowl and an insect is\(\sqrt{0.44}\) and the radius of the bowl is \(0.6 \mathrm{~m}\). The maximum height to which an insect can crawl in the bowl will be

1 \(0.4 \mathrm{~m}\)
2 \(0.2 \mathrm{~m}\)
3 \(0.3 \mathrm{~m}\)
4 \(0.1 \mathrm{~m}\)
Laws of Motion

270271 A\(500 \mathrm{~kg}\) horse pulls a cart of mass \(1500 \mathrm{~kg}\) along a level road with an acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). If coefficient of sliding friction is 0.2 , then force exerted by the earth on horse is

1 \(3000 \mathrm{~N}\)
2 \(4000 \mathrm{~N}\)
3 \(5000 \mathrm{~N}\)
4 \(6000 \mathrm{~N}\)
Laws of Motion

270272 Anaeroplane requires for take off a speed of \(108 \mathrm{kmph}\) the run on the ground being \(100 \mathrm{~m}\). Mass of the plane is \(10^{4} \mathrm{~kg}\) and the coefficient of friction between the plane and the ground is 0.2. Assuming the plane accelerates uniformly the minimum force required is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(2 \times 10^{4} \mathrm{~N}\)
2 \(2.43 \times 10^{4} \mathrm{~N}\)
3 \(6.5 \times 10^{4} \mathrm{~N}\)
4 \(8.86 \times 10^{4} \mathrm{~N}\)
Laws of Motion

270273 A duster weighs\(0.5 \mathrm{~N}\). It is pressed against a vertical board with a horizontal force of \(11 \mathrm{~N}\). If the co-efficient of friction is 0.5 the minimum force that must be applied on the duster parallel to the board to move it upwards is

1 \(0.4 \mathrm{~N}\)
2 \(0.7 \mathrm{~N}\)
3 \(6 \mathrm{~N}\)
4 \(7 \mathrm{~N}\)
Laws of Motion

270270 The coefficient of friction between a hemispherical bowl and an insect is\(\sqrt{0.44}\) and the radius of the bowl is \(0.6 \mathrm{~m}\). The maximum height to which an insect can crawl in the bowl will be

1 \(0.4 \mathrm{~m}\)
2 \(0.2 \mathrm{~m}\)
3 \(0.3 \mathrm{~m}\)
4 \(0.1 \mathrm{~m}\)
Laws of Motion

270271 A\(500 \mathrm{~kg}\) horse pulls a cart of mass \(1500 \mathrm{~kg}\) along a level road with an acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). If coefficient of sliding friction is 0.2 , then force exerted by the earth on horse is

1 \(3000 \mathrm{~N}\)
2 \(4000 \mathrm{~N}\)
3 \(5000 \mathrm{~N}\)
4 \(6000 \mathrm{~N}\)
Laws of Motion

270272 Anaeroplane requires for take off a speed of \(108 \mathrm{kmph}\) the run on the ground being \(100 \mathrm{~m}\). Mass of the plane is \(10^{4} \mathrm{~kg}\) and the coefficient of friction between the plane and the ground is 0.2. Assuming the plane accelerates uniformly the minimum force required is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(2 \times 10^{4} \mathrm{~N}\)
2 \(2.43 \times 10^{4} \mathrm{~N}\)
3 \(6.5 \times 10^{4} \mathrm{~N}\)
4 \(8.86 \times 10^{4} \mathrm{~N}\)
Laws of Motion

270273 A duster weighs\(0.5 \mathrm{~N}\). It is pressed against a vertical board with a horizontal force of \(11 \mathrm{~N}\). If the co-efficient of friction is 0.5 the minimum force that must be applied on the duster parallel to the board to move it upwards is

1 \(0.4 \mathrm{~N}\)
2 \(0.7 \mathrm{~N}\)
3 \(6 \mathrm{~N}\)
4 \(7 \mathrm{~N}\)